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EXAMPLE 1 Verify the requirements for performing an analysis of variance

dormitory

Verify the requirements for performing an analysis of variance using the hypotheses

H0:μA=μB=μCversusHa:not all the population means are equal

where μi represents the population mean GPA for Dormitory i, using data from Table 1.

Solution

  • Step 1 Normality. To verify that each of the k=3 populations is normally distributed, we examine normal probability plots of each sample, shown in Figure 5. Each plot indicates acceptable normality.

    FIGURE 5 Normal probability plots verify normality requirement.
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  • Step 2 Equal Variances. To find the standard deviation for Dorm A, we first find

    (xˉx)2=(0.602.2)2+(3.822.2)2+(4.002.2)2+(2.222.2)2+(1.462.2)2+(2.912.2)2+(2.202.2)2+(1.602.2)2+(0.892.2)2+(2.302.2)2=11.5626

    Then

    sA=(xˉx)2n1=11.56261011.133460777

    We similarly find sB1.030857248 and sC0.9370284. The largest, sA1.133460777, is not larger than twice the smallest, sC0.9370284. Thus, the equal variance require-ment is satisfied.

  • Step 3 Independence. Because the students are randomly sampled from each dormitory, with the selection of students in one dormitory not affecting the selection of students sampled from the other dormitories, the independence assumption is also validated.

Note: We retain many decimal places when calculating sA, sB, and sC because these values are used to calculate other quantities later on.

NOW YOU CAN DO

Exercises 7–10.

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