Calculate the integral of f(x, y) = 7x over the region D bounded above by y = x(2 − x) and below by x = y(2 − y). Hint: Apply the quadratic formula to the lower boundary curve to solve for y as a function of x.
The first step is to understand the region D.
The upper bound, y = x(2 − x), is a that opens with x-intercepts at x = 0 and x = 2.
The lower bound, x = y(2 − y), is a that opens with y-intercepts at y = 0 and y = 2.
With this information, graph the region.
Consider the following figure.
We could treat the region D as either vertically or horizontally simple, but since the integrand, x, is without the variable y, it will be easier to consider D as vertically simple.
In order to do so, we need the bounding functions in terms of x. Hence we must solve the lower bound, x = y(2 − y), for y.
Use the quadratic equation to solve for y in terms of x.
x = y(2 − y)
y2 − 2y + x = 0
y =
A. |
B. |
C. |
D. |
The two solutions correspond to the upper and the lower branch of the parabola. The lower bound of D is only one of these branches.
Find the proper branch that bounds D from below. (Hint: This branch goes to −infinity.)
y =
A. |
B. |
State the inequalities that define region D
0 ≤ x ≤
and
1 √(1-x) ≤ y ≤ x(2 − x)
Set up the integral considering the region D as vertically simple.
,
where b =
A. |
B. |
C. |
D. |
Integrate. (Hint: For the x√(1 − x) term, integrate using u-substitution.) Round your answer to two decimal places.
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