Jacob and Monod worked out the structure and function of the lac operon by analyzing mutations that affected lactose metabolism. To help define the roles of the different components of the operon, they used partial diploid strains of E. coli. The cells of these strains possessed two different DNA molecules: the full bacterial chromosome and an extra piece of DNA. Jacob and Monod created these strains by allowing conjugation to take place between two bacteria (see Chapter 7). In conjugation, a small circular piece of DNA (the F plasmid, see Chapter 7) is transferred from one bacterium to another. The F plasmid used by Jacob and Monod contained the lac operon, so the recipient bacterium became partly diploid, possessing two copies of the lac operon. By using different combinations of mutations on the bacterial and plasmid DNA, Jacob and Monod determined that some parts of the lac operon are cis acting (able to control the expression of genes only when on the same piece of DNA), whereas other parts are trans acting (able to control the expression of genes on other DNA molecules).
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STRUCTURAL-
Through the use of partial diploids, Jacob and Monod were able to establish that mutations at the lacZ and lacY genes were independent and usually affected only the product of the gene in which the mutation occurred. Partial diploids with lacZ+ lacY− on the bacterial chromosome and lacZ− lacY+ on the plasmid functioned normally, producing β-galactosidase and permease in the presence of lactose. (The genotype of a partial diploid is written by separating the genes on each DNA molecule with a slash: lacZ+ lacY−/lacZ− lacY+.) In this partial diploid, a single functional β-galactosidase gene (lacZ+) is sufficient to produce β-galactosidase; whether the functional β-galactosidase gene is coupled to a functional (lacY+) or a defective (lacY−) permease gene makes no difference. The same is true of the lacY+ gene.
REGULATOR-
Some of these mutations were constitutive mutations, causing the lac proteins to be produced all the time, whether lactose was present or not. Such mutations in the regulator gene were designated lacI−. The construction of partial diploids demonstrated that a lacI+ gene is dominant over a lacI− gene; a single copy of lacI+ (genotype lacI+/lacI−) was sufficient to bring about normal regulation of protein production. Furthermore, lacI+ restored normal control to an operon even if the operon was located on a different DNA molecule, showing that lacI+ can be trans acting. A partial diploid with genotype lacI+ lacZ−/lacI− lacZ+ functioned normally, synthesizing β-galactosidase only when lactose was present (Figure 12.9). In this strain, the lacI+ gene on the bacterial chromosome was functional, but the lacZ− gene was defective; on the plasmid, the lacI− gene was defective, but the lacZ+ gene was functional. The fact that a lacI+ gene could regulate a lacZ+ gene located on a different DNA molecule indicated to Jacob and Monod that the lacI+ gene product was able to operate on either the plasmid or the chromosome.
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Some lacI mutations isolated by Jacob and Monod prevented transcription from taking place even in the presence of lactose. These mutations were referred to as superrepressors (lacIs), because they produced defective repressors that could not be inactivated by an inducer. The lacIs mutations produced a repressor with an altered inducer-
OPERATOR MUTATIONS Jacob and Monod mapped a second set of constitutive mutations to a site adjacent to lacZ. These mutations occurred at the operator and were referred to as lacOc (“O” stands for operator and “c” for constitutive). The lacOc mutations altered the sequence of DNA at the operator so that the repressor protein was no longer able to bind to it. A partial diploid with genotype lacI+ lacOc lacZ+/lacI+ lacO+ lacZ+ exhibited constitutive synthesis of β-galactosidase, indicating that lacOc is dominant over lacO+.
