Centripetal acceleration (3-17)

Question 1 of 3

Question

$\textbf{Speed}$ of an object as it moves around the circle

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Question

$\textbf{Centripetal acceleration}$ : Magnitude of the acceleration of an object in uniform circular motion

{"title":"Centripetal acceleration Magnitude of the acceleration of an object in uniform circular motion","description":"Correct!","type":"correct","color":"#99CCFF","code":"[{\"shape\":\"rect\",\"coords\":\"1,64,28,104\"},{\"shape\":\"poly\",\"coords\":\"82,133\"}]"} {"title":"Speed of an object as it moves around the circle","description":"Wrong","type":"incorrect","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"172,27,208,69\"}]"} {"title":"Radius of the circle","description":"Incorrect","type":"incorrect","color":"#333300","code":"[{\"shape\":\"poly\",\"coords\":\"113,132\"},{\"shape\":\"rect\",\"coords\":\"173,96,204,132\"}]"}

Question

$\textbf{Radius}$ of the circle

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Review

Now, the object's speed $v$ equal to the distance $\Delta{s}$ that it travels divided by the time interval $\Delta{t}$ required to travel this distance: $v = \Delta{s}/\Delta{t}$ . Therefore we can replace $\Delta{s}/\Delta{t}$ in Equation 3-16 by $v$ , and our expression for the object's centripetal acceleration becomes $a_\mathrm{cent} = v(v/r)$ , or: