For Exercises 17.1 and 17.2, see pages 17-3 to 17-4; for 17.3 and 17.4, see page 17-5; for 17.5 to 17.7, see page 17-8; for 17.8 to 17.10, see page 17-11; and for 17.11 to 17.13, see page 17-14.

Question 17.13

17.13 or .

The Minitab output in Figure 17.6 does not give the value of . The column labeled “-Value” provides similar information.

  1. Find the value under the heading “-Value” for the predictor LCONC. Verify that this value is simply the estimated coefficient divided by its standard error. This is a statistic that has approximately the standard Normal distribution if the null hypothesis (slope 0) is true.
  2. Show that the square of is . The two-sided -value for is the same as for .

17.13

(a) . (b) 64.16, which agrees with the output up to rounding error.