Loading [MathJax]/jax/output/HTML-CSS/jax.js

Molar specific heat at constant volume for an ideal gas (15-18)

Question 1 of 3

Question

Number of degrees of freedom for a molecule of the gas

Feedback
{"title":"Molar specific heat of an ideal gas at constant volume","description":"Wrong","type":"incorrect","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"10,16,12,16\"},{\"shape\":\"rect\",\"coords\":\"3,44,44,90\"},{\"shape\":\"poly\",\"coords\":\"144,22\"}]"} {"title":"Number of degrees of freedom for a molecule of the gas","description":"Correct!","type":"correct","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"165,9,210,55\"}]"} {"title":"Ideal gas constant","description":"Wrong","type":"incorrect","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"249,40,290,93\"}]"}

Review

We'll use the symbol D to represent the number of degress of freedom. Then the average energy per gas molecule is (D/2)kT. One mole of the gas contains Avogadro's number of molecules, so the energy per mole is NA(D/2)kT=(D/2) (NAk)T=(D/2)RT. (Again, recall that k=R/NA, so R=NAk).) Then the internal energy of n moles of ideal gas is

(15-16) U=n(D2R)T (ideal gas, D degrees of freedom)

If the temperature of the gas changes by ΔT, it follows from Equation 15-16 that the internal energy change is

(15-17) ΔU=n(D2R)ΔT (ideal gas, D degrees of freedom)

But, we saw above that for an ideal gas, ΔU=nCV ΔT. Comparing this to Equation 15-17, we see that