Problem Statement

{2,4,6,8}
{2,3,4,5}
8*8
round(1/(64-1),4)
round(sqrt(0.0159),4)
round(8*sqrt(0.1261*0.1261+1)-0.1261,3)
round(8*sqrt(2*2+1)-2,3)
round(max(7.937,15.889,8),3)
round(min(7.937,15.889,8),3)

Find the maximum and minimum values fo the function on the interval [0,2].

 
Step 1

Question Sequence

Question 1

A number c in the domain of f is called a critical point if f'(c) = or where f'(c).

Correct.
Incorrect.

Question 2

The extreme values (absolute maximum and absolute minimum) of a continuous function on a closed interval occur either at a of the function or at the of the closed interval.

Correct.
Incorrect.

 
Step 2

Thus, we need to find the critical points of and then compare the function values at these critical points with the function values at the endpoints of [0,2] to find the extreme values.

Question Sequence

Question 3

Find y'.

Thus, y' is defined for .

Correct.
Incorrect.

 
Step 3

Solve y' = 0 for [0.2] to find any critical points, c.

Question Sequence

Question 4

y' = 0

x2 =

(Round your answer to four decimal places.)

Correct.
Incorrect.

Question 5

Thus, the critical point on [0,2] that satisifes this equation is

c = .

(Round your answer to four decimal places.)

Correct.
Incorrect.

 
Step 4

Compare the values of at the critical point c = 0.1261 and the endpoints of [0,2]. The greatest value is the absolute maximum and the smallest value is the absolute minimum of y on [0,2]. (Round your answers to three decimal places.)

Question Sequence

Question 6

.

.

.

Correct.
Incorrect.

 
Step 5

Question Sequence

Question 7

The minimum value of the function is .

The maximum value of the function is .

(Round your answers to three decimal places.)

Correct.
Incorrect.