Solve for the unknown, t.
3·e6·t = 100
e6·t =
(Round to two decimal places.)
Next we take the natural logarithm of each side of the equation.
e6·t = 33.33
ln(e6·t) = ln(33.33)
Using the properties recalled in Step 1, ln(e6·t) = loge(e6·t) = ·t.
Substituting ln(e6·t) = 6·t, solve for t.
e6·t = 33.33
ln(e6·t) = ln(33.33)
6·t = ln(33.33)
t =
(Round to two decimal places.)