Chapter 5. 5.1 Sanger Sequencing

Assessments for Animated Techniques
true
false

5.1 Sanger Sequencing

1.

received a second Nobel Prize in 1980 for his work in the development of the dideoxy method of DNA sequencing.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

2.

is the enzyme required for the in vitro DNA sequencing reaction.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

3.

A total of sequencing reactions are required to generate the sequence for one DNA template.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

4.

The DNA sequence that is closest to the DNA primer being used will be the fragment and will run near the of the gel.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

5.

True or False: Dideoxy nucleotide triphosphates (ddNTPs) are missing the 2’ and 3’ hydroxyl groups and cannot be further extended in a DNA sequencing reaction.

A.
B.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

6.

True or False: DNA sequencing gels are read from the top down.

A.
B.

_feedback_correct: Correct. _feedback_incorrect: Incorrect.

7.

Click on the step and the associated process to identify the correct order for the Sanger Sequencing method.

Step 1
Step 2
Step 3
Step 4
Step 5
Step 6
Step 7
The sequence reaction is initiated by the addition of DNA polymerase.
dNTPs are added to the reaction mixture.
The completed gel is transferred to filter paper, dried, and exposed to x-ray film.
The reactions are analyzed by PAGE.
The appropriate dideoxy nucleotide is added to each reaction tube.
A short radiolabelled primer is annealed to the single-stranded DNA template.
The reaction mixture is divided into four separate tubes, one for each nucleotide base (ACGT).
_feedback_correct: Correct. _feedback_incorrect: Incorrect.

8.

A patient is concerned that she may be a carrier for a hereditary disease. A DNA sample is taken from the patient and the gene of interest is sequenced. The wild-type gene is sequenced side by side for comparison.

Wild-Type Sequence:
5’ – ACTTCTTGGCAAGTAGGTTAAGATC – 3’

Patient X Sequence:
5’ – ACTTCTTGGCAAGTCGGTTAAGATC – 3’

DNA sample from Patient X, side-by-side with Wild-Type DNA sample

After analyzing the results, what would you advise this patient?

The patient’s sequence shows both a G and C at position 16, indicating that she is heterozygous for this gene locus, carrying one wild-type allele and one mutant allele. She should be advised that she is a carrier for the disease trait.

Activity results are being submitted...