Chemical kinetics is the study of the speed, or rate, of reactions. We know that some reactions happen faster than others. The addition of baking soda to vinegar produces a quick reaction that we see almost instantly. Contrarily, rust forming on our cars is a very slow reaction and not something that we will notice in minutes. It is often advantageous for scientists to know the speed of reactions. Pharmaceutical researchers, for example, must know how fast a drug will work when it enters the body. In this lab you will study chemical kinetics. We will use absorbance measurements to track the progress of a reaction as a function of time and determine a rate law and rate constant for a chemical reaction.
17.1 Connection to Lecture
The rate of a reaction is the change in concentration with a change in time. The rate generally depends on the concentration of reactants. The rate law is a mathematical expression of how the rate changes with changing concentration. For a general reaction represented below,
the rate law has the form
where square brackets indicate molar concentrations of reactants A and B
Values of x, y, and k can only be determined from experiment. Determining the values of x and y establishes the rate law. You will determine the rate law and the rate constant for a particular reaction in this experiment.
Conditions in this experiment allow us to study the effect of concentration of just one reactant on the rate.
The rate is the change in concentration with a change in time and can be expressed as
The negative sign arises because the concentration of A is decreasing (a negative change in concentration). What we are really interested in is the instantaneous change in concentration, which is the limit as the time interval Δt approaches zero. This is the derivative of [A] with respect to time.
17.2 Determining Rate Order
First Order
If x = 1, the above equation is a first-order rate law. Rearranging the first-order expression produces
Integration from time 0 to time t gives
where [A]t is the concentration of reactant A at time t and [A]0 is the concentration of A at time t = 0. This equation can be rearranged
so that it has the form of an equation of a straight line.
For a first-order process, a graph of the natural log of concentration of A at time t, ln [A]t, versus time, t, will be a straight line.
Question 17.1: For a first-order process, a graph of ln [A]t versus t will give a straight line. What is the slope and y-intercept of this line?
Second Order Similarly, a second-order rate of the form
can be written, rearranged, and integrated as follows.
Again, a rearrangement produces the form of an equation of a straight line.
A graph of (1/ [A]t) versus t is a second-order graph. It will be a straight line if the reaction is second order.
Question 17.2: What is the slope and y-intercept for a second-order plot?
Zero Order
In some cases, rate does not depend on concentration.
Rearrangement and integration here produce
A graph of concentration at time t versus time is a straight line for a zero-order reaction.
Question 17.3: What is the slope and y-intercept of the line for a zero-order plot?
17.3 Determining Rate Constant, k
If we consider a reaction that has one of these three rate laws, we can determine the rate law (the order with respect to A) by drawing zero-order, first-order, and second-order graphs. Only one of these graphs will be a straight line. The graph with the straight line establishes the order of the reaction and the rate law.
Once the rate law is established, the rate constant for the reaction can be determined from the same graph. Looking back at the linear integrated equation for each order, you will notice that the slope equals the negative of the rate constant, –k, for both a zero-order and first-order graph. For a second-order graph, slope = k. Graphical determination of the slope establishes the rate constant.
17.4 Reaction for This Lab
The reaction you are studying is between Cr3+ ion and dihydrogen ethylenediaminetetraacetate, H2EDTA2–, in aqueous solution. The reaction can be represented as follows.
Ethylenediaminetetraacetic acid is a large molecule with the structure shown below.
The four terminal hydrogen atoms, circled, are acidic; removal of two of them produces H2EDTA2−, the reactant in this experiment. The EDTA4− ion effectively wraps itself around a Cr3+ ion, bonding through four oxygen atoms (two on each end) and the two nitrogen atoms.
The effect of changing concentration of Cr3+ on the rate of the reaction will be studied. The rate of this reaction also depends on H2EDTA2− and H3O+ concentrations, but conditions are arranged so that you will not see that dependence. An approximately fifty times excess of H2EDTA2− is used so that its concentration is essentially constant. In addition, the excess H2EDTA2− will react with the hydronium ion produced in the reaction keeping the pH nearly constant.
Absorbance Measurements
In order to determine a rate law and rate constant, we must be able to measure concentration of a reactant or product during the course of the reaction, while it is changing. In this experiment, the chromium-containing reactant and product are different colors: Cr(H2O)63+ is rose and CrEDTA− is purple. A spectrophotometer can be used to measure the absorbance, A, which is directly proportional to concentration, c.
