Let F = <3/x, −1/y>. Calculate the work against F required to move an object from (1, 1) to (4, 5) along any path in the first quadrant.
Recall the cross-partial property of conservative vector fields.
F = <F1, F2> is conservative if and only if (∂F1 / ∂y) = (∂F2 / ∂x). Use this property to check if F = <3/x, −1/y> is conservative.
(∂F1 / ∂y) =
(∂F2 / ∂x) =
Thus F = <3/x, −1/y> conservative.
Since F = <3/x, −1/y> is conservative, it is also path independent. Thus any path from (1, 1) to (4, 5) will yield the same amount work. In order to evaluate the line integral representing the work, we need to find a potential function, V(x, y), such that F = −∇V (the minus sign is a convention from physics). Thus 3/x = F1 = − (∂V / ∂x).
Integrate (∂V / ∂x) = −3/x with respect to x.
A. |
B. |
C. |
D. |
We need to determine C(y). To do so, differentiate this expression with respect to y.
(∂V / ∂y) = + Cy(y)
Since F = −∇V, we have −1/y = F2 = − (∂V / ∂y) = −Cy(y).
Integrate Cy(y) = 1/y with respect to y.
A. |
B. |
C. |
D. |
Thus the general potential function is V(x, y) =
A. |
B. |
C. |
D. |
Recall the fundamental theorem for conservative vector fields.
If F = −∇V and c is a path from P to Q, then .
Use the fundamental theorem for conservative vector fields to determine the amount of work against F required to move an object from (1, 1) to (4, 5) along any path in the first quadrant. Let c be any such path.
= V(4, 5) - V(1, 1) =
A. |
B. |
C. |
D. |