Integrate f(x, y, z) = x over the region in the first octant (x ≥ 0, y ≥ 0, z ≥ 0) above z = y2 and below z = 8 − 2x2 − y2.
Find the boundary of D in the xy-plane. The upper and lower surfaces intersect where they have the same z-values. Find the intersection of the two surfaces in terms of x and y ≥ 0.
y2 = 8 − 2x2 − y2
x2 + y2 =
Thus the boundary of D is a in the first quadrant.
The region D can be expressed as either vertically or horizontally simple, depending on which variable we express the boundary in.
Solve the boundary, x2 + y2 = 4, for y in terms of x, thus making D simple.
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0 ≤ x ≤
Write the triple integral as an iterated integral.
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Evaluate the inner integral.
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At this point, we will choose to write the integrand as 8x − 2x3 − 2xy2 = 2x(4 − x2) − 2xy2. Integrate the middle integral.
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Evaluate f(x, y, z) = x over the defined region by integrating the last of the iterated integral. Round your answer to two decimal places.
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