Problem Statement

2.5*rand(1,2)
2*5
{2,3}
rand(2,3)
rand(1,9)
2*10*10-2*10+2
(182-2)/10
2*2
round((2 + 18)/4,1)

The position of a particle moving in a straight line during a 10–second trip is cm. Find a time t at which the instantaneous velocity is equal to the average velocity for the entire trip.

 
Step 1

The average velocity, vavg, is the average rate of change of a position function s(t) over a time interval [t0, t1].

vavg is defined as

Question Sequence

Question 1

The average velocity of the given position function s(t) during the interval from t0 = 0 s to t1 = 10 seconds is

s(10) = cm

s(0) = cm

Incorrect
Correct

Question 2

vavg = cm/s.

Correct.
Incorrect.

 
Step 2

Question 3

The formula for the instantaneous velocity of a particle at time t is found by differentiating the position function s(t).

cm

s'(t) = ·t - cm/s

Correct.
Incorrect.

 
Step 3

Question 4

To find the time when the instantaneous velocity is equal to the average velocity, set s'(t) = vavg and solve for t.

s'(t) = vavg

4·t-2 = 18

t = seconds

(Rounded to one decimal place)

Correct.
Incorrect.