Graph the equation x2=16y.
Solution The graph of x2=16y is a parabola of the form x2=4ay
where a=4. Look at Figure 37(c). The graph will open up, with focus at(0,4). The vertex is at (0,0). To graph the parabola, we let y=a; that is, let y=4. (Any other positive number will also work.) x2=16y=↑y=a=416(4)=64x=−8 or x=8
The points(−8,4) and(8,4) are on the parabola and establish its opening. See Figure 38.
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