EXAMPLE 1 Verify the requirements for performing an analysis of variance
dormitory
Verify the requirements for performing an analysis of variance using the hypotheses
H0:μA=μB=μCversusHa:not all the population means are equal
where μi represents the population mean GPA for Dormitory i, using data from Table 1.
Solution
Step 1 Normality. To verify that each of the k=3 populations is normally distributed, we examine normal probability plots of each sample, shown in Figure 5. Each plot indicates acceptable normality.
Step 2 Equal Variances. To find the standard deviation for Dorm A, we first find
∑(x−ˉx)2=(0.60−2.2)2+(3.82−2.2)2+(4.00−2.2)2+(2.22−2.2)2 +(1.46−2.2)2+(2.91−2.2)2+(2.20−2.2)2+(1.60−2.2)2 +(0.89−2.2)2+(2.30−2.2)2 =11.5626
Then
sA=√∑(x−ˉx)2n−1=√11.562610−1≈1.133460777
We similarly find sB≈1.030857248 and sC≈0.9370284. The largest, sA≈1.133460777, is not larger than twice the smallest, sC≈0.9370284. Thus, the equal variance require-ment is satisfied.
Note: We retain many decimal places when calculating sA, sB, and sC because these values are used to calculate other quantities later on.
NOW YOU CAN DO
Exercises 7–10.