The stopping distance for an automobile is F(s) = 1.1s + 0.054s2 ft, where s is the speed in mph. Use the Linear Approximation to estimate the change in stopping distance per additional mph when s = $s1 and when s = $s2.
If the function F is differentiable at s = a and Δs is small, then the Linear Approximation of ΔF is
ΔF ≈ B3lCeNir/NfP3RILH6ECIWW8LigpGa3llhPc8T9XZeg=,
where Δs represents the change in s.
To use Linear Approximation to estimate the change in stopping distance per additional mph, ΔF, first we need to find F'($s1) and F'($s2).
Find F'($s1)Δs and F'($s2)Δs, respectively.
F(s) = 1.1s + 0.054s2
F'(s) = 1.1 + 0.108s ft/mph
F'($s1) = UFPfACDOxzX9rlDg ft/mph
F'($s2) = 2Og4UEB2nw1H7dPo ft/mph
(Round your answers to two decimal places.)
To estimate the change in stopping distance per additional mph, use Δs = 0VV1JcqyBrI= mph.
Compute F'($s1)Δs and F'($s2)Δs, respectively.
F'($s1)Δs = UFPfACDOxzX9rlDg
F'($s2)Δs = 2Og4UEB2nw1H7dPo
(Round your answers to two decimal places.)
Use the Linear Approximation to estimate ΔF at s = $s1 mph and at s = $s2 mph.
At s = $s1 mph, the change in stopping distance per additional mph is
ΔF ≈ UFPfACDOxzX9rlDg ft.
(Round your answer to two decimal places.)
At s = $s2 mph, the change in stopping distance per additional mph is
ΔF ≈ 2Og4UEB2nw1H7dPo ft.
(Round your answer to two decimal places.)