The RNA molecule is likely to be single stranded. If the molecule were double stranded, we would expect nearly equal percentages of adenine and uracil and equal percentages of guanine and cytosine.
Because the DNA template strand is complementary to the RNA molecule, we would expect equal percentages of bases in DNA complementary to the RNA bases. Therefore, in the template strand of DNA, we would expect A = 42%, T = 23%, C = 14%, and G = 21%.
The RNA molecule would be complementary to the template strand, contain uracil, and be synthesized in an antiparallel fashion. The sequence would be
5′—AUAGGCGAUGCCA—
The RNA strand contains the same sequence as the nontemplate DNA strand, except that the RNA strand contains uracil in place of thymine.
The consensus sequence is identified by determining which nucleotide is used most frequently at each position. For the two nucleotides that occur at an equal frequency at the first position, both are listed at that position in the sequence and identified by a slash mark: T/A G C A A T T.
This mutation would probably affect the −10 consensus sequence, which would most likely decrease transcription.
This mutation could affect the binding of the sigma factor to the promoter, reducing or inhibiting transcription.
This mutation would be unlikely to have any effect on transcription.
This mutation would have little effect on transcription.
The large size of the dystrophin gene is probably due to the presence of many intervening sequences, or introns, within the coding region of the gene. Excision of the introns through RNA splicing yields the mature mRNA that encodes the dystrophin protein.