Find the equation of the line with the given description.
parallel to y = $ax-4, passes through ($p,$q)
The given line is expressed in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Parallel lines have QY5Xl6yk2P8OML+XEDRA51whrFEpnnAZBe6WpdZisDA= slopes.
The given line has slope nc1ItEz0kR4=. Thus, the equation of the line passing through point ($p,$q) has slope nc1ItEz0kR4=.
We want to write the equation of a line with slope $a that passes through the point ($p, $q). We will choose to use the point-slope form for the equation of a line, y − b = m(x − a), where m is the slope and (a, b) is a known point on the line.
From the given equation, we have
y - VdD/yKVKNAI= = nc1ItEz0kR4= (x - 3jRAm4T6Mr4=)
Solve y - $q = $a (x-$p) for y in terms of x to get the slope-intercept form of the line that passes through the point ($p,$q) and is parallel to y = $a·x-4.
y = nc1ItEz0kR4= x - iSba6t70dtA=