The boiling of a liquid is a common phenomenon familiar to all of us. In both the kitchen and the laboratory we have all observed the boiling of water. We have also observed what happens when a puddle of water evaporates on a sunny day. In these examples the water molecules become gaseous, leave the system (the water) and enter the air (the surroundings). Would the boiling of water, or any other liquid for that matter, be affected if the gaseous molecules remained part of the system? What happens if the liquid and the gas above it are a closed system, i.e., a system in which energy can be exchanged with the surroundings but matter cannot? In this laboratory experiment you bring together the concepts of intermolecular forces, boiling point, and vapor pressure and develop a model to be able to answer questions like these.
Molecules can escape from the surface of a liquid into the gas phase by evaporation. In order to escape the liquid the molecule must overcome the intermolecular forces that attract it to other molecules in the liquid phase. If a liquid is heated the motion of the molecules increases. With this increase in kinetic energy some molecules have sufficient energy to overcome the attractive forces holding it in the liquid phase. The amount of energy required to vaporize a mole of liquid is the heat of vaporization, ΔHvap. The units for heat of vaporization are generally kJ · mol–1:
Question 14.1: Which statement(s) regarding the heat of vaporization is/are true?
What happens after the particles enter the gas phase? If the vessel is open to the atmosphere they may disperse and move away from the liquid. However, if they happen to strike the surface of the liquid they can be recaptured and return to the liquid phase. Obviously, as the concentration of gas-phase molecules increases the probability that they will strike the surface and condense, i.e., go from the gas phase to the liquid phase, also increases. We therefore have two processes taking place simultaneously; evaporation of the liquid and the condensation of the gas. When two processes occur simultaneously at equal rates, they are said to be in dynamic equilibrium. Even though it may appear nothing is happening, a great deal is happening as some of the molecules continuously pass from liquid to gas state, and from gas to liquid state.
Suppose the evaporation of the liquid and condensation of the gas takes place in a closed system. When the molecules are in the gaseous phase they will exert a pressure as they strike the walls of the container (see Figure 14.1). The vapor pressure of a liquid is the pressure exerted by its vapor when the liquid and vapor are in dynamic equilibrium.
In (a) we imagine that no molecules of the liquid are in the gas phase initially; there is zero vapor pressure in the vessel. In (b), after equilibrium is reached, the rate at which molecules leave the surface equals the rate at which gas molecules return to the liquid phase. These equal rates produce a stable vapor pressure that does not change as long as the temperature remains constant. What do you predict happen if there are initially no gas molecules above the liquid (Figure 14.1a)? If there is no external pressure being exerted on the liquid’s surface, it will be easier for the gas molecules to escape into the vapor. In other words, the evaporation of a liquid is affected by the external pressure acting on the liquid surface. When the vapor pressure equals the external pressure acting on the liquid it is boiling. The boiling point of a liquid at 1 atm (760 torr) pressure is called its normal boiling point.
Question 14.2: What do the liquids shown in Figure 14.2 have in common? Select all true statements:
There is a quantitative relationship between vapor pressure, temperature, and heat of vaporization known as the Clausius-Clapeyron equation,
where P is the vapor pressure at temperature T, ΔHvap is the heat of vaporization, R is the gas constant, 8.315 J · mol−1· K−1, and C is a constant. The units of R makes clear that temperature must be in Kelvins and that ΔHvap will have units of J · mol−1. Notice that the equation has the form of the equation of a straight line. If the vapor pressure is determined at a number of different temperatures, a graph of ln P vs. 1/T should be a straight line with a slope of −ΔHvap /R and
In this way, it is possible to experimentally determine the ΔHvap and one of the points on the graph will be the boiling point, i.e., the temperature at which the vapor pressure equals atmospheric pressure.
Question 14.3: Which statement correctly states the relationship between intermolecular force, vapor pressure, and normal boiling point?
The procedure has three parts:
a. Determine temperature–volume data for a known compound.
b. Determine temperature–volume data for an unknown compound.
c. Determine the boiling point of the unknown compound.
The temperature–volume data is obtained by injecting a small amount of the compound to be studied into a 30-mL syringe. The syringe is immersed in a water bath and the water is slowly heated. The experimental setup is shown in Figure 14.3. Volume readings are taken at five different temperatures.
