Chapter 14. Molecular Geometry, Bonding, and Polarity

Objectives

Laboratory 11
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At the end of this activity you should be able to:

  • Write Lewis structures for molecules.
  • Classify bonds as nonpolar covalent, polar covalent, or ionic based on electronegativity differences.
  • Recognize exceptions to the octet rule; draw accurate representations.
  • Describe three-dimensional shapes of simple molecules based on VSEPR theory.
  • Predict polarity based on geometry and individual dipole moments.
  • Use a model kit to construct physical models of molecules consistent with VSEPR theory and describe the bond and molecular polarity.
These learning objectives are assessed in the post-lab quiz and with an
end-of-class laboratory practical.

There is no laboratory report.

You may record your responses within the laboratory manual.

Introduction

The substances in our world exhibit remarkably different properties. At room temperature some substances are solids, others liquids, and others gases. Some participate in sudden chemical reactions, whereas others are quite inert and unreactive. Perhaps most remarkably, this wonderful diversity occurs even though the substances are comprised of a limited number of elements. Indeed, only a very small number of different elements are present in almost any pure substance we encounter in the environment or the laboratory. How can this wide diversity of properties be explained?

A key to understanding the wide range of physical and chemical properties of substances is recognizing that atoms combine with other atoms to form molecules or compounds and that the shape or geometry of a collection of atoms strongly affects the properties of that substance. One reason this occurs is because the distribution of charge in a molecule affects many properties of the substance. For example, if the negative change is concentrated in one region of a molecule its properties will be widely different than if the charge is distributed evenly throughout the entire molecule.

In this investigation you will examine a theory that chemists use to explain different aspects of chemical bonding: valence shell electron pair repulsion (VSEPR) theory. Attention will be given to how molecules are arranged in different shapes and how chemists can predict the geometry of a given molecule. It will then be shown how a molecule’s shape, along with electronegativity differences for its atoms, determine the molecule’s polarity. As suggested above, the best way to understand and predict the physical and chemical properties of substances in our world is by understanding their structure at the molecular level.

Discussion of Activities

In this investigation you will complete activities that ask you to examine molecular geometry and molecular polarity. These activities are based on computer simulations and balland- stick models. All of these activities can be discussed with classmates and/or completed in small groups. Your Teaching Assistant will check on your progress.

The VSEPR model can be used to predict the geometry of molecules and polyatomic ions. Molecular geometry describes the positions of the nuclei in relation to each other. Included in the description are the bond angles, the angles made by the lines joining the nuclei of bonded atoms. In order to predict geometry using the VSEPR model, we need to know the number of electron pairs in the valence shell of the central atom. That can easily be determined by drawing a Lewis structure.

Activity 1: Drawing Lewis Structures

Guidelines for Drawing Lewis Structures

  1. Determine the total number of valence electrons; for polyatomic ions remember to adjust for charge.
  2. Arrange atoms in a skeleton structure and connect them with single bonds.
  • If you are working with a molecule or ion that has three or more atoms, the least electronegative atom is most likely to be the central atom (remember that hydrogen can only form one bond and therefore is never a likely candidate to be the central atom).
  1. Complete octets of the terminal atoms (remember H atoms can only accommodate 2 electrons).
  2. If not all of the valence electrons have been used, place any extra electrons on the central atom.
  • Extra electrons placed on the central atom may in some cases bring the number to more than eight. This is called expansion of the valence shell and is an exception to the octet rule; this is acceptable for atoms in the third period and below.
  1. If the central atom does not have an octet, use lone pairs from terminal atoms to form multiple bonds.
  • Only the second period elements, C, N, O and sometimes S (in combination with C or O), form multiple bonds. This leads to another exception to the octet rule, i.e., when an atom like Be is combined with either hydrogen or halogens, as in BeH2. Since Be does not form multiple bonds, the central atom is electron-deficient.
  • If more than one acceptable Lewis structure can be drawn by simply choosing a lone pair from a different terminal atom to form a double bond with the central atom, the different structures are called resonance forms. The “extra” electron pair is delocalized, spread out among the possible bonding sites.

Table 11.1 Drawing Lewis structures and determining electron and bonding domains.

