Preliminary Questions
Describe the shape of the curve \(x=3\cos t, y = 3\sin t\).
How does \(x=4+3\cos t, y = 5+3\sin t\) differ from the curve in the previous question?
What is the maximum height of a particle whose path has parametric equations \(x = t^9\), \(y = 4-t^2\)?
Can the parametric curve \((t, \sin t)\) be represented as a graph \(y=f(x)\)? What about \((\sin t, t)\)?
Match the derivatives with a verbal description:
Exercises
Find the coordinates at times \(t = 0\), 2, 4 of a particle following the path \(x=1+t^3\), \(y =9-3t^2\).
Find the coordinates at \(t = 0, \frac{\pi}4, \pi\) of a particle moving along the path \(c(t)=(\cos 2t, \sin^2t)\).
Show that the path traced by the bullet in Example 3 is a parabola by eliminating the parameter.
Use the table of values to sketch the parametric curve \((x(t),y(t))\), indicating the direction of motion.
\(t\) | -3 | -2 | -1 | 0 | 1 | 2 | 3 |
\(x\) | -15 | 0 | 3 | 0 | -3 | 0 | 15 |
\(y\) | 5 | 0 | -3 | -4 | -3 | 0 | 5 |
Graph the parametric curves. Include arrows indicating the direction of motion.
Give two different parametrizations of the line through \((4,1)\) with slope \(2\).
In Exercises 7–14, express in the form \(y=f(x)\) by eliminating the parameter.
\(x = t+3,\quad y = 4t\)
\(x = t^{-1},\quad y=t^{-2}\)
\(x = t,\quad y=\tan^{-1}(t^3+e^t)\)
\(x = t^2,\quad y = t^3 + 1\)
\(x = e^{-2t},\quad y = 6e^{4t}\)
\(x = 1 + t^{-1},\quad y = t^2\)
\(x = \ln t,\quad y = 2 - t\)
\(x = \cos t,\quad y = \tan t\)
In Exercises 15–18, graph the curve and draw an arrow specifying the direction corresponding to motion.
\(x=\frac12 t,\quad y = 2t^2\)
\(x=2+4t,\quad y = 3+2t\)
\(x=\pi t,\quad y = \sin t\)
\(x=t^2,\quad y = t^3\)
Match the parametrizations (a)–(d) below with their plots in Figure 11.14, and draw an arrow indicating the direction of motion.
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A particle follows the trajectory \[x(t) = \dfrac14 t^3 + 2t,\qquad y(t) = 20t - t^2 \] with \(t\) in seconds and distance in centimeters.
Find an interval of \(t\)-values such that \(c(t)=(\cos t, \sin t)\) traces the lower half of the unit circle.
Find an interval of \(t\)-values such that \(c(t)=(2t+1,4t-5)\) parametrizes the segment from \((0,-7)\) to \((7,7)\).
In Exercises 23–38, find parametric equations for the given curve.
\(y= 9-4x\)
\(y = 8x^2-3x\)
\(4x-y^2=5\)
\(x^2+y^2=49\)
\((x+9)^2+(y-4)^2=49\)
\(\Big(\frac{x}5\Big)^2 + \Big(\frac{y}{12}\Big)^2 = 1\)
Line of slope \(8\) through \((-4,9)\)
Line through \((2,5)\) perpendicular to \(y=3x\)
Line through \((3,1)\) and \((-5,4)\)
Line through \(\big(\frac13,\frac16\big)\) and \(\big(-\frac76,\frac53\big)\)
Segment joining \((1,1)\) and \((2,3)\)
Segment joining \((-3,0)\) and \((0,4)\)
Circle of radius 4 with center \((3,9)\)
Ellipse of Exercise 28, with its center translated to \((7,4)\)
\(y = x^2\), translated so that the minimum occurs at \((-4,-8)\)
\(y=\cos x\) translated so that a maximum occurs at \((3,5)\)
In Exercises 39–42, find a parametrization \(c(t)\) of the curve satisfying the given condition.
