For Exercises 5.40 and 5.41, see page 269; and for 5.42 and 5.43, see page 271.
Unless stated otherwise in the exercise, use software to find the exact Poisson.
5.44 How many calls?
Calls to the customer service department of a cable TV provider are made randomly and independently at a rate of 11 per minute. The company has a staff of 20 customer service specialists who handle all the calls. Assume that none of the specialists are on a call at this moment and that a Poisson model is appropriate for the number of incoming calls per minute.
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5.45 EPL goals.
Refer to Example 5.20 (pages 271–272) in which we found that the total number of goals scored in a game is well modeled by the Poisson distribution. Compute the following probabilities without the aid of software.
5.45
(a) 0.0628. (b) 0.5229.
5.46 Email.
Suppose the average number of emails received by a particular employee at your company is five emails per hour. Suppose the count of emails received can be adequately modeled as a Poisson random variable. Compute the following probabilities without the aid of software.
5.47 Traffic model.
The number of vehicles passing a particular mile marker during 15-minute units of time can be modeled as a Poisson random variable. Counting devices show that the average number of vehicles passing the mile marker every 15 minutes is 48.7.
5.47
(a) 0.4450 (0.4247 using Normal). (b) . . (c) 0.4095 (0.3974 using Normal).
5.48 Flaws in carpets.
Flaws in carpet material follow the Poisson model with mean 0.8 flaw per square yard. Suppose an inspector examines a sample of carpeting measuring 1.25 yards by 1.5 yards.
5.49 Email, continued.
Refer to Exercise 5.46, where we learned that a particular employee at your company receives an average of five emails per hour.
5.49
(a) Poisson with . (b) 0.0703 (0.0571 using Normal).
5.50 Initial public offerings.
The number of companies making their initial public offering of stock (IPO) can be modeled by a Poisson distribution with a mean of 15 per month.
5.51 How many zeroes expected?
Refer to Example 5.21 (page 272). We would find 1099 of the observed counts to have a value of 0. Based on the provided information in the example, how many more observed zeroes are there in the data set than what the best-fitting Poisson model would expect?
5.51
184.
5.52 Website hits.
A “hit” for a website is a request for a file from the website’s server computer. Some popular websites have thousands of hits per minute. One popular website boasts an average of 6500 hits per minute between the hours of 9 A.M. and 6 P.M. Assume that the hits per hour are well modeled by the Poisson distribution. Some software packages will have trouble calculating Poisson probabilities with such a large value of .
5.53 Website hits, continued.
Refer to the previous exercise to determine the number of website hits in one hour. Use the Normal distribution to find the range in which we would expect 99.7% of the hits to fall.
5.53
Between 388126.5 and 391873.5.
5.54 Mishandled baggage.
In the airline industry, the term “mishandled baggage” refers to baggage that was lost, delayed, damaged, or stolen. In 2013, American Airlines had an average of 3.02 mishandled baggage per 1000 passengers.14 Consider an incoming American Airlines flight carrying 400 passengers. Let be the number of mishandled baggage.
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5.55 Calculator convenience.
Suppose that follows a Poisson distribution with mean .
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(a) .
(b)
(c) .
(d) .
5.56 Baseball runs scored.
We found in Example 5.20 (pages 271–272) that, in soccer, goal scoring is well described by the Poisson model. It will be interesting to investigate if that phenomenon carries over to other sports. Consider data on the number of runs scored per game by the Washington Nationals for the 2013 season. Parts (a) through (e) can be done with any software.
washnat