The proportionality constant is represented by εb where ε is the molar absorptivity and b is the path length of light through the solution. The relationship is known as Beer’s law.
Different colored species absorb at different wavelengths. We are using a wavelength of 545 nm, at which the CrEDTA− product absorbs strongly. Absorbance will increase during the course of the reaction as the CrEDTA− is produced.
The procedure has three parts:
Four solutions are prepared with different concentrations of Cr3+ ion. These will provide data for four determinations of the rate constant. Be sure to note time of mixing for each solution—this is time t = 0.
The absorbance is read for each solution at five-minute intervals. Temperature is held constant by placing cuvettes containing the solution in a water bath between readings. The temperature of the water bath is maintained between 24 and 25 degrees Celsius.
To determine absorbance at the completion of the reaction, a portion of each solution is heated for several minutes in a boiling water bath. The higher temperature increases the rate so that the reaction is complete in a relatively short time. Therefore the final concentration of the CrEDTA– product will be equal to the initial concentration of the Cr3+ reactant. The proportionality constant can then be determined from the slope of a Beer’s law graph.
17.5 Data Analysis
You should use a graphing program, e.g., Excel, for your calculations and graphs. Construct a table of your data, like the one shown on the last page of the report sheet, for each solution 1 through 4. Data of “Time” and “A” will be collected in lab, and the other columns of “[CrEDTA−]t,” “[Cr3+]t,” “ln [Cr3+]t” and “1/[Cr3+]t” will be calculated.
Four graphs will be constructed:
Beer’s Law (Graph 1)
In the four boiled solutions, the reaction has gone to completion so all of the chromium is present as the product, CrEDTA−. Calculate the final molar concentration of CrEDTA− by using molarity and volumes in the original solution, [Cr3+]0. This is a dilution calculation. Construct a Beer’s law plot by graphing absorbance (y-axis) versus concentration (x-axis) for these four solutions (Graph 1). Your line should go through the origin. Determine the slope of the line, m, which is equal to the proportionality constant, εb.
Use your Beer’s law graph and absorbance values to determine [CrEDTA−]t. This value is subtracted from total chromium to obtain concentration of unreacted chromium(III), [Cr3+]t, at each time.
Zero Order (Graph 2)
Construct a zero-order graph by plotting [Cr3+]t versus t for each solution. Include all four solution plots on the same graph. Draw a smooth curve through the points for each solution.
First Order (Graph 3)
Construct a first-order graph by plotting ln [Cr3+]t versus t for each solution. Include all four solution plots on the same graph. Draw a smooth curve or a straight line through the points for each solution.
Second Order (Graph 4)
Construct a second-order graph by plotting 1/[Cr3+]t versus t for each solution. Include all four solution plots on the same graph. Draw a smooth curve or a straight line through the points for each solution.
Select the type of graph (of graphs 3 or 4) for which the curve is most nearly a straight line. Use linear trendlines for each data set. Set the options to include the line equations and R2 values. However, do not use the R2 values to determine the reaction order. Instead, look at the lines on graphs 3 or 4 and choose the graph (order) for which the lines are the most parallel. Report this reaction order on your report sheet.
The Rate Constant
Use the graph you selected as your reaction order to determine the rate constant. The rate constant will be the slope of the line and should be the same for all four solutions. Calculate the average rate constant and average deviation. Include all of these on your report sheet.
If this experiment is performed in groups, recording of data is done together in the lab. ALL calculations, graphs, and other parts of the report must be completed individually.
Equipment
Chemicals
Common Equipment
Be careful to avoid burns from the ring, beaker, and the open flame. Salts of Cr3+ are toxic; be sure to wash your hands thoroughly. Goggles must be worn at all times.
Discussions with your peers and TA are encouraged as you proceed.
Table 17.1 Preparations of solutions.
All solutions containing Cr3+ ion must be collected and added to the inorganic salts waste beaker. Fill in the waste disposal sheet. Your lab instructor will dispose of the total volume in the appropriate container.
In this analysis you are constructing graphs for a zero-, first-, and second-order rate law. You will use this graph to determine the rate constant.