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7.1 Assess Your Understanding

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Concepts and Vocabulary

  1. True or False Integration by parts is based on the Product Rule for derivatives.

True

  1. The integration by parts formula states that udv= ______.

uvvdu

Skill Building

In Problems 3–30, use integration by parts to find each integral.

  1. xe2xdx

12xe2x14e2x+C

  1. xe3xdx

  1. xcosx dx

xsinx+cosx+C

  1. xsin(3x) dx

  1. xlnx dx

23x3/2 lnx49x3/2+C

  1. x2lnx dx

  1. cot1x dx

xcot1x+12ln(x2+1)+C

  1. sin1x dx

  1. (lnx)2dx

x(lnx)22xlnx+2x+C

  1. x(lnx)2dx

  1. x2sinx dx

x2cosx+2xsinx+2cosx+C

  1. x2cosx dx

  1. xcos2x dx

12xcosxsinx+14x214sin2x+C

  1. xsin2x dx

  1. xsinhx dx

xcoshxsinhx+C

  1. xcoshx dx

  1. cosh1x dx

xcosh1xx21+C

  1. sinh1x dx

  1. sin(lnx) dx

x2[sin(lnx)cos(lnx)]+C

  1. cos(lnx) dx

  1. (lnx)3dx

x(lnx)33x(lnx)2+6xlnx6x+C

  1. (lnx)4dx

  1. x2(lnx)2dx

13x3(lnx)229x3lnx+227x3+C

  1. x3(lnx)2dx

  1. x2tan1x dx

13x3tan1x16x2+16ln(1+x2)+C

  1. xtan1x dx

  1. 7xx dx

7xxln77x(ln7)2+C

  1. 2xx dx

In Problems 31–38, use integration by parts to find each definite integral.

  1. π0excosx dx

eπ+12

  1. 10x2exdx

  1. 20x2e3xdx

2275027e6

  1. π/40xtan2x dx

  1. 91lnxdx

9ln34

  1. 3π/4π/4xcsc2x dx

  1. e1(lnx)2dx

e2

  1. π/40xsec2x dx

Applications and Extensions

Area Between Two Graphs In Problems 39 and 40, find the area of the region enclosed by the graphs of f and g.

  1. f(x)=3lnx and g(x)=xlnx,x1

92ln34

  1. f(x)=4xlnx and g(x)=x2lnx,x1

  1. Area Under a Graph Find the area under the graph of y=exsinx from 0 to π.

eπ+12

  1. Volume of a Solid of Revolution Find the volume of the solid of revolution generated by revolving the region bounded by the graph of y=cosx and the x-axis from x=0 to x=π2 about the y-axis. See the figure below.

  1. Volume of a Solid of Revolution Find the volume of the solid of revolution generated by revolving the region bounded by the graph of y=sinx and the x-axis from x=0 to x=π2 about the y-axis.

2π

  1. Volume of a Solid of Revolution Find the volume of the solid of revolution generated by revolving the region bounded by the graph of y=xsinx and the x-axis from x=0 to x=π2 about the x-axis.

479

  1. Volume of a Solid of Revolution Find the volume of the solid of revolution generated by revolving the region bounded by the graph of y=lnx and the x-axis from x=1 to x=e about the x-axis.

eπ2π

  1. Area

    1. (a) Graph the functions f(x)=x3e3x and g(x)=x2e3x on the same set of coordinate axes.
    2. (b) Find the area enclosed by the graphs of f and g.
  1. Damped Spring The displacement x of a damped spring at time t, 0t5, is given by x=x(t)=3etcos(2t)+2etsin(2t).

    1. (a) Graph x=x(t).
    2. (b) Find the least positive number t that satisfies x(t)=0.
    3. (c) Find the area under the graph of x=x(t) from t=0 to the value of t found in (b).

  1. (a)
  2. (b) π2+12tan1(32)
  3. (c) 1.890
  1. A function y=f(x) is continuous and differentiable on the interval (2,6). If 53f(x) dx=18 and f(3)=8 and f(5)=11, then find 53xf(x) dx.

In Problems 49–54, find each integral by first making a substitution and then integrating by parts.

  1. sinxdx

2sinx2xcosx+C

  1. exdx

  1. cosxln(sinx) dx

(sinx)ln(sinx)sinx+C

  1. exln(2+ex)dx

  1. e4xcose2xdx

12e2xsine2x+12cose2x+C

  1. cosxtan1(sinx) dx

  1. Find x3ex2dx. (Hint: Let u=x2,dv=xex2dx.)

12x2ex212ex2+C

  1. Find xnlnx dx; n1, n real.

  1. Find xexcosx dx.

12ex(xsinx+xcosxsinx)+C

  1. Find xexsinx dx.

In Problems 59–62, derive each reduction formula where n>1 is an integer.

