Problem Statement

{2,4,6,8}
{2,3,4,5}
2*2
round(1/(4-1),4)
round(sqrt(0.3333),4)
round(2*sqrt(0.5773*0.5773+1)-0.5773,3)
round(2*sqrt(3*3+1)-3,3)
round(max(1.732,3.325,2),3)
round(min(1.732,3.325,2),3)

Find the maximum and minimum values fo the function on the interval [0,3].

 
Step 1

Question Sequence

Question 1

A number c in the domain of f is called a critical point if f'(c) = or where f'(c).

Correct.
Incorrect.

Question 2

The extreme values (absolute maximum and absolute minimum) of a continuous function on a closed interval occur either at a of the function or at the of the closed interval.

Correct.
Incorrect.

 
Step 2

Thus, we need to find the critical points of and then compare the function values at these critical points with the function values at the endpoints of [0,3] to find the extreme values.

Question Sequence

Question 3

Find y'.

Thus, y' is defined for .

Correct.
Incorrect.

 
Step 3

Solve y' = 0 for [0.3] to find any critical points, c.

Question Sequence

Question 4

y' = 0

x2 =

(Round your answer to four decimal places.)

Correct.
Incorrect.

Question 5

Thus, the critical point on [0,3] that satisifes this equation is

c = .

(Round your answer to four decimal places.)

Correct.
Incorrect.

 
Step 4

Compare the values of at the critical point c = 0.5773 and the endpoints of [0,3]. The greatest value is the absolute maximum and the smallest value is the absolute minimum of y on [0,3]. (Round your answers to three decimal places.)

Question Sequence

Question 6

.

.

.

Correct.
Incorrect.

 
Step 5

Question Sequence

Question 7

The minimum value of the function is .

The maximum value of the function is .

(Round your answers to three decimal places.)

Correct.
Incorrect.