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Introduction

Chapter 8. Chemical Compositions of Atmospheres

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Author: Neil F.Comins, University of Maine

The goals of this module. In this module you will use Kepler's third law to identify two of the planets. Once you have identified them, you will compare and contrast the orbits of all the planets, to see how they are related.

Why you are doing it: By understanding how gases interact with the gravity of their planet, you can learn a lot about why different planets have atmospheres with different chemical compositions.

Three major factors determine whether a gas remains in an atmosphere, rather than drifting into space. These are:

  1. The mass of the gas atom or molecule, m
  2. The temperature of the air, T
  3. The escape velocity from the surface of the planet, vesc

The masses of the gas particles combine with the planet's surface temperature to determine how rapidly atoms and molecules move in the air. If the average speed of any type of gas particle is less than the planet's escape velocity divided by six, then that gas will typically stay near the surface of the planet for billions of years. Otherwise, it will be gone from around that planet today, four and a half billion years after it formed. The escape velocity, vesc , is the speed that a particle moving straight up without striking any other particles must have to escape from the gravitational clutches of the body holding it down. The factor six takes into account the fact that gas particles travel in all different directions, as well as that they experience many collisions during their time in the air.

How you will determine whether various gases can remain in the air:
You need to determine whether common atmospheric gases are moving at average speeds, vavg, that are greater than or less than vesc/6 . The gases you will examine are: hydrogen, helium, nitrogen, oxygen, carbon dioxide, and water. Note that ammonia and methane, common gases in the solar system, have about the same mass and therefore the same vesc as water. If water is retained, so are these other two gases and vice versa.

The average speed of a gas atom or molecule is determined by equating two versions of the kinetic energy equation, Ek , for the gas. First:

Ek=32kT

Where k = 1.38 · 10-23 J/K is the Boltzmann constant and T is the temperature in Kelvins.

The other equation is:

Ek=12mv2avg

Where m is the mass of the gas atom or molecule and vavg is its average velocity at that temperature. Equating these two equations and solving for vavg , we find:

vavg=3kTm

You will not need your calculator to do this, as this tutorial has a built-in average velocity calculator.

At the escape velocity, vesc , the kinetic energy of the gas moving straight upward from the surface is equal to the gravitational potential energy, Ep , it feels straight downward

Ep=GmMR

Where G = 6.67 · 10-11 Nm2/kg2 is the universal constant of gravitation, m is the mass of the gas atom or molecule, and M and R are the mass and radius of the body holding the gas down. Equating Ep = Ek , we find that:

vesc=2GMR

As noted above, if 6vavg > vesc , a gas will not remain bound to its planet or moon, and vice versa. This tutorial will calculate 6vavg when you specify T and m.

Before you determine what gases can exist in the terrestrial atmospheres and in the atmosphere of some moons, we will work through one world with you. Use Earth as the example, with the mass and the radius given below. Please enter these values into the vesc calculator. It will give you the escape velocity. Earth's radius is 6378 km and its mass is 59.7×1023kg.

We will consider two gases: water and hydrogen. First, determine the average velocity of water by looking up the mass of a water molecule in the Gas Table and putting that number, along with the surface temperature of Earth (300°K), into the vavg calculator, or selecting "Earth" and "water" from the presets.

Atmosphere Animation

Question Sequence

Question 1.

Comparing 6vavg and vesc, click on whether or not water will stay in Earth's atmosphere.

A.
B.

Correct.
Incorrect.

Here is the data for a variety of terrestrial worlds in the solar system, along with the masses of some molecules:

Data about several stars:

Planet Mass × 1023 kg Radius × 103 kg Surface Temperature ° K
Mercury 3.30 2440 650
Venus* 48.7 6052 750
Earth 59.7 6378 300
Our Moon 0.735 1738 400
Mars 6.42 3397 275
Titan (moon of Saturn) 1.40 2575 100
Table : *This temperature includes adjustment for the greenhouse effect that occurs there.
#Typical high temperatures are given for worlds with significantly varying temperatures.

Data about some chemical compositions:

Gas Table
Gas Mass Per Molecule (× 10-23kg)
Hydrogen 0.335
Helium 0.665
Nitrogen 4.65
Oxygen 5.32
Carbon Dioxide 7.31
Water 2.99

Use the techniques you just learned to determine whether these gases exist in the atmospheres of the other terrestrial worlds. Guideline for this analysis: If the lightest gas, hydrogen, is held down by a planet or moon, then all available gases are held down by that planet. You can see why this is so by noting from the equations above that (a) the escape velocity is independent of the mass of the gas being held down and, (b) the lighter an element, the higher its vavg. Since all other gases are moving more slowly, if hydrogen is held down then all other gases are, too.

First determine whether a terrestrial planet or moon retains hydrogen in its atmosphere. If so, it retains all other available gases. For each terrestrial world that doesn't retain hydrogen, try helium, the second lightest gas. If neither of these gases is retained, proceed with the same analysis through increasingly more massive gases. When you are done with each world, press the "Finished with World" button and your results will be compared to the correct answers.

Atmosphere Animation

Question Sequence

Question 3.

The lightest gas that is held down by Mercury is:

A.
B.
C.
D.
E.
F.
G.

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Try again.
Correct.
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The kinds of calculations you have just done can be applied to the Jovian planets (Jupiter, Saturn, Uranus, and Neptune), but there is a caveat. Just because a planet can contain certain gases in its atmosphere (This is also true for the terrestrials, e.g., carbon dioxide on the earth.) doesn't mean that it will necessarily have those gases. Some gases that were in the air may have been dissolved deep inside the liquid Jovian worlds or been chemically changed on them into other compounds, while some gases may have always been lacking in the region of the solar system containing these worlds. Therefore, the results from the list above for the Jovian planets yield allowed gases, although not necessarily gases that are found on them. Perform the calculations for the Jovian worlds, listed below.

Planet Mass × 1026 kg Radius × 103 kg Surface Temperature ° K
Jupiter 19.0 71492 150
Saturn 5.63 60268 100
Uranus 0.866 25559 60
Neptune 1.03 24764 55

Question Sequence

Question 8.

The lightest gas that is held down by Jupiter is:

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B.
C.
D.
E.
F.
G.

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Correct.
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Indepth Activity: Chemical Compositions of Atmospheres

Question 12.

The ____________ a gas is the ____________ it will be for a planet to retain it.

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D.
E.

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Question 13.

If a given planet moved closer to its star, gases in its atmosphere will more easily escape it because the:

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B.
C.
D.
E.

Correct.
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Question 14.

If oxygen is held down in a planet's atmosphere then so is:

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B.
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D.
E.

Correct.
Incorrect.

Question 15.

What are the three major factors that determine whether or not a gas remains in a planet’s atmosphere?

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B.
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D.
E.

Correct.
Incorrect.

Question 16.

Which planet has no carbon dioxide?

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D.
E.

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Incorrect.

Question 17.

Which planet has no helium?

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B.
C.
D.
E.

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Question 18.

A planet initially formed with an atmosphere rich in helium, but it doesn’t have any helium today. What likely happened to the planet?

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D.
E.

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Question 19.

If you wanted to increase the average velocity of gas on a planet, what would you need to do?

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D.
E.

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Question 20.

If planet A and planet B have the same mass but planet B's radius is 4 times the radius of planet A then vesc B/vesc A equals:

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B.
C.
D.

Correct.
Incorrect.

Question 21.

If planet A and planet B have the same radius but planet B is 4 times denser than planet A then vesc B/vesc A equals:

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B.
C.
D.

Correct.
Incorrect.

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