Calculate for the given surface and function.
x2 + y2 = 9, 0 ≤ z ≤ 2; f(x, y, z) = e−z
Recall how to find surface integrals with a parametrized surface. Let G(u, v) be a parametrization of a surface S with parameter domain D. Assume that G is continuously differentiable, one-to-one, and regular (except possibly at the boundary of D). Then we can calculate the integral of a function over this surface.
Choose the correct integration for below.
A. |
B. |
C. |
In order to use this equation, we must parametrize the surface described by x2 + y2 = 9, 0 ≤ z ≤ 2.
The given surface represents a portion of a cylinder, so it will be easiest to integrate if we parametrize with coordinates.
In the coordinates (θ, z), we have the following parametrization of the surface.
Φ(θ, z) = (cos θ, sin θ, z)
The bounds on z and θ are 0 ≤ z ≤ and 0 ≤ θ ≤ π.
Compute Tθ and Tz, the tangent vectors to the surface Φ(θ, z) = (3 cos θ, 3 sin θ, z).
Tθ = (∂ / ∂θ)(3 cos θ, 3 sin θ, z)
= <sin θ, cos θ, 0>
Tz = (∂ / ∂z)(3 cos θ, 3 sin θ, z)
= <0, 0, >
Use these vectors to find n(θ, z), the normal vector to the surface. Let the table below represent the matrix A.
i | j | k |
-3 sin θ | 3 cos θ | 0 |
0 | 0 | 1 |
n(θ, z) = Tθ × Tz
= det(A)
= <cos θ, sin θ, 0>
Compute the length of the normal vector, ||n(θ, z)||.
||n(θ, z)|| = ||<3 cos θ, 3 sin θ, 0>||
= √((3 cos θ)2 + (sin θ)2)
=
Compute f(Φ(θ, z)) given f(x, y, z) = e−z and Φ(θ, z) = (3 cos θ, 3 sin θ, z).
f(Φ(θ, z)) =
A. |
B. |
C. |
D. |
Calculate for the surface described by x2 + y2 = 9, 0 ≤ z ≤ 2, and the function f(x, y, z) = e−z.
= π(1 - e-2)