With an initial deposit of $100, the balance in a bank account after t years is dollars. Find the average rate of change over [0, 0.5] and [0, 1], then estimate the instantaneous rate of change at t = 0.5.
The average rate of change of f with respect to t is the ratio of the change in f(t) divided by the unit change in t.
The account balance f(t) is measured in dollarsJvMTWtHHPxcVgRd4iHmpHpAOkxQe6GvTNzwj4lqqJTw= and t is measured in yearsEFBAAtjIr6f0KWQKxGhjyzhRKP+ZNnARzqfy/+h/RGY=.
The average rate of change of y = f(t) over the interval [t0, t1] is given by the following.
Average rate of change =
Find the average rate of change over the interval [0, 0.5]. (Round your answers to two decimal places.)
For the interval [0.0, 0.5], let t0= 0 and t1 = ot+qaZUmHUo=.
In this case, f(t1) = 100*(iSba6t70dtA=)0.5 and f(t0) = 100*(iSba6t70dtA=)0
Thus the average rate of change is ogclm5qspRNIZA6hUagrKN0l3ew= dollars per year.
Find the average rate of change over the interval [0, 1]. (Round your answers to two decimal places.)
For the interval [0, 1], let t0= 0 and t1 = 0VV1JcqyBrI=.
In this case, f(t1) = 100*(iSba6t70dtA=)1 and f(t0) = 100*(iSba6t70dtA=)0
Thus the average rate of change is KGcZUYuIxHXTNi6IdrtiAh9Q02E= dollars per year.
Recall that the instantaneous rate of change at t = t0 is the limit of the average rates of change.
To estimate the instantaneous rate of change of the given problem, we calculate the average rate of change over smaller and smaller intervals to the nO/+DAdRVq+2oOvmzNgeN0ocEUKz3yEuOTAqpssC58Q= of t = ot+qaZUmHUo=
First calculate the average rate of change over three intervals to the left of t=0.5. (Round your answers to four decimal places.)
Interval | [0.49, 0.5] | [0.499, 0.500] | [0.4999, 0.5000] |
---|---|---|---|
Average rate of change | bECI2HMu3zb8FISFiyvzAg== | AqHQgaV4SHbsguD1jWG/hg== | HZJ3TiwmXftPFf5AM9MwDw== |
This table suggests the limit of the average rates of change as t approaches 0.5 from the left is approximately L1roKTQ32O/N3Yl8O0Zde3nASJA= dollars per year (rounded to two decimal places).
Now calculate the average rate of change over three intervals to the right of t=0.5. (Round your answers to four decimal places.)
Interval | [0.5, 0.51] | [0.5, 0.501] | [0.5, 0.5001] |
---|---|---|---|
Average rate of change | KM4Y0fTBDKXkN24kA9uYBg== | tOpUvmG3/QKqNS+t06QXwA== | BM6dDvGjjeFBDTN8BeDEVg== |
This table suggests the limit of the average rates of change as t approaches 0.5 from the right is approximately l097cUlDKsa+7APQBYli5GbNDSg= dollars per year (rounded to two decimal places).
Based on the previous questions, the instantaneous rate of change at t = 0.5 is approximately L1roKTQ32O/N3Yl8O0Zde3nASJA= dollars per year (rounded to two decimal places).