\(y=3x-4,\quad c(0)=(2,2)\)
\(y=3x-4,\quad c(3)=(2,2)\)
\(y=x^2,\quad c(0)=(3,9)\)
\(x^2+y^2=4,\quad c(0)=\big(\frac12,\frac{\sqrt{3}}2\big)\)
Describe \(c(t) = (\sec t, \tan t)\) for \(0\le t <\frac{\pi}2\) in the form \(y=f(x)\). Specify the domain of \(x\).
Find a parametrization of the right branch (\(x>0\)) of the hyperbola \[ \left(\dfrac{x}{a}\right)^2-\left(\dfrac{y}{b}\right)^2=1 \] using the functions \(\cosh t\) and \(\sinh t\). How can you parametrize the branch \(x<0\)?
The graphs of \(x(t)\) and \(y(t)\) as functions of \(t\) are shown in Figure 11.15. Which of (I)–(III) is the plot of \(c(t)=(x(t),y(t))\)? Explain.
Which graph, (I) or (II), is the graph of \(x(t)\) and which is the graph of \(y(t)\) for the parametric curve in Figure 11.16?
Sketch \(c(t) = (t^3 - 4t, t^2)\) following the steps in Example 7.
Sketch \(c(t) = (t^2 - 4t, 9 - t^2)\) for \(-4\le t \le 10\).
In Exercises 49–52, use Eq. (7) to find \(dy/dx\) at the given point.
\((t^3, t^2 - 1),\quad t = -4\)
\((2t+9, 7t-9),\quad t = 1\)
\((s^{-1}-3s, s^3),\quad s = -1\)
\((\sin 2\theta, \cos 3\theta),\quad \theta = \frac{\pi}6\)
In Exercises 53–56, find an equation \(y = f(x)\) for the parametric curve and compute \({dy}/dx\) in two ways: using Eq. (7) and by differentiating \(f(x)\).
\(c(t)=(2t+1, 1-9t)\)
\(c(t)=\bigl(\frac{1}{2}t, \frac14t^2 - t\bigr)\)
\(x = s^3,\quad y = s^6+s^{-3}\)
617
\(x = \cos \theta,\quad y = \cos\theta + \sin^2\theta\)
Find the points on the curve \(c(t) = (3t^2-2t,t^3-6t)\) where the tangent line has slope \(3\).
Find the equation of the tangent line to the cycloid generated by a circle of radius \(4\) at \(t=\frac{\pi}2\).
In Exercises 59–62, let \(c(t) = (t^2 - 9, t^2 - 8t)\) (see Figure 11.17).
Draw an arrow indicating the direction of motion, and determine the interval of \(t\)-values corresponding to the portion of the curve in each of the four quadrants.
Find the equation of the tangent line at \(t = 4\).
Find the points where the tangent has slope \(\frac12\).
Find the points where the tangent is horizontal or vertical.
Let \(A\) and \(B\) be the points where the ray of angle \(\theta\) intersects the two concentric circles of radii \(r<R\) centered at the origin (Figure 11.18). Let \(P\) be the point of intersection of the horizontal line through \(A\) and the vertical line through \(B\). Express the coordinates of \(P\) as a function of \(\theta\) and describe the curve traced by \(P\) for \(0\le \theta \le 2\pi\).
A 10-ft ladder slides down a wall as its bottom \(B\) is pulled away from the wall (Figure 11.19). Using the angle \(\theta\) as parameter, find the parametric equations for the path followed by (a) the top of the ladder \(A\), (b) the bottom of the ladder \(B\), and (c) the point \(P\) located 4 ft from the top of the ladder. Show that \(P\) describes an ellipse.
In Exercises 65–68, refer to the Bézier curve defined by Eqs. (8) and (9).
Show that the Bézier curve with control points \[ P_0 = (1, 4),\quad P_1 =(3, 12),\quad P_2 =(6, 15),\quad P_3 =(7, 4) \] has parametrization \[ c(t) = (1 + 6t + 3t^2 - 3t^3, 4 + 24t - 15t^2 - 9t^3) \] Verify that the slope at \(t=0\) is equal to the slope of the segment \(\overline{P_0P_1}\).
