Preliminary Questions
What is the flux of \({\bf F}=\langle 1,0,0\rangle\) through a closed surface?
Justify the following statement: The flux of \({\bf F}=\langle x^3,y^3,z^3\rangle\) through every closed surface is positive.
Which of the following expressions are meaningful (where \({\bf F}\) is a vector field and \(f\) is a function)? Of those that are meaningful, which are automatically zero?
Which of the following statements is correct (where \({\bf F}\) is a continuously differentiable vector field defined everywhere)?
How does the Divergence Theorem imply that the flux of \({\bf F} = \langle x^2, y-e^z, y-2zx\rangle\) through a closed surface is equal to the enclosed volume?
Exercises
In Exercises 1–4, compute the divergence of the vector field.
\(\displaystyle{{\bf F} = \langle xy,yz,y^2-x^3\rangle}\)
\(\displaystyle{x{\bf i}+y{\bf j}+z{\bf k}}\)
\(\displaystyle{{\bf F} = \langle x-2zx^2,z-xy,z^2x^2\rangle}\)
\(\displaystyle{\sin(x+z){\bf i}-ye^{xz}{\bf k}}\)
Find a constant \(c\) for which the velocity field \[ {\bf v} = (cx - y){\bf i} + (y - z){\bf j} + (3x + 4cz){\bf k} \] of a fluid is incompressible [meaning that \(\hbox{div}({\bf v})=0\)].
Verify that for any vector field \({\bf F} = \langle F_1, F_2, F_3\rangle\), \[ \hbox{div}({\bf curl}({\bf F}))=0 \]
In Exercises 7–10, verify the Divergence Theorem for the vector field and region.
\({\bf F} = \langle z,x,y\rangle\), the box \([0,4]\times[0,2]\times[0,3]\)
\({\bf F} = \langle y,x,z\rangle\), the region \(x^2+y^2+z^2\le 4\)
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\({\bf F} = \langle 2x,3z,3y\rangle\), the region \(x^2+y^2\le 1\), \(0\le z \le 2\)
\({\bf F} = \langle x,0,0\rangle\), the region \(x^2+y^2\le z \le 4\)
In Exercises 11–18, use the Divergence Theorem to evaluate the flux \(\displaystyle{\iint_{S\,}{\bf F}\cdot d{\bf S}}\).
\({\bf F} = \langle 0,0,z^3/3 \rangle\), \(S\) is the sphere \(x^2+y^2+z^2=1\).
\({\bf F} = \langle y, z, x \rangle\), \(S\) is the sphere \(x^2+y^2+z^2=1\).
\({\bf F} = \langle x^3,0,z^3\rangle\), \(S\) is the octant of the sphere \(x^2+y^2+z^2=4\), in the first octant \(x\ge 0, y\ge 0, z\ge 0\).
\({\bf F} = \langle e^{x+y}, e^{x+z}, e^{x+y} \rangle\), \(S\) is the boundary of the unit cube \(0\le x \le 1, 0 \le y \le 1, 0 \le z\le 1\).
\({\bf F} = \langle x,y^2,z+y \rangle\), \(S\) is the boundary of the region contained in the cylinder \(x^2+y^2= 4\) between the planes \(z=x\) and \(z=8\).
\({\bf F} = \langle x^2-z^2, e^{z^2}-\cos x, y^3 \rangle\), \(S\) is the boundary of the region bounded by \(x+2y+4z=12\) and the coordinate planes in the first octant.
\({\bf F} = \langle x+y, z, z-x\rangle\), \(S\) is the boundary of the region between the paraboloid \(z=9-x^2-y^2\) and the \(xy\)-plane.
\({\bf F} = \langle e^{z^2}, 2y+\sin(x^2z), 4z+\sqrt{x^2+9y^2} \rangle\), \(S\) is the region\newline \) x^2+y^2\le z \le 8-x^2-y^2\).
Calculate the flux of the vector field \({\bf F} = 2xy{\bf i}- y^2{\bf j}+{\bf k}\) through the surface \(S\) in Figure 17.70. Hint: Apply the Divergence Theorem to the closed surface consisting of \(S\) and the unit disk.
Let \(S_1\) be the closed surface consisting of \(S\) in Figure 17.70 together with the unit disk. Find the volume enclosed by \(S_1\), assuming that \[ \iint_{S_1}\langle x, 2y, 3z \rangle\cdot\,d{\bf S} = 72 \]
Let \(S\) be the half-cylinder \(x^2+y^2=1\), \(x\ge 0\), \(0\le z\le 1\). Assume that \({\bf F}\) is a horizontal vector field (the \(z\)-component is zero) such that \({\bf F}(0,y,z) = zy^2{\bf i}\). Let \(W\) be the solid region enclosed by \(S\), and assume that \[ \iiint_{W\,} \hbox{div}({\bf F})\, dV = 4 \] Find the flux of \({\bf F}\) through the curved side of \(S\).
Volume as a Surface Integral Let \({\bf F} = \langle x, y, z\rangle\). Prove that if \(W\) is a region \({\bf R}^3\) with a smooth boundary \(S\), then \begin{equation} \textrm{Volume}(W) = \frac13\iint_{S\,}{\bf F}\cdot d{\bf S}\tag{10} \end{equation}
Use Eq. (10) to calculate the volume of the unit ball as a surface integral over the unit sphere.
