Two positions of the object
{"title":"Speed at position x sub f of an object in linear motion with constant acceleration","description":"Incorrect","type":"incorrect","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"1,26,21,47\"}]"} {"title":"Speed at position x sub i of the object","description":"Wrong","type":"incorrect","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"66,23,83,45\"}]"} {"title":"Two positions of the object","description":"Correct!","type":"correct","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"264,23,284,49\"},{\"shape\":\"rect\",\"coords\":\"198,21,219,49\"}]"} {"title":"Constant acceleration of the object","description":"Incorrect","type":"incorrect","color":"#000080","code":"[{\"shape\":\"rect\",\"coords\":\"150,23,171,49\"}]"}In Equation 6-3 v2fx is the square of the velocity at xf, but it also equals the square of the object’s speed vf at xf. That’s because vfx is equal to +vf if the object is moving in the positive x direction and equal to −vf if moving in the negative x direction. In either case,v2fx=v2f . For the same reason v2ix = v2i , where vi is the object’s speed at xi. So we can rewrite Equation 6-3 as: