Chapter 1. Binomial Mean and Standard Deviation

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Questions 1-4

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Question 1.1

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Correct. The mean (expected value) is μ = np = 25*0.23.
Incorrect. The mean (expected value) is μ = np = 25*0.23.
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Question 1.2

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Correct.The standard deviation is \(\sigma = \sqrt{25*0.23*(1-0.23)} = \sqrt{4.4275} \).
Incorrect. The standard deviation is \(\sigma = \sqrt{25*0.23*(1-0.23)} = \sqrt{4.4275} \).
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Question 1.3

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Correct.The mean (expected value) is μ = np = 1036*0.54.
Incorrect. The mean (expected value) is μ = np = 1036*0.54.
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Question 1.4

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Correct. The standard deviation is \(\sigma = \sqrt{1036*0.54*(1-0.54)} = \sqrt{257.3424} \).
Incorrect. The standard deviation is \(\sigma = \sqrt{1036*0.54*(1-0.54)} = \sqrt{257.3424} \).
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Questions 5-6

5:56

Question 1.5

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Correct. Because p is larger than 0.5 and n is fairly small, we will expect a somewhat left-skewed shape.
Incorrect. Because p is larger than 0.5 and n is fairly small, we will expect a somewhat left-skewed shape.
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Question 1.6

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Correct. In this case, we have a small value of p, but a large n. Here, we will expect a bell-shaped, symmetric distribution.
Incorrect. In this case, we have a small value of p, but a large n. Here, we will expect a bell-shaped, symmetric distribution.
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