EXAMPLE 15 Finding percentiles Using the Central Limit Theorem for Proportions
Figure 7.15: FIGURE 16 Finding the percentiles using the TI-83/84.
Using the information from Example 13, find the 2.5th and the 97.5th percentiles of sample proportions for .
Solution
We use the inverse normal function on the TI-83/84, just as we did in Example 8 (page 406). The results, using mean and standard deviation , are shown in Figure 16. We have the and the .
The 2.5th and the 97.5th percentiles contain the middle 95% of sample proportions, as shown in Figure 17.
Figure 7.16: FIGURE 17 The 2.5th percentile and the 97.5th percentile contains the middle 95% of sample proportions.
NOW YOU CAN DO
Exercises 33–38.