1. Like salt and pepper. Match the terms with the descriptions. ✓ 4
Primary messenger Second messenger G- Heterotrimeric G- Gαs Protein kinase A cAMP phosphodiesterase GTPase activity Cholera Pertussis Phospholipase C Gaq Inositol trisphosphate Protein kinase C | Composed of seven transmembrane helices Activates phospholipase C Generates two second messengers Stimulated by cAMP Results from Gαi inhibition Activates a Ca2+ channel Results in the inactivation of protein kinase A Results in the reassociation of Gα and Gβγ Activates adenylate cyclase Activated by diacylglycerol Due to persistent stimulation of Gαs Intracellular chemical that relays message from ligand receptor complex Activated by 7TM receptor Message received by the cell |
2. Class differences. What are the three major classes of membrane receptors? ✓ 5
3. Magnification. Explain how a small number of hormones binding to the extracellular surface of a cell can have a large biochemical effect inside the cell. ✓ 4
4. Common properties. What are some of the structural features common to all membrane-
5. On–
6. Specificity. Hormones affect the biochemistry of a distinct set of tissues. What accounts for the tissue specificity of hormone action? ✓ 4
7. Like peanut butter and jelly. Match the terms with the descriptions.
Growth hormone binding Growth hormone receptor Receptor tyrosine kinase Grb- Sos Ras IRS Phosphoinositide kinase PIP3-activated kinase Akt | Dimerization results in cross- Binds IRS and forms IP3 Activates JAK Binds receptor tyrosine kinase and Sos Activates Akt Causes receptor dimerization Adaptor protein in insulin signaling pathway Promotes movement of glucose transporters to the cell membrane Activates Ras Small G- |
8. Chimeras. In an elegant experiment on the nature of receptor tyrosine kinase signaling, a gene was synthesized that encoded a chimeric receptor—the extracellular part came from the insulin receptor, and the membrane-
9. Antibodies mimicking hormones. An antibody has two identical antigen-
10. Alike but different. What is the difference between heterotrimeric G proteins and small G proteins? ✓ 4
11. Facile exchange. A mutated form of the a subunit of the heterotrimeric G protein has been identified; this form readily exchanges GDP for GTP even in the absence of an activated receptor. What would be the effect on a signaling pathway containing the mutated a subunit?
12. Diffusion rates. Normally, rates of diffusion vary inversely with molecular weights; so smaller molecules diffuse faster than do larger ones. In cells, however, calcium ion diffuses more slowly than does cAMP. Propose a possible explanation.
13. Awash with glucose. Glucose is mobilized for ATP generation in muscle in response to epinephrine, which activates Gαs. Cyclic AMP phosphodiesterase is an enzyme that converts cAMP into AMP. How would inhibitors of cAMP phosphodiesterase affect glucose mobilization in muscle? ✓ 4
14. Many defects. Considerable effort has been directed toward determining the genes in which sequence variation contributes to the development of type 2 diabetes, a disease that results from a loss of sensitivity of cells to insulin. Approximately 800 genes have been implicated. Explain the significance of this observation.
15. Growth-
16. Different genes. Differentiate among a proto-
17. Accelerator and brake. Only one copy of a proto-
18. Redundancy. Because of the high degree of genetic variability in tumors, typically no single anticancer therapy is universally effective for all patients, even within a given tumor type. Hence, it is often desirable to inhibit a particular pathway at more than one point in the signaling cascade. In addition to the EGFR-
19. A reappearance. Ligand-
20. Molecular exposure. The binding of Ca2+ to calmodulin induces substantial conformational changes in its EF hands, exposing hydrophobic residues on the surface of the protein. How might this structural change help to propagate the calcium signal?
21. Making connections. Suppose that you were investigating a newly discovered growth-
22. Vive la difference. Why is the fact that a monomeric hormone binds to two identical receptor molecules, thus promoting the formation of a dimer of the receptor, considered remarkable? ✓ 5
23. Active mutants. Some protein kinases are inactive unless they are phosphorylated on key serine or threonine residues. In some cases, active enzymes can be generated by mutating these serine or threonine residues to glutamate. Explain.
24. Signal-
25. Receptor truncation. You prepare a cell line that overexpresses a mutant form of EGFR in which the entire intracellular region of the receptor has been deleted. Predict the effect of overexpression of this construct on EGF signaling in this cell line. ✓ 5
26. Total amplification. Suppose that each β-adrenergic receptor bound to epinephrine converts 100 molecules of Gαs into their GTP-
27. Establishing specificity. You wish to determine the hormone-
(a) What concentrations of each hormone yield 50% maximal binding?
(b) Which hormone shows the highest binding affinity for the receptor?
You next wish to determine whether the hormone–
(a) What is the relation between the binding affinity of the hormone–
(b) Suggest experiments that would determine whether a Gαs protein is a component of the signal-
28. Binding matters. A scientist wishes to determine the number of receptors specific for a ligand X, which he has in both radioactive and nonradioactive form. In one experiment, he adds increasing amounts of the radioactive X and measures how much of it is bound to the cells. The result is shown as total activity in the adjoining graph. Next, he performs the same experiment, except that he includes a several hundredfold excess of nonradioactive X. This result is shown as nonspecific binding. The difference between the two curves is the specific binding.
(a) Why is the total binding not an accurate representation of the number of receptors on the cell surface?
(b) What is the purpose of performing the experiment in the presence of excess nonradioactive ligand?
(c) What is the significance of the fact that specific binding attains a plateau?
29. Counting receptors. With the use of experiments such as those described in problems 27 and 28, the number of receptors in the cell membrane can be calculated. Suppose that the specific activity of the radioactive ligand is 1012 counts per minute (cpm) per millimole and that the maximal specific binding is 104 cpm per milligram of membrane protein. There are 1010 cells per milligram of membrane protein. Assume that one ligand binds per receptor. Calculate the number of receptor molecules present per cell.
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