Approximate ln2 using the first three terms of (7). Approximate ln3 using the first three terms of (7).
Solution (a) In (7), we let N=1 and use the first three terms of the series; then ln2≈2[13+13(13)3+15(13)5]≈0.693004
(The first three terms of this series approximates ln2 correct to within 0.001.)
(b) To find ln3, let N=2 and use ln2=0.693004 in (7). ln3≈ln2+2[15+13(15)3+15(15)5]≈0.693004+2[15+13(15)3+15(15)5]≈1.098465