Find an equation of the tangent line at the point indicated.
s(t) = ln(7 - 5 t), t = 1
Recall that a tangent line to a graph of y = f(x) at a point P(a, f(a)) is the line through the point P of slope . The equation of the tangent line in point-slope form is y - = ยท(x - a).
We must now find the slope of the tangent line at the point of tangency, (1,ln(2)), by calculating the derivative of s(t) and evaluating the derivative at t = 1.
Recall the derivative of ln(x).
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Write the equation of the tangent line.
m = , n =