Analyses of other partial diploids showed that the lacO gene is cis acting, affecting only genes on the same DNA molecule. For example, a partial diploid with genotype lacI+ lacO+ lacZ−/lacI+ lacOc lacZ+ was constitutive, producing β-galactosidase in the presence or absence of lactose (Figure 12.11a), but a partial diploid with lacI+ lacO+ lacZ+/lacI+ lacOc lacZ− produced β-galactosidase only in the presence of lactose (Figure 12.11b). In the constitutive partial diploid (lacI+ lacO+ lacZ−/lacI+ lacOc lacZ+; see Figure 12.11a), the lacOc mutation and the functional lacZ+ gene were present on the same DNA molecule, but in lacI+ lacO+ lacZ+/lacI+ lacOc lacZ− (see Figure 12.11b), the lacOc mutation and the functional lacZ+ gene were on different molecules. Thus, the lacOc mutation affects only genes to which it is physically connected, as is true of all operator mutations. Such mutations prevent the binding of a repressor protein to the operator and thereby allow RNA polymerase to transcribe genes on the same DNA molecule. However, they cannot prevent a repressor from binding to normal operators on other DNA molecules. Watch Animation 12.1 to observe the effects of different combinations of lacI and lacO mutations on the expression of the lac operon. TRY PROBLEM 26
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PROMOTER MUTATIONS Mutations affecting lactose metabolism have also been isolated at the promoter; these mutations, designated lacP−, interfere with the binding of RNA polymerase to the promoter. Because this binding is essential for the transcription of the structural genes, E. coli strains with lacP− mutations don’t produce lac proteins either in the presence or in the absence of lactose. Like operator mutations, lacP− mutations are cis acting and thus affect only genes on the same DNA molecule. The partial diploid lacI+ lacP+ lacZ+/lacI+ lacP− lacZ+ exhibits normal synthesis of β-galactosidase, whereas lacI+ lacP− lacZ+/lacI+ lacP+ lacZ− fails to produce β-galactosidase whether or not lactose is present.
For E. coli strains with the following lac genotypes, make a table and use a plus sign (+) to indicate the synthesis of β-galactosidase and permease and a minus sign (−) to indicate no synthesis of the proteins when lactose is absent and when it is present.
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Genotype of strain
lacI+ lacP+ lacO+ lacZ+ lacY+
lacI+ lacP+ lacOc lacZ− lacY+
lacI+ lacP− lacO+ lacZ+ lacY−
lacI+ lacP+ lacO+ lacZ− lacY−/lacI− lacP+ lacO+ lacZ+ lacY+
Solution Strategy
What information is required in your answer to the problem?
An indication of whether or not β-galactosidase and permease are produced by each genotype when lactose is present and when lactose is absent by placing a plus sign (+) or minus sign (−) for each enzyme and condition in the table.
What information is provided to help solve the problem?
The genotype of each strain.
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Solution Steps
Genotype of strain
lacI+ lacP+ lacO+ lacZ+ lacY+
lacI+ lacP+ lacOc lacZ− lacY+
lacI+ lacP− lacO+ lacZ+ lacY−
lacI+ lacP+ lacO+ lacZ− lacY−/lacI− lacP+ lacO+ lacZ+ lacY+
All the genes possess normal sequences, so the lac operon functions normally: when lactose is absent, the regulator protein binds to the operator and inhibits the transcription of the structural genes, and so β-galactosidase and permease are not produced. When lactose is present, some of it is converted into allolactose, which binds to the repressor and makes it inactive; the repressor does not bind to the operator, and so the structural genes are transcribed, and β-galactosidase and permease are produced.
The structural lacZ gene is mutated, so β-galactosidase will not be produced under any conditions. The lacO gene has a constitutive mutation, which means that the repressor is unable to bind to lacO, and so transcription takes place at all times. Therefore, permease will be produced in both the presence and the absence of lactose.
In this strain, the promoter is mutated, so RNA polymerase is unable to bind to it, and transcription does not take place. Therefore, β-galactosidase and permease are not produced under any conditions.
This strain is a partial diploid, which consists of two copies of the lac operon: one on the bacterial chromosome and the other on a plasmid. The lac operon represented in the upper part of the genotype has mutations in both the lacZ and the lacY genes, and so it is not capable of encoding β-galactosidase or permease under any conditions. The lac operon in the lower part of the genotype has a defective regulator gene, but the normal regulator gene in the upper operon produces a repressor that is capable of diffusing to other molecules (trans acting), so that it binds to the lower operon in the absence of lactose and inhibits transcription. Therefore, no β-galactosidase or permease is produced when lactose is absent. In the presence of lactose, the repressor cannot bind to the operator, and so the lower operon is transcribed and β-galactosidase and permease are produced.
Lactose absent | Lactose present | ||
---|---|---|---|
β-Galactosidase | Permease | β-Galactosidase | Permease |
− | − | + | + |
− | + | − | + |
− | − | − | − |
− | − | + | + |
Now try your own hand at predicting the outcome of different lac mutations by working Problem 24 at the end of the chapter.