(a) C; (b) B and F; (c) G; (d) F; (e) E; (f) H; (g) I; (h) D; (i) A; (j) F; (k) B
The oxidative phase generates NADPH and is irreversible. The nonoxidative phase allows for the interconversion of phosphorylated sugars.
Glucose 6-
When much NADPH is required. The oxidative phase of the pentose phosphate pathway is followed by the nonoxidative phase. The resulting fructose 6-
Fava beans contain vicine, a purine glycoside that can lead to the generation of peroxides—
C27
The nonoxidative phase of the pentose phosphate pathway can be used to convert three molecules of ribose 5-
The conversion of fructose 6-
The label emerges at C-
Because red blood cells do not have mitochondria and the only means to obtain NADPH is through the pentose phosphate pathway. There are biochemical means to convert mitochondrial NADH into cytoplasmic NADPH.
The Calvin cycle begins with the fixation of CO2 and proceeds to use NADPH in the synthesis of glucose. The pentose phosphate pathway begins with the oxidation of a glucose-
The oxidative decarboxylation of isocitrate to α-ketoglutarate
Lacking mitochondria, red blood cells metabolize glucose to lactate to obtain energy in the form of ATP. The CO2 results from extensive use of the pentose phosphate pathway coupled with gluconeogenesis. This coupling allows the generation of much NADPH with the complete oxidation of glucose by the oxidative branch of the pentose phosphate pathway.
C-
ΔE′0 for the reduction of glutathione by NADPH is +0.09 V. Hence ΔG°′ is −17.4 kJ mol−1 (−4.2 kcal mol−1), which corresponds to an equilibrium constant of 1126. The required [NADPH]/[NADP+] ratio is 8.9 × 10−5.
Incubate an aliquot of a tissue homogenate with glucose labeled with 14C at C-