One reason Lewis structures are useful is because they help to identify the number of electron domains, or regions of high electron density, about a central atom. An electron domain can be a bonding pair, a lone pair, or a double or triple bond. A multiple bond is counted as one domain.

The Lewis structure for HCN is shown below. Notice that the central carbon atom has two electron domains (a single bond and a triple bond) and also two bonding domains. The nitrogen atom also has two electron domains (a lone pair of electrons and a triple bond) but only one bonding domain. The hydrogen atom only has one electron domain (the single bond) and one bonding domain.

Activity 2: VSEPR and Predicting Molecular Geometry

Once we have the Lewis structure, we have the information needed to predict the geometry. It’s important to remember that what we really want to know is the molecular geometry—the positions of the nuclei in relation to each other. The molecular geometry is dependent on the electron domain geometry; that is why the initial step is drawing the appropriate Lewis structure! As noted above, the simple concept behind valence shell electron pair repulsion theory (VSEPR) is the idea that electron pairs in the valence shell of an atom will repel each other and arrange themselves as far apart as possible. This arrangement of electron pairs will determine the geometry of the molecule or polyatomic ion.

Figure 11.1 The PhET computer simulatioin "Molecule Shapes."

Your initial task in this activity is to determine the molecule geometry as the number of electron pairs changes. Accomplish this by using the computer simulation “MoleculeShapes” (shown above) and fill in the table.

Notice, in this simulation you can increase the number of electron domains by adding single, double, or triple bonds, or lone pair electrons. In the lower left corner you will find both the molecule geometry and the electron geometry.

Table 11.2 Model electron domain geometries.

The molecular geometry is the same as the electron domain geometry if all domains contain bonding pairs. What if lone pair electrons are present on the central atom? The molecular geometry will NOT be the same as the electron domain geometry. To investigate this, return to the simulation and complete Table 11.3. If you do not understand the names for the different geometries ask your Teaching Assistant.

Table 11.3 Electron and molecular geometries.


Question 11.1: VSEPR stands for “valence shell electron pair repulsion.” How does electron pair repulsion determine the molecular geometry? Discuss two specific examples from the table. (Hint: In the simulation, is it possible to force the electron domains to be close together?)



Question 11.2:

For each shape identify the molecular geometry.

i.

ii.

iii.

Determine the electron domain geometry on which the molecular geometry is based.

i.

ii.

iii.

How many lone pairs are there on each central atom?

i.

ii.

iii.

Which of the following element(s) could be the central atom in shape (iii)?

Be, C, S, Se, Si, Xe?

You may have noticed that some electron domains appear larger than others. To investigate how this may affect the resulting molecular geometry, complete Table 11.4 and predict both the geometry and the bond angles. Then, compare your predictions with the experimentally determined bond angles (as shown in the simulation under the tab “Real Molecules”).

Table 11.4 Comparison of electron domains.


Question 11.3: Which assumption about the space occupied by nonbonding (lone pair) electron pairs is most consistent with the experimental bond angles: Do nonbonding pairs occupy more, less, or the same amount of space as bonding pairs?


Activity 3: Molecular Polarity

Your next task in this activity is to investigate the relationship between bond polarity, molecular shape, and molecular polarity. Accomplish this with the computer simulation “Molecule Polarity.”

To begin, take a few moments and explore the simulation. Click on different things and see what happens, what you can manipulate, etc.

Investigating Bond Polarity with the Molecule AB

Select the “Two Atoms” tab on the top.

You will initially examine the bond polarity, which is a measure of how equally the electrons in a bond are shared between the two atoms of the bond.

There are different ways of representing where the electrons are in a bond. Take a few minutes and try the different “views” in the simulation, i.e., bond dipole, partial charges, and bond character. The electron density or electrostatic potential are other ways of communicating where the electrons are in the molecule.

Note: Within the simulation you change the relative electronegativity of atoms A and B.



Molecules in Electric Fields

In this simulation, the molecule AB is placed between electric plates (–) and (+) and an electric field can be turned on or off. It is also possible to click on the molecule AB and rotate it.


Question 11.5:

  1. What happens to the molecule AB when it has a bond dipole and the electric field is turned on? Spin the molecule around several times and make observations. What if the bond dipole is zero?
  2. Is there a relationship between the magnitude of the bond dipole and how the molecule is affected by the electric field?

Investigating Bond Polarity and Molecular Polarity with the Molecule ABC

Select the “Three Atoms” tab on the top.

In this portion of the simulation you can manipulate molecule ABC. The relative electronegativity of each atom can again be changed. However, it is now also possible to change the geometry by clicking and dragging an atom to change the angle <ABC. Once again, you can spin the entire molecule.

In the “View” section a new option has been added, “Molecular Dipole.” Molecular polarity describes the charge distribution in the entire molecule, not just a bond. If centers of positive and negative charge do not coincide, the molecule is polar. How can you predict if a molecule is polar? The two important variables are 1) the bond dipoles in the molecule, and 2) the molecular geometry.

It is important to note that bond dipoles are vector quantities; that is, they have both a magnitude and a direction. In a polyatomic molecule, like ABC, the magnitude and the direction of the individual bond dipoles must be considered when summing vectors. As an example, consider the molecule CO2. In this molecule there are two bond dipoles because the electronegativity of carbon and oxygen differ. There is no overall molecular dipole, however, because the bond dipoles “cancel” since they are of equal magnitude and pointed in opposite directions. Carbon dioxide is an example of a nonpolar molecule that has polar bonds.

To explore the idea of molecular polarity, complete the following table. Make an initial prediction as to whether each ABC molecule will be polar or nonpolar based on the bond dipoles and the geometry; remember, bond dipoles are vector quantities. Then, construct the molecule in the simulation and see how it behaves in the electric field. Were your predictions correct?

Putting It All Together...

Being able to predict the polarity of a molecule is extremely important since many properties of molecules depend on whether they are polar or nonpolar. As you have seen in this activity, determining a molecule’s polarity is a multi-step process:

Draw Lewis structure

          ↓

Use VSEPR to determine molecular geometry

                    ↓

Determine bond polarity (based on electronegativity differences)

                              ↓

Determine molecular polarity based on bond dipoles and molecular geometry

For the following molecules, complete this step-by-step process.

Make a prediction, then check it in the “Real Molecules” section of the simulation.

Activity 4: Molecule Model Kit and Laboratory Practical

Chemists have long used model kits to communicate the spatial arrangement of atoms. To conclude this laboratory experiment you will construct several molecules using a modelkit. To do this correctly you must apply the steps noted previously, e.g., begin with the Lewis structure, apply VSEPR theory, and finally consider the molecular polarity.

Lab Practical

A lab practical concludes the lab. In the lab practical you will use the model kit to construct a few molecules, discuss them with your TA, and answer a few questions. This will be done individually without referring to your lab manual or notes. You may consult a periodic table. To prepare for the lab practical you should work through the following examples and discuss your answers with your classmates and/or TA.

Construct a representation of the molecule CH4.
  • What is the electron domain geometry?
  • What is the molecular domain geometry?
  • What is the approximate H–C–H bond angle?
  • Is the molecule polar or nonpolar?
  • Does it have a net dipole moment? How would it behave when placed in an electric field?
Construct a representation of the molecule NH3.
  • What is the electron domain geometry?
  • What is the molecular domain geometry?
  • How do the bond angles in NH3 compare with those in CH4?
  • Is the molecule polar or nonpolar?
  • Does it have a net dipole moment? How would it behave when placed in an electric field?
Construct a representation of a trigonal bipyramidal molecular geometry.
  • Is the electron domain geometry the same as the molecular geometry?
  • Use a periodic table and suggest a molecule that would adopt a trigonal bipyramidal structure.
  • Is it possible for a molecule to have a trigonal bipyramidal geometry and be polar? To have a trigonal bipyramidal geometry and be nonpolar?
  • What is the molecular geometry if one of the bonds is replaced by a lone pair of electrons? Does this change affect the bond angles?
Construct a representation of the molecule XeF2.
  • What is the electron domain geometry?
  • What is the molecular domain geometry?
  • What is the F–Xe–F bond angle?
  • Is the molecule polar or nonpolar?
  • Does it have a net dipole moment? How would it behave when placed in an electric field?
Construct a representation of a seesaw molecular geometry (SF4 is an example).
  • What is the electron domain geometry?
  • What happens if SF4 molecules are placed in an electric field?
  • What is the molecular geometry if one of the bonds is replaced by a lone pair of electrons?