Find an equation of the tangent line to the Bézier curve in Exercise 65 at \(t = \frac13\).
Find and plot the Bézier curve \(c(t)\) passing through the control points \[ P_0 = (3, 2),\quad P_1 =(0, 2),\quad P_2 =(5,4),\quad P_3 =(2, 4) \]
Show that a cubic Bézier curve is tangent to the segment \(\overline{P_2P_3}\) at \(P_3\).
A bullet fired from a gun follows the trajectory \[ x = at,\qquad y = bt - 16t^2 \quad (a,b>0) \] Show that the bullet leaves the gun at an angle \(\theta = \tan^{-1}\big(\tfrac{b}{a}\big)\) and lands at a distance \({ab}/{16}\) from the origin.
Plot \(c(t)= (t^3 - 4t, t^4 - 12t^2 + 48)\) for \(-3\le t \le 3\). Find the points where the tangent line is horizontal or vertical.
Plot the astroid \(x = \cos^3\theta\), \(y = \sin^3\theta\) and find the equation of the tangent line at \(\theta =\frac{\pi}3\).
Find the equation of the tangent line at \(t=\frac{\pi}4\) to the cycloid generated by the unit circle with parametric equation (5).
Find the points with horizontal tangent line on the cycloid with parametric equation (5).
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Property of the Cycloid Prove that the tangent line at a point \(P\) on the cycloid always passes through the top point on the rolling circle as indicated in Figure 11.20. Assume the generating circle of the cycloid has radius 1.
A curtate cycloid (Figure 11.21) is the curve traced by a point at a distance \(h\) from the center of a circle of radius \(R\) rolling along the \(x\)-axis where \(h<R\). Show that this curve has parametric equations \(x = Rt - h \sin t\), \(y = R - h \cos t\).
Use a computer algebra system to explore what happens when \(h>R\) in the parametric equations of Exercise 75. Describe the result.
Show that the line of slope \(t\) through \((-1,0)\) intersects the unit circle in the point with coordinates \begin{equation} \label{12.exparam.parcir} x = \frac{1 - t^2}{t^2 + 1}, \qquad y = \frac{2t}{t^2 + 1}\tag{10} \end{equation}
Conclude that these equations parametrize the unit circle with the point \((-1,0)\) excluded (Figure 11.22). Show further that \(t = {y}/({x+1})\).
The folium of Descartes is the curve with equation \(x^3+y^3=3axy\), where \(a\ne 0\) is a constant (Figure 11.23).
Use the results of Exercise 78 to show that the asymptote of the folium is the line \(x+y=- a\). Hint: Show that \(\lim\limits_{t\to -1}(x+y)=-a\).
Find a parametrization of \(x^{2n+1}+y^{2n+1}=ax^ny^n\), where \(a\) and \(n\) are constants.
Second Derivative for a Parametrized Curve Given a parametrized curve \(c(t)=(x(t), y(t))\), show that \[ \frac{d}{dt}\Big(\frac{dy}{dx}\Big) = \frac{x'(t)y''(t)-y'(t)x''(t)}{x'(t)^2} \]
Use this to prove the formula \[ \boxed{\bbox[#fef7e5,5pt]{\frac{d^2y}{dx^2} = \frac{x'(t)y''(t)-y'(t)x''(t)}{x'(t)^3}}}\tag{11} \]
The second derivative of \(y=x^2\) is \({dy^2}{d^2x}=2\). Verify that Eq. (11) applied to \(c(t)=(t,t^2)\) yields \({dy^2}{d^2x}=2\). In fact, any parametrization may be used. Check that \(c(t)=(t^3,t^6)\) and \(c(t) = (\tan t,\tan^2 t)\) also yield \({dy^2}{d^2x}=2\).
In Exercises 83–86, use Eq. (11) to find \({d^2y}/{dx^2}\).
\(x=t^3+t^2,\quad y = 7t^2-4,\quad t = 2\)
\(x=s^{-1}+s,\quad y = 4-s^{-2},\quad s = 1\)
\(x=8t+9,\quad y = 1-4t,\quad t = -3\)
\(x=\cos \theta,\quad y = \sin \theta,\quad \theta = \frac{\pi}{4}\)
Use Eq. (11) to find the \(t\)-intervals on which \(c(t) =(t^2, t^3 - 4t)\) is concave up.
