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Table 3:
TABLE 3
θ
r
=
3
+
2
cos
θ
(
r
,
θ
)
0
3
+
2
(
1
)
=
5
(
5
,
0
)
π
3
3
+
2
(
1
2
)
=
4
(
4
,
π
3
)
π
2
3
+
2
(
0
)
=
3
(
3
,
π
2
)
2
π
3
3
+
2
(
−
1
2
)
=
2
(
2
,
2
π
3
)
π
3
+
2
(
−
1
)
=
1
(
1
,
π
)
4
π
3
3
+
2
(
−
1
2
)
=
2
(
2
,
4
π
3
)
3
π
2
3
+
2
(
0
)
=
3
(
3
,
3
π
2
)
5
π
3
3
+
2
(
1
2
)
=
4
(
4
,
5
π
3
)
2
π
3
+
2
(
1
)
=
5
(
5
,
2
π
)
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