At each of the five temperatures, the liquid will establish its vapor pressure. The vapor pressure is then calculated from volume measurements using Dalton’s law and the combined gas law. The known compound is one in a set of three related compounds, and data for the other two known compounds in the set will be obtained from students designated by your lab instructor. After the syringe is cleaned and dried, the procedure is repeated with the unknown sample.
In the third part of the experiment the boiling point of the unknown sample will be determined. The setup for the boiling point determination is shown in Figure 14.4. The key to a successful boiling point determination is to keep everything on small scale: A 100-mL beaker is used for the water bath; a 4-mL test tube contains 1 mL of the sample. A capillary tube is broken to a length of approximately 3 cm and placed, open end down, in the liquid. As the temperature is slowly increased, a fine stream of bubbles will come from the capillary tube as vapor from the unknown liquid forces air from the capillary tube. After a few seconds, the capillary tube will contain only vapor from the unknown. The burner is removed and the liquid slowly starts to cool. When the vapor pressure falls below atmospheric pressure, liquid will start to enter the capillary tube. This temperature, at which vapor pressure equals atmospheric pressure, is the boiling point.
As noted above, ΔHvap is calculated from the slope of the graph of ln P vs. 1/T, where P is the vapor pressure of the liquid at temperature T in Kelvins. The vapor pressures must be calculated from recorded volumes.
The syringe contains both air and vapor from the liquid sample. As the temperature is increased, two things happen: conditions of pressure and volume change for the air and more of the liquid vaporizes. At each temperature, the liquid is assumed to be in equilibrium with the vapor.
The pressure inside the syringe is equal to the barometric pressure, PB, and is the sum of the pressure of the sample, PS, and the pressure of the air, PA (Dalton’s law):
The pressure of the sample is what we need to know; it is the vapor pressure of the liquid:
An expression for the pressure of air at each temperature is obtained from the combined gas law:
The left side of the equation represents the initial conditions: the volume of air (VR) in the syringe at room temperature (TR) and the barometric pressure (PB). The right side of the equation represents a second set of conditions: pressure and volume at some higher temperature. Solve the equation for pressure of air, PA:
Equation (4) can now be substituted into equation (2):
In your analysis, calculate the pressure of the sample at each set of conditions.
Graph ln PS vs. 1/T for each of the four samples. Include the three known compounds on the same graph. Prepare a second graph for your unknown compound. Include the boiling point for each compound on the graph. The vapor pressure for the boiling points taken from the literature is 760.0 mm Hg. For the experimentally determined boiling point, the vapor pressure is the barometric pressure. Each student must independently generate their graphs.
It is suggested you use a graphing program (e.g., Excel) for your calculations and graphs. If you make your worksheets look like those in the lab manual, you can submit them in place of the Report Sheets in the manual (without having to copy all the data to the Report Sheet). However, you must turn in the Report Sheet (even if blank). If data is copied to the Report Sheet, you still need to turn in the worksheets with your graphs.
In the graphing program, add a linear line to each data set. Set the option to print the equation for the line and the R2 values (correlation coefficient). In your report, discuss how the slope is calculated from the equation, and use that slope to calculate ΔHvap.
For the sample calculation for ΔHvap you should show a sample calculation for the slope of one of the lines, even if you use the slope generated by the program.
Using the slope of the “best fit” line for each sample, calculate ΔHvap (kJ · mol21).
In your conclusion, report the value of ΔHvap for your unknown and discuss the trend in ΔHvap for the three knowns.
Equipment
Common Equipment
Chemicals
One of the following compounds:
Be careful to avoid burns from the ring, beaker, and open flame. Vapors from the organic unknowns can be irritating. Fume hoods should be on.
Your TA will assign you to a group for Part A—each student does a different known in the assigned set. Your TA will also distribute an unknown.
A. Determine temperature–volume data for the known compound.
B. Determine temperature–volume data for the unknown compound.
C. Determine the boiling point of the unknown compound.
Excess unknown compound and acetone are disposed in the beaker for organic waste, and the waste disposal sheet should be properly filled in. Your lab instructor will dispose of the total volume in the appropriate container.