Use Eq. (11) to find the \(t\)-intervals on which \(c(t) =(t^2, t^4 - 4t)\) is concave up.
619
Area Under a Parametrized Curve Let \(c(t)=(x(t),y(t))\), where \(y(t)>0\) and \(x'(t)>0\) (Figure 11.24). Show that the area \(A\) under \(c(t)\) for \(t_0\le t\le t_1\) is \begin{equation} \label{12.exparam.paramarea} A = \int_{t_0}^{t_1} y(t)x'(t)\,dt\tag{12} \end{equation}
Hint: Because it is increasing, the function \(x(t)\) has an inverse \(t = g(x)\) and \(c(t)\) is the graph of \(y = y(g(x))\). Apply the change-of-variables formula to \({A = \int_{x(t_0)}^{x(t_1)} y(g(x))\,dx}\).
Calculate the area under \(y=x^2\) over \(\left[0,1\right]\) using Eq. (12) with the parametrizations \((t^3,t^6)\) and \((t^2,t^4)\).
What does Eq. (12) say if \(c(t) = (t,f(t))\)?
Sketch the graph of \(c(t)=(\ln t, 2 - t)\) for \(1\le t\le 2\) and compute the area under the graph using Eq. (12).
Galileo tried unsuccessfully to find the area under a cycloid. Around 1630, Gilles de Roberval proved that the area under one arch of the cycloid \(c(t) = (Rt-R\sin t, R-R\cos t)\) generated by a circle of radius \(R\) is equal to three times the area of the circle (Figure 11.25). Verify Roberval’s result using Eq. (12).
Further Insights and Challenges
Prove the following generalization of Exercise 93: For all \(t>0\), the area of the cycloidal sector \(OPC\) is equal to three times the area of the circular segment cut by the chord \(PC\) in Figure 11.26.
Derive the formula for the slope of the tangent line to a parametric curve \(c(t)=(x(t), y(t))\) using a method different from that presented in the text. Assume that \(x'(t_0)\) and \(y'(t_0)\) exist and that \(x'(t_0)\ne 0\). Show that \[ \lim_{h\to 0} \frac{y(t_0+h)-y(t_0)}{x(t_0+h)-x(t_0)}=\frac{y'(t_0)}{x'(t_0)} \]
Then explain why this limit is equal to the slope \(dy/dx\). Draw a diagram showing that the ratio in the limit is the slope of a secant line.
Verify that the tractrix curve \((\ell>0)\) \[ c(t) = \left(t-\ell\tanh \frac{t}{\ell}, \ell \textrm{sech } \frac{t}{\ell}\right) \] has the following property: For all \(t\), the segment from \(c(t)\) to \((t,0)\) is tangent to the curve and has length \(\ell\) (Figure 11.27).
In Exercise 54 of Section 9.1, we described the tractrix by the differential equation \[ \frac{dy}{dx}=-\frac{y}{\sqrt{\ell^2-y^2}} \]
Show that the curve \(c(t)\) identified as the tractrix in Exercise 96 satisfies this differential equation. Note that the derivative on the left is taken with respect to \(x\), not \(t\).
In Exercises 98 and 99, refer to Figure 11.28.
In the parametrization \(c(t)= (a\cos t, b\sin t)\) of an ellipse, \(t\) is not an angular parameter unless \(a=b\) (in which case the ellipse is a circle). However, \(t\) can be interpreted in terms of area: Show that if \(c(t)= (x,y)\), then \(t = (2/ab)A\), where \(A\) is the area of the shaded region in Figure 11.28. Hint: Use Eq. (12).
620
Show that the parametrization of the ellipse by the angle \(\theta\) is \begin{align*} x &= \frac{ab\cos\theta}{\sqrt{a^2\sin^2\theta+b^2\cos^2\theta}}\\ y&=\frac{ab\sin\theta}{\sqrt{a^2\sin^2\theta+b^2\cos^2\theta}} \end{align*}