Verify that Eq. (10) applied to the box \([0,a]\times[0,b]\times[0,c]\) yields the volume \(V=abc\).
Let \(W\) be the region in Figure 17.71 bounded by the cylinder \(x^2+y^2=4\), the plane \(z=x+1\), and the \(xy\)-plane. Use the Divergence Theorem to compute the flux of \({\bf F}=\langle z, x, y + z^2\rangle\) through the boundary of \(W\).
Let \(\displaystyle{I=\iint_{S\,} {\bf F}\cdot d{\bf S}}\), where \[ {\bf F} = \langle \frac{2yz}{r^2},-\frac{xz}{r^2},-\frac{xy}{r^2}\rangle \] (\(r=\sqrt{x^2+y^2+z^2}\)) and \(S\) is the boundary of a region \(W\).
The velocity field of a fluid \({\bf v}\) (in meters per second) has divergence \(\hbox{div}({\bf v})(P)=3\) at the point \(P=(2,2,2)\). Estimate the flow rate out of the sphere of radius \(0.5\) centered at \(P\).
A hose feeds into a small screen box of volume \(10\) cm\(^3\) that is suspended in a swimming pool. Water flows across the surface of the box at a rate of \(12\) cm\(^3\)/s. Estimate \(\hbox{div}({\bf v})(P)\), where \({\bf v}\) is the velocity field of the water in the pool and \(P\) is the center of the box. What are the units of \(\hbox{div}({\bf v})(P)\)?
The electric field due to a unit electric dipole oriented in the \({\bf k}\)-direction is \(\displaystyle{{\bf E}= \nabla ({z}/{r^3} )}\), where \(r=(x^2+y^2+z^2)^{1/2}\) (Figure 17.72). Let \(\displaystyle{{\bf e}_r =r^{-1}\langle x, y, z\rangle}\).
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Let \({\bf E}\) be the electric field due to a long, uniformly charged rod of radius \(R\) with charge density \(\delta\) per unit length (Figure 17.73). By symmetry, we may assume that \({\bf E}\) is everywhere perpendicular to the rod and its magnitude \(E(d)\) depends only on the distance \(d\) to the rod (strictly speaking, this would hold only if the rod were infinite, but it is nearly true if the rod is long enough). Show that \(\displaystyle{E(d) = {\delta}/{2\pi\epsilon_0 d}}\) for \(d>R\). Hint: Apply Gauss’s Law to a cylinder of radius \(R\) and of unit length with its axis along the rod.
Let \(W\) be the region between the sphere of radius \(4\) and the cube of side \(1\), both centered at the origin. What is the flux through the boundary \(S=\partial W\) of a vector field \({\bf F}\) whose divergence has the constant value \(\hbox{div}({\bf F})=-4\)?
Let \(W\) be the region between the sphere of radius \(3\) and the sphere of radius \(2\), both centered at the origin. Use the Divergence Theorem to calculate the flux of \({\bf F} = x {\bf i}\) through the boundary \(S=\partial W\).
Find and prove a Product Rule expressing \(\hbox{div}(f{\bf F})\) in terms of \(\hbox{div}({\bf F})\) and \(\nabla f\).
Prove the identity \[ \hbox{div}({\bf F}\times{\bf G}) = {\bf curl}({\bf F}) \cdot {\bf G} - {\bf F} \cdot {\bf curl}({\bf G}) \] Then prove that the cross product of two irrotational vector fields is incompressible [\({\bf F}\) is called irrotational if \({\bf curl}({\bf F})=0\) and incompressible if \(\hbox{div}({\bf F})=0\)].
Prove that \(\hbox{div}(\nabla f\times\nabla g)=0\).
In Exercises 36–38, \(\Delta\) denotes the Laplace operator defined by \[ \boxed{\Delta\varphi = \dfrac{\partial^2\varphi}{\partial x^2} + \dfrac{\partial^2\varphi}{\partial y^2} + \dfrac{\partial^2\varphi}{\partial z^2} } \]
Prove the identity \[ {\bf curl}({\bf curl}({\bf F}))=\nabla(\hbox{div}({\bf F}))-\Delta{\bf F} \] where \(\Delta {\bf F}\) denotes \(\langle \Delta F_1,\Delta F_2,\Delta F_3\rangle\).
A function \(\varphi\) satisfying \(\Delta\varphi=0\) is called harmonic.
Let \({\bf F} = r^n{\bf e}_r \), where \(n\) is any number, \(r=(x^2+y^2+z^2)^{1/2}\), and \({\bf e}_r = r^{-1}\langle x,y,z \rangle\) is the unit radial vector.
Further Insights and Challenges
Let \(S\) be the boundary surface of a region \(W\) in \({\bf R}^3\) and let \(D_{{\bf e}_{\bf n}}\varphi\) denote the directional derivative of \(\varphi\), where \({\bf e}_{\bf n}\) is the outward unit normal vector. Let \(\Delta\) be the Laplace operator defined earlier.
