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CHAPTER 6 PROJECTDetermining the Amount of Concrete Needed for a Cooling Tower

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A common design for cooling towers is modeled by a branch of a hyperbola rotated about an axis. The design is used because of its strength and efficiency. Not only is the shape stronger than either a cone or cylinder, it takes less material to build. This shape also maximizes the natural upward draft of hot air without the need for fans.*

How much concrete is needed to build a cooling tower that has a base 460 ft wide that is 442ft below the vertex if the top of the tower is 310ft wide and 123ft above the vertex? Assume the walls are a constant 5in =0.42ft thick. See Figure 76.

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  1. Show that the equation of the right branch of the hyperbola in Figure 76 is given by x=g2(y)=a2+by2

    where a=147 and b=0.16.

  1. Find the volume of the solid of revolution obtained by revolving the area enclosed by x=g2(y) from y=442 to y=123 about the y-axis.

  1. Using the fact that the walls are 0.42ft thick, show that the equation of the interior hyperbola is given by x=g1(y)=q2+ry2

    where q=146.58 and r=0.16. See Figure 77.

  1. Find the volume of the solid of revolution obtained by revolving the area enclosed by x=g1(y) from y=442 to y=123 about the y-axis.

  1. Now determine the volume (in cubic feet) of concrete required for the cooling tower.

  1. Do an Internet search to find the cost of concrete. How much will the concrete used in the cooling tower cost?

  1. Write a report for an audience that is not familiar with cooling towers summarizing the findings in Problems 1–6.

For pictures of the cooling towers and power plant, as well as a time-lapse video of the towers being built, log onto https://www.dom.com/about/stations/fossil/brayton-point-power-station.jsp

*The design of an unsupported, reinforced concrete hyperbolic cooling tower was patented in 1918 (UK patent 198,863) by Frederic von Herson and Gerard Kupeers of the Netherlands.

Source: Excerpts from The Providence Journal, Frieda Squires, May 2010.