Self Check Answers
Self Check Answers
- 8 vertices and 11 edges
- A, B, D, H, F, and E are even-valent.
- It is not an Euler circuit. One of the two edges joining B and F was not traversed; FG was traversed twice; edge BC was not traversed.
- No. Though the graph is connected, its vertices are not all even-valent.
- By duplicating one edge, we get a new graph, all of whose vertices are even-valent.