Assume that . Find sin(θ), sec(θ), and cot(θ) if tan(θ)=.
Recall the signs of sin(θ) and cos(θ) for .
For , sin(θ) and cos(θ) are AHS/KvCvN60M0alrhEg6js74p/c5bldxDkt6KSfGLDzGp0rD. Thus we can use the definitions of the trigonometric functions associated with a right triangle to find sin(θ), sec(θ), and cot(θ).
Draw a right triangle to find sin(θ) and cos(θ) given that tan(θ)=.
Label θ as one of the acute angles inside the right triangle. Label the leg of the triangle opposite θ as b and label the leg of the triangle adjacent to θ as a. Label the hypotenuse c.
According to this triangle, we can solve for b and a using the relationship
.
Since , we have b = $b and a = nc1ItEz0kR4=.
We can find c using the Pythagorean theorem, which states that the sum of the squares of the legs of a right triangle equals the square of the hypotenuse.
a2 + b2 = c2
c = SFgqQUkJGdg=
(Rounded to two decimal places.)
Knowing that a = $a, b = $b, and c = $c, we can solve for sin(θ) and cos(θ) using their definitions with respect to a right triangle.
= 6Dfm+jOF/bgyzWF+wDvdrAfl09QnFwc2BQzoCQ==.
=/FbchM+7zRJiP0bzLMC4Y9L2TVmxGBe8cM/k6w==.
For and tan(θ)=,
sin(θ) = SSlBS8LbM0I=
and
cos(θ) = xn/8UFOXYhs=.
(Rounded to two decimal places.)
Recall the definitions of sec(θ) and cot(θ).
sec(θ) = KiMf4AhgqCQxuq59j8foAV9wxlzjNxxk
cot(θ) = jpYz/8GIrJycRjmEe59p/Kdg32bIgAu5PQbcRRUFZV6siY2w
Find and simplify sec(θ) and cot(θ) using, from Step 3, sin(θ) = $sin and cos(θ) = $cos.
For and tan(θ) = we have
sec(θ) = fxYeI31FYsY=
(Rounded to two decimal places.)
For and tan(θ) = we have
cot(θ) = tE/bvqTBTKc=
(Rounded to two decimal places.)