The Graded Naming Test (GNT) asks respondents to name objects in a set of 30 black-
Given μ = 20.4 and σ = 3.2, we can start by calculating standard error:
We then find the z values that mark off the most extreme 0.025 in each tail, which are −1.96 and 1.96. We calculate the lower end of the interval as:
Mlower = −z(σM) + Msample = −1.96(0.584) + 17.5 = 16.36
We calculate the upper end of the interval as:
Mupper = z(σM) + Msample = 1.96(0.584) + 17.5 = 18.64
The 95% confidence interval around the mean of 17.5 is [16.36, 18.64].
How can we calculate the 90% confidence interval for the same data? In this case, we find the z values that mark off the most extreme 0.05 in each tail, which are −1.645 and 1.645. We calculate the lower end of the interval as:
Mlower = −z(σM) + Msample = −1.645(0.584) + 17.5 = 16.54
We calculate the upper end of the interval as:
Mupper = z(σM) + Msample = 1.645(0.584) + 17.5 = 18.46
The 90% confidence interval around the mean of 17.5 is [16.54, 18.46].
What can we say about these two confidence intervals in comparison to each other? The range of the 95% confidence interval is larger than that of the 90% confidence interval. When calculating the 95% confidence interval, we are describing where we think a larger portion of our sample means will fall if we repeatedly select samples of this size from the same population (95% as opposed to 90%) so that we have a larger range within which those means are likely to fall.
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The Graded Naming Test (GNT) study has a population norm for adults in England of 20.4. Researchers found a mean for 30 Canadian adults of 17.5, and we assumed a standard deviation of adults in England of 3.2 (Roberts, 2003). How can we calculate effect size for these data?
The appropriate measure of effect size for a z statistic is Cohen’s d, which is calculated as:
Based on Cohen’s conventions, this is a large effect size.