Velocity as a function of time for simple harmonic motion (12-14)

Question 1 of 4

Question

$\textbf{Angular frequency}$ of the oscillation ( $\omega = 2\pi{f} = 2\pi/T$ )

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Question

$\textbf{Amplitude}$ of the oscillation = maximum displacement from the equilibrium position

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Question

$\textbf{Velocity}$ of an object in SHM at time $t$

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Question

$\textbf{Phase angle}$

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Review

So for an object in simple harmonic motion the value of the phase angle $\phi$ tells you the point in the oscillation cycle that corresponds to $t = 0$ . Note that Figures 12-6a and 12-6b really depict the same oscillation, with the same amplitude $A$ and period $T$ ; the only difference is the point in the cycle that we call $t = 0$ .

The phase angle also appears in the expressions for velocity and acceleration in simple harmonic motion (Equations 12-7 and 12-8), which we found by analogy with uniform circular motion: