Chapter 1. Chapter 5 Branched Tutorial: Epistasis

1.1 Problem Statement

Final Feedback

Epistasis problems can follow a similar solution process as traditional Mendelian inheritance problems. Both types of problems will involve segregation of alleles and independent assortment; a Punnett square or branch diagram can be used to help you obtain the genotypes and frequencies for each cross. Completing this portion of the problem will provide you with the basic information—you will then need to interpret the genotypes based on the allele interactions to assign the correct phenotypes.

In this problem, you worked step by step to: identify the relationship of the alleles to one another; determine the gametes from each parent; conduct the cross to obtain the progeny genotypes; assign phenotypes; and determine the proportions of each phenotype. All of this information is combined to provide the final, summary answer of proportions and phenotypes of progeny for each cross.

The type of plumage found in mallard ducks is determined by three alleles at a single locus: MR, which encodes restricted plumage; M, which encodes mallard plumage; and md, which encodes dusky plumage. The restricted phenotype is dominant over mallard and dusky; mallard is dominant over dusky (MR > M > md).

Question

Give the expected phenotypes and proportions of offspring produced by the following crosses:

a. MRM × mdmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
b. MRmd × Mmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f mallard Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f dusky
c. MRmd × MRM C/3EiBqnMMR9jY3N+qRQDfPTe1YSoJED restricted Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
d. MRM × Mmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
2
Great job!
At least one of your answers is incorrect. Try again or click "Work Problem Step-By-Step" to go through the tutorial steps.
Incorrect.
false
{qq == true} done
{help} 1.2 OK. Let’s go through the problem step by step. We’ll start by determining the best approach to solving this problem.
{qqMC1 != 0 && qqMC2 != 0 && qqMC3 == 0 && qqMC4 != 0 && qqMC5 != 0 && qqMC6 != 0 && qqMC7 != 0 && qqMC8 != 0 && qqMC9 == 0 && qqMC10 != 0 && qqMC11 != 0 && qqMC12 == 0} 1.6 Let’s set up Punnett squares for these crosses to help determine the proportion of each phenotype.
{(qqMC1 == 0 || qqMC1 == 2) && (qqMC2 == 0 || qqMC2 == 2) && (qqMC3 == 0 || qqMC3 == 2) && (qqMC4 == 1 || qqMC4 == 2) && (qqMC5 == 1 || qqMC5 == 2) && (qqMC6 == 1 || qq6 == 2) && (qqMC7 == 0 || qqMC7 == 1 || qqMC7 == 3) && (qqMC8 == 0 || qqMC8 == 1 || qqMC8 == 3) && (qqMC9 == 0 || qqMC9 == 1 || qq9MC == 3) && (qqMC10 == 0 || qqMC10 == 2) && (qqMC11 == 0 || qqMC11 == 2) && (qqMC12 == 0 || qqMC12 == 2)} 1.7 Let’s work on converting each genotype into the correct phenotype.
{else} 1.2 Let’s work through this problem step by step.

1.2 Problem Strategy

Question

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
2
Correct.
Incorrect. You have one more chance to answer correctly. Please try again.
Incorrect.

Instant TA

It is important to first identify the key information from the problem. Even though this problem involves epistasis, the approach will be the same as solving typical Mendelian inheritance problems. It will be very important to understand the dominance relationship between the alleles before carrying out the crosses.

1.3 Step 1: Understanding the problem

Question

1. Match the allele with the correct phenotype.

acLzd3s/UjTUSW3zBg8bJ+ygYQ7vRZ0ACvgwSJjgcAGMzKqu/FA+9Q== dusky

Wyi9mUa7H2KfLVGdIbYjKedgs2CgxO/97O3XPDBauorDiX9C7fz9zQ== mallard

ZCEfwzHJsMA/wDXCUj3hxVB7xsNn4YCWJserEIDcuB/FZLCNAnBfQA== restricted

2
Correct.
Incorrect. You have one more chance to answer correctly. Please try again.
Incorrect.

Instant TA

Review the Problem Statement to help you identify the allele designation that is used for each phenotype.

1.4 Step 2: Determining the dominance relationship between the alleles

Question

1. Use the dominance relationship between the alleles to identify the phenotype associated with each genotype.

VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE= M R M R

44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk= Mm d

VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE= M R m

IkP29rwD6gkG45J/9wmvg7sIV05vMGrV4ycwHxBW2Vc= m d m d

VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE= M R m d

44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk= MM

2
Correct.
Incorrect. You have one more chance to answer correctly. Please try again.
Incorrect.

Instant TA

Review the Problem Statement to help you identify the dominance relationships between the alleles.

1.5 Step 3: Determining the gametes

Question

1. For cross “a,” determine the types of gametes produced by each parent.

Gametes from MRM parent: MR UxXCdiuIDfYB7iao| M UxXCdiuIDfYB7iao| md YZqRursQbQ4R6IcA

Gametes from mdmd parent: MR YZqRursQbQ4R6IcA| M YZqRursQbQ4R6IcA| md UxXCdiuIDfYB7iao

1
Great job!
At least one of your answers is incorrect. Try again
Incorrect.

Instant TA

The alleles for plumage type are encoded by a single locus. The parental alleles will segregate in meiosis so that only one allele would be found in each gamete. Even though there are three alleles for this locus, an individual can only carry two alleles.

Question

2. For cross “b,” determine the types of gametes produced by each parent.

Gametes from MRmd parent: MR UxXCdiuIDfYB7iao| M YZqRursQbQ4R6IcA| md UxXCdiuIDfYB7iao

Gametes from Mmd parent: MR YZqRursQbQ4R6IcA| M UxXCdiuIDfYB7iao| md UxXCdiuIDfYB7iao

1
Great job!
At least one of your answers is incorrect. Try again
Incorrect.

Instant TA

The alleles for plumage type are encoded by a single locus. The parental alleles will segregate in meiosis so that only one allele would be found in each gamete. Even though there are three alleles for this locus, an individual can only carry two alleles.

Question

3. For cross “c,” determine the types of gametes produced by each parent.

Gametes from MRmd parent: MR UxXCdiuIDfYB7iao| M YZqRursQbQ4R6IcA| md UxXCdiuIDfYB7iao

Gametes from MRM parent: MR UxXCdiuIDfYB7iao| M UxXCdiuIDfYB7iao| md YZqRursQbQ4R6IcA

1
Great job!
At least one of your answers is incorrect. Try again
Incorrect.

Instant TA

The alleles for plumage type are encoded by a single locus. The parental alleles will segregate in meiosis so that only one allele would be found in each gamete. Even though there are three alleles for this locus, an individual can only carry two alleles.

Question

4. For cross “d,” determine the types of gametes produced by each parent.

Gametes from MRM parent: MR UxXCdiuIDfYB7iao| M UxXCdiuIDfYB7iao| md YZqRursQbQ4R6IcA

Gametes from Mmd parent: MR YZqRursQbQ4R6IcA| M UxXCdiuIDfYB7iao| md UxXCdiuIDfYB7iao

1
Great job!
At least one of your answers is incorrect. Try again
Incorrect.

Instant TA

The alleles for plumage type are encoded by a single locus. The parental alleles will segregate in meiosis so that only one allele would be found in each gamete. Even though there are three alleles for this locus, an individual can only carry two alleles.

1.6 Step 4: Predicting the offspring genotypes with a Punnett square

Question

1. For cross “a,” combine the gametes of the two parents with the use of a Punnett square. Indicate the correct gametes from the first parent along the top of the table and the gametes from the second parent along the left side of the table. The gamete order should be maintained as indicated (the first gamete for each parent would be listed first in the row or column). Select the correct genotype for each combination of gametes which would appear in the labeled cells of the Punnett square.

Please note that that the dropdown menus are not able to display the proper notation for the alleles (italics and superscripts).

6m3cXuPCDDa84peNoo3jkQ== TVNPzQYM/z48X0l/FYi9qA==
+kAxdZlbGyQ9zcsf3LYRVw== 6oiK67/dv4VzE3O8fOcPKyoDCOKWrL7ikVmaZZuHBzh/z0Dy zIU44+ko86ImIlRTK05LKlFbmtGuXRxBfbN4CyUs91UL2YXc
+kAxdZlbGyQ9zcsf3LYRVw== 6oiK67/dv4VzE3O8fOcPKyoDCOKWrL7ikVmaZZuHBzh/z0Dy zIU44+ko86ImIlRTK05LKlFbmtGuXRxBfbN4CyUs91UL2YXc
2
Great job!.
At least one of your answers is incorrect. Try again. Be sure that you are following the directions to set up your Punnett square correctly.
Incorrect.

Instant TA

The Punnett square provides an easy way to determine the genotypes of the progeny for this cross. Remember that the gametes from the first parent should be listed across the top of the table and the gametes from the second parent should be listed along the left side of the table.

Question

2. For cross “b,” combine the gametes of the two parents with the use of a Punnett square. Indicate the correct gametes from the first parent along the top of the table and the gametes from the second parent along the left side of the table. The gamete order should be maintained as indicated (the first gamete for each parent would be listed first in the row or column). Select the correct genotype for each combination of gametes which would appear in the labeled cells of the Punnett square.

6m3cXuPCDDa84peNoo3jkQ== +kAxdZlbGyQ9zcsf3LYRVw==
TVNPzQYM/z48X0l/FYi9qA== jWi+aTYaMvUBDGQFKmDmGGCiaIvWCuONtHoRDDl/QP1JQ092 zIU44+ko86ImIlRTK05LKlFbmtGuXRxBfbN4CyUs91UL2YXc
+kAxdZlbGyQ9zcsf3LYRVw== 6oiK67/dv4VzE3O8fOcPKyoDCOKWrL7ikVmaZZuHBzh/z0Dy DuiSR6Be5V3k9y5rCIyyFlHTKVJJkEauciVA46YIyD01RadV
2
Great job!.
At least one of your answers is incorrect. Try again. Be sure that you are following the directions to set up your Punnett square correctly.
Incorrect.

Instant TA

The Punnett square provides an easy way to determine the genotypes of the progeny for this cross. Remember that the gametes from the first parent should be listed across the top of the table and the gametes from the second parent should be listed along the left side of the table.

Question

3. For cross “c,” combine the gametes of the two parents with the use of a Punnett square. Indicate the correct gametes from the first parent along the top of the table and the gametes from the second parent along the left side of the table. The gamete order should be maintained as indicated (the first gamete for each parent would be listed first in the row or column). Select the correct genotype for each combination of gametes which would appear in the labeled cells of the Punnett square.

6m3cXuPCDDa84peNoo3jkQ== +kAxdZlbGyQ9zcsf3LYRVw==
6m3cXuPCDDa84peNoo3jkQ== pET7MDK273gZ2S7MqVBSomFBZVb2JHu8OqIWfbTMpVgOASRK 6oiK67/dv4VzE3O8fOcPKyoDCOKWrL7ikVmaZZuHBzh/z0Dy
TVNPzQYM/z48X0l/FYi9qA== jWi+aTYaMvUBDGQFKmDmGGCiaIvWCuONtHoRDDl/QP1JQ092 zIU44+ko86ImIlRTK05LKlFbmtGuXRxBfbN4CyUs91UL2YXc
2
Great job!.
At least one of your answers is incorrect. Try again. Be sure that you are following the directions to set up your Punnett square correctly.
Incorrect.

Instant TA

The Punnett square provides an easy way to determine the genotypes of the progeny for this cross. Remember that the gametes from the first parent should be listed across the top of the table and the gametes from the second parent should be listed along the left side of the table.

Question

4. For cross “d,” combine the gametes of the two parents with the use of a Punnett square. Indicate the correct gametes from the first parent along the top of the table and the gametes from the second parent along the left side of the table. The gamete order should be maintained as indicated (the first gamete for each parent would be listed first in the row or column). Select the correct genotype for each combination of gametes which would appear in the labeled cells of the Punnett square.

6m3cXuPCDDa84peNoo3jkQ== TVNPzQYM/z48X0l/FYi9qA==
TVNPzQYM/z48X0l/FYi9qA== jWi+aTYaMvUBDGQFKmDmGGCiaIvWCuONtHoRDDl/QP1JQ092 +D7FBKThJsV6bVebLxUnmLrhgUKcn9CyUuww5ndGQ8AlaOyq
+kAxdZlbGyQ9zcsf3LYRVw== 6oiK67/dv4VzE3O8fOcPKyoDCOKWrL7ikVmaZZuHBzh/z0Dy zIU44+ko86ImIlRTK05LKlFbmtGuXRxBfbN4CyUs91UL2YXc
2
Great job!.
At least one of your answers is incorrect. Try again. Be sure that you are following the directions to set up your Punnett square correctly.
Incorrect.

Instant TA

The Punnett square provides an easy way to determine the genotypes of the progeny for this cross. Remember that the gametes from the first parent should be listed across the top of the table and the gametes from the second parent should be listed along the left side of the table.

1.7 Step 5: Assigning the correct phenotype to the progeny genotype

Question

1. For cross “a,” determine the phenotype of each offspring.
Progeny genotype: MRmd. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: Mmd. Phenotype: 44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk=

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The phenotypes of the progeny can be determined by looking at the dominance relationships of the alleles in the progeny’s genotype.

Question

2. For cross “b,” determine the phenotype of each offspring.
Progeny genotype: MRM. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: MRmd. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: Mmd. Phenotype: 44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk=
Progeny genotype: mdmd. Phenotype: IkP29rwD6gkG45J/9wmvg7sIV05vMGrV4ycwHxBW2Vc=

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The phenotypes of the progeny can be determined by looking at the dominance relationships of the alleles in the progeny’s genotype.

Question

2. For cross “c,” determine the phenotype of each offspring.
Progeny genotype: MRMR. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: MRM. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: MRmd. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: Mmd. Phenotype: 44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk=

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The phenotypes of the progeny can be determined by looking at the dominance relationships of the alleles in the progeny’s genotype.

Question

3. For cross “d,” determine the phenotype of each offspring.
Progeny genotype: MRM. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: MRmd. Phenotype: VLwPF9x+ZLRx5oXMFBBbHRQrPutNzkeFRnVYSGhJ3DE=
Progeny genotype: MM. Phenotype: 44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk=
Progeny genotype: Mmd. Phenotype: 44bj998zZqKzyZ8HqUhZTaK1gjh/wnXIho+cDylSsHk=

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The phenotypes of the progeny can be determined by looking at the dominance relationships of the alleles in the progeny’s genotype.

1.8 Step 6: Determining the proportion of each progeny phenotype

Question

1. For cross “a,” (MRM × mdmd) determine the proportion of each progeny phenotype. Any phenotypes that do not appear with this cross should be indicated as “0.”
Restricted: Q4HkdsINFP4woNW2CQogGLXXAe5V5II7
Mallard: Q4HkdsINFP4woNW2CQogGLXXAe5V5II7
Dusky: ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The proportion should be expressed as a fraction and the values should add up to 1. This value can be determined by using the information in the Punnett square.

Question

2. For cross “b,” (MRmd × Mmd) determine the proportion of each progeny phenotype. Any phenotypes that do not appear with this cross should be indicated as “0.”
Restricted: Q4HkdsINFP4woNW2CQogGLXXAe5V5II7
Mallard: Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f
Dusky: Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The proportion should be expressed as a fraction and the values should add up to 1. This value can be determined by using the information in the Punnett square.

Question

3. For cross “c,” (MRmd × MRM) determine the proportion of each progeny phenotype. Any phenotypes that do not appear with this cross should be indicated as “0.”
Restricted: C/3EiBqnMMR9jY3N+qRQDfPTe1YSoJED
Mallard: Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f
Dusky: ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The proportion should be expressed as a fraction and the values should add up to 1. This value can be determined by using the information in the Punnett square.

Question

4. For cross “d,” (MRM × Mmd) determine the proportion of each progeny phenotype. Any phenotypes that do not appear with this cross should be indicated as “0.”
Restricted: Q4HkdsINFP4woNW2CQogGLXXAe5V5II7
Mallard: Q4HkdsINFP4woNW2CQogGLXXAe5V5II7
Dusky: ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT

2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

The proportion should be expressed as a fraction and the values should add up to 1. This value can be determined by using the information in the Punnett square.

1.9 Step 7: Reviewing your answers

Question

1. Give the expected phenotypes and proportions of offspring produced by the following cross:

MRM × mdmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

Review your answers provided in the earlier steps of this tutorial.

Question

2. Give the expected phenotypes and proportions of offspring produced by the following cross:

MRmd × Mmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f mallard Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f dusky
2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

Review your answers provided in the earlier steps of this tutorial.

Question

3.Give the expected phenotypes and proportions of offspring produced by the following cross:

MRmd × MRM C/3EiBqnMMR9jY3N+qRQDfPTe1YSoJED restricted Jl3L0N1C1bGuwH9lMqfve2HQ3A0I0F9f mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

Review your answers provided in the earlier steps of this tutorial.

Question

4. Give the expected phenotypes and proportions of offspring produced by the following cross:

MRM × Mmd Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 restricted Q4HkdsINFP4woNW2CQogGLXXAe5V5II7 mallard ufeY7Y1ixo/Kg+tSY3jFYT2LNIACSAXT dusky
2
Great job!
At least one of your answers is incorrect. Try again.
Incorrect.

Instant TA

Review your answers provided in the earlier steps of this tutorial.