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Concepts and Vocabulary
The area A of the sector of a circle of radius r and central angle θ is A= ______________.
θr22
True or False The area enclosed by the graph of a polar equation and two rays that have the pole as a common vertex is found by approximating the area using sectors of a circle.
True
True or False The area A enclosed by the graph of the equation r=f(θ), r≥0, and the rays θ=α and θ=β, is given by A=∫βαf(θ)dθ.
False
True or False If x(θ)=rcosθ, y(θ)=rsinθ are parametric equations of the polar equation r=f(θ), then (dxdθ)2+(dydθ)2=r2+(drdθ)2.
True
Skill Building
In Problems 5–8, find the area of the shaded region.
r=cos(2θ)
π4
r=2sin(3θ)
r=2+2sinθ
8+3π
r=3−3cosθ
In Problems 9–12, find the area of the region enclosed by the graph of each polar equation swept out by the given rays.
r=3cosθ;θ=0toθ=π3
316(3√3+4π)
r=3sinθ;θ=0toθ=π4
r=aθ;θ=0 to θ=2π
4π3a23
r=eaθ;θ=0 to θ=π2
In Problems 13–18, find the area of the region enclosed by the graph of each polar equation.
r=1+cosθ
3π2
r=2−2sinθ
r=3+sinθ
19π2
r=3(2−sinθ)
r=8sin(3θ)
16π
r=cos(4θ)
In Problems 19–22, find the area of the region enclosed by one loop of the graph of each polar equation.
r=4sin(2θ)
2π
r=5cos(3θ)
r2=4cos(2θ)
2
r=a2cos(2θ)
In Problems 23–26, find the area of each region described.
Inside r=2sinθ; outside r=1
√32+π3
Inside r=4cosθ; outside r=2
Inside r=sinθ; outside r=1−cosθ
1−π4
Inside r2=4cos(2θ); outside r=√2
In Problems 27–30, find the surface area of the solid of revolution generated by revolving each curve about the polar axis.
r=sinθ,0≤θ≤π2
π22
r=1+cosθ,0≤θ≤π
r=eθ,0≤θ≤π
25√2(1+e2π)π
r=2acosθ,0≤θ≤π2
Applications and Extensions
In Problems 31–48, find the area of the region:
enclosed by the small loop of the limaçon r=1+2cosθ.
π−3√32
enclosed by the small loop of the limaçon r=1+2sinθ.
684
enclosed by the loop of the graph of r=2−secθ.
√3+4π3−4ln(2+√3)
enclosed by the loop of the graph of r=5+secθ.
enclosed by r=2sin2θ2.
3π2
enclosed by r=6cos2θ.
inside the circle r=8cosθ and to the right of the line r=2secθ.
4√3+32π3
inside the circle r=10sinθ and above the line r=2cscθ.
outside the circle r=3 and inside the cardioid r=2+2cosθ.
9√32−π
inside the circle r=sinθ and outside the cardioid r=1+cosθ.
common to the circle r=cosθ and the cardioid r=1−cosθ.
7π12−√3
common to the circles r=cosθ and r=sinθ.
common to the inside of the cardioid r=1+sinθ and the outside of the cardioid r=1+cosθ.
2√2
common to the inside of the lemniscate r2=8cos(2θ) and the outside of the circle r=2.
enclosed by the rays θ=0 and θ=1 and r=e−θ, 0≤θ≤1.
1−e−24
enclosed by the rays θ=0 and θ=1 and r=eθ, 0≤θ≤1.
enclosed by the rays θ=1 and θ=π and r=1θ, 1≤θ≤π.
π−12π
inside the outer loop but outside the inner loop of r=1+2sinθ.
Area Find the area of the loop of the graph of r=secθ+2.
√3+4π3−4 ln(2+√3)
Surface Area of a Sphere Develop a formula for the surface area of a sphere of radius R.
Surface Area of a Bead A sphere of radius R has a hole of radius a<R drilled through it. See the figure. The axis of the hole coincides with a diameter of the sphere.
Surface Area of a Plug A plug is made to repair the hole in the sphere in Problem 51.
Area Find the area enclosed by the loop of the strophoid r=secθ−2cosθ,−π2<θ<π2 as shown in the figure.
2−π2
Area
Challenge Problems
Show that the area enclosed by the graph of rθ=a and the rays θ=θ1 and θ=θ2 is proportional to the difference of the radii, r1−r2, where r1=aθ1 and r2=aθ2.
See Student Solutions Manual.
Find the area of the region that lies outside the circle r=1 and inside the rose r=3sin(3θ).
Find the area of the region that lies inside the circle r=2 and outside the rose r=3sin(2θ).
2√5−sin−1(23)