  1. xnsin1xdx=xn+1n+1sin1x1n+1xn+11x2dx

See the Student Solutions Manual.

  1. dx(x2+1)n+1=(112n)dx(x2+1)n+x2n(x2+1)n

  1. sinnx dx=sinn1xcosxn+n1nsinn2xdx

See the Student Solutions Manual.

  1. sinnxcosmx dx=sinn1xcosm+1xn+m+n1n+msinn2xcosmxdx

    where mn, m1

    1. (a) Find x2e5xdx.
    2. (b) Using integration by parts, derive a reduction formula for xnekxdx, where k0 and n2 is an integer, in which the resulting integrand involves xn1.

  1. (a) 15x2e5x225xe5x+2125e5x+C
  2. (b) xnekxdx=1kxnekxnkxn1ekxdx
    1. (a) Assuming there is a function p for which x3exdx =p(x)ex, show that p(x)+p(x)=x3.
    2. (b) Use integration by parts to find a polynomial p of degree 3 for which x3exdx=p(x)ex+C.
    1. (a) Use integration by parts with u=sinx and dv=cosxdx to find a function f for which sinxcosx dx=f(x)+C1.
    2. (b) Use integration by parts with u=cosx and dv=sinxdx to find a function g for which sinxcosx dx=g(x)+C2.
    3. (c) Use the trigonometric identity sin(2x)=2sinxcosx and substitution to find a function h for which sinxcosx dx=h(x)+C3.
    4. (d) Compare the functions f and g. Find a relationship between C1 and C2.
    5. (e) Compare the functions f and h. Find a relationship between C1 and C3.

  1. (a) f(x)=12sin2x
  2. (b) g(x)=12cos2x
  3. (c) h(x)=14cos(2x)
  4. (d) C2=12+C1
  5. (e) C3=14+C1
  1. Derive the formula ln(x+x2+a2)dx=xln(x+x2+a2)x2+a2+C

  1. Derive the formula eaxsin(bx) dx=eax[asin(bx)bcos(bx)]a2+b2+C,a>0,b>0

See the Student Solutions Manual.

  1. Suppose F(x)=x0tg(t)dt for all x0. Show that F(x)= xg(x)x0g(t)dt.

  1. Use Wallis’ formulas, given below, to find each definite integral.

    • π/20sinnx dx=π/20cosnx dx n>1 an integer ={(n1)(n3)(4)(2)n(n2)(5)(3)(1)n>1 is odd(n1)(n3)(5)(3)(1)n(n2)(4)(2)(π2)n>1 is even
    1. (a) π/20sin6x dx
    2. (b) π/20sin5x dx
    3. (c) π/20cos8x dx
    4. (d) π/20cos6x dx

  1. (a) 5π32
  2. (b) 815
  3. (c) 35π256
  4. (d) 5π32

Challenge Problems

  1. Derive Wallis’ formulas given in Problem 69. (Hint: Use the result of Problem 61.)

    1. (a) If n is a positive integer, use integration by parts to show that there is a polynomial p of degree n for which xnexdx=p(x)ex+C

      480

    2. (b) Show that p(x)+p(x)=xn.
    3. (c) Show that p can be written in the form p(x)=nk=0(1)kn!(nk)!xnk

See the Student Solutions Manual.

  1. Show that for any positive integer n, 10ex2dx=e[123+4158105++(1)n2n(2n+1)(2n1)31]+(1)n+12n+1(2n+1)(2n1)3110x2n+2ex2dx

  1. Use integration by parts to show that if f is a polynomial of degree n1, then f(x)exdx=g(x)ex+C for some polynomial g(x) of degree n.

See the Student Solutions Manual.

  1. Start with the identity f(b)f(a)=baf(t)dt and derive the following generalizations of the Mean Value Theorem for Integrals:

    • (a) f(b)f(a)=f(a)(ba)baf(t)(tb)dt
    • (b) f(b)f(a)=f(a)(ba)+f(a)2(ba)2+baf(t)2(tb)2dt
  1. If y=f(x) has the inverse function given by x=f1(y), show that baf(x)dx+f(b)f(a)f1(y)dy=bf(b)af(a)

See the Student Solutions Manual.

    1. (a) When integration by parts is used to find excoshx dx, what happens? Explain.
    2. (b) Find excoshx dx without using integration by parts.