Assume that \(\varphi\) is harmonic. Show that \(\hbox{div}(\varphi\nabla \varphi)=\|{\nabla \varphi}\|^2\) and conclude that \[ \iint_{S\,} \varphi D_{{\bf e}_{\bf n}}\varphi\,dS = \iiint_{W\,}\|{\nabla \varphi}\|^2\,dV \]
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Let \({\bf F} = \langle P,Q,R\rangle\) be a vector field defined on \({\bf R}^3\) such that \(\hbox{div}({\bf F})=0\). Use the following steps to show that \({\bf F}\) has a vector potential.
Show that \[{\bf F} = \langle 2y-1, 3z^2, 2xy \rangle\] has a vector potential and find one.
Show that\[{\bf F} = \langle 2ye^z - xy, y, yz-z\rangle\] has a vector potential and find one.
In the text, we observed that although the inverse-square radial vector field \(\displaystyle{{\bf F} = \frac{{\bf e}_r}{r^2}}\) satisfies \(\hbox{div}({\bf F})=0\), \({\bf F}\) cannot have a vector potential on its domain \(\{(x,y,z)\ne (0,0,0)\}\) because the flux of \({\bf F}\) through a sphere containing the origin is nonzero.
Let \({\bf F}(x,y)= \langle x+ y^2, x^2-y \rangle\) and let \(C\) be the unit circle, oriented counterclockwise. Evaluate \(\displaystyle \oint_{C} {\bf F}\cdot d{\bf s} \) directly as a line integral and using Green’s Theorem.
Let \(\partial R\) be the boundary of the rectangle in Figure 17.74 and let \(\partial R_1\) and \(\partial R_2\) be the boundaries of the two triangles, all oriented counterclockwise.
In Exercises 3–6, use Green’s Theorem to evaluate the line integral around the given closed curve.
\(\displaystyle{\oint_{C} x y^3 \,dx+ x^3y \,dy}\), where \(C\) is the rectangle \(-1\le x\le 2\), \(-2\le y\le 3\), oriented counterclockwise.
\(\displaystyle{\oint_{C}(3x+5y- \cos y) \,dx+x \sin y \,dy}\), where \(C\) is any closed curve enclosing a region with area \(4\), oriented counterclockwise.
\(\displaystyle{\oint_{C} y^2 \,dx- x^2 \,dy}\), where \(C\) consists of the arcs \(y= x^2\) and \(y=\sqrt{x}\), \(0\le x\le 1\), oriented clockwise.
\(\displaystyle \oint_{C} y e^x \,dx+x e^y \,dy\), where \(C\) is the triangle with vertices \((-1,0)\), \((0,4)\), and \((0,1)\), oriented counterclockwise.
Let \({\bf c}(t)=\bigl(t^2(1-t),t{(t-1)}^2\bigr)\).
In (a)–(d), state whether the equation is an identity (valid for all \({\bf F}\) or \( V\)). If it is not, provide an example in which the equation does not hold.
In Exercises 9–12, calculate the curl and divergence of the vector field.
\(\displaystyle{{\bf F}= y{\bf i}-z{\bf k}}\)
\({\bf F}= \langle e^{x+y}, e^{y+z},xyz \rangle\)
\(\displaystyle{{\bf F} = \nabla(e^{-x^2-y^2-z^2})}\)
\(\displaystyle{{\bf e}_r =r^{-1}\langle x, y, z\rangle}\) \(\bigl(r = \sqrt{x^2+y^2+z^2}\bigr)\)
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Recall that if \(F_1\), \(F_2\), and \(F_3\) are differentiable functions of one variable, then \[ {\bf curl} \left(\left< F_1(x), F_2(y), F_3(z) \right>\right)=\mathbf{0} \] Use this to calculate the curl of \[ {\bf F}=\langle x^2+ y^2,\ln y+z^2, z^3\sin(z^2)e^{z^3} \rangle \]
Give an example of a nonzero vector field \({\bf F}\) such that \({\bf curl}({\bf F})={\bf 0}\) and \(\hbox{div}({\bf F})=0\).
Verify the identities of Exercises 6 and 13 in Section 17.3 for the vector fields \({\bf F} = \langle xz, ye^x, yz\rangle\) and \({\bf G} = \langle z^2, xy^3, x^2 y\rangle\).
Suppose that \(S_1\) and \(S_2\) are surfaces with the same oriented boundary curve \(C\). Which of the following conditions guarantees that the flux of \({\bf F}\) through \(S_1\) is equal to the flux of \({\bf F}\) through \(S_2\)?
Prove that if \({\bf F}\) is a gradient vector field, then the flux of \({\bf curl}({\bf F})\) through a smooth surface \(S\) (whether closed or not) is equal to zero.
Verify Stokes’ Theorem for \({\bf F}= \left< y,z-x,0 \right>\) and the surface \(z=4- x^2- y^2\), \(z\ge 0\), oriented by outward-pointing normals.
Let \({\bf F}= \langle z^2,x+z, y^2 \rangle\) and let \(S\) be the upper half of the ellipsoid \[{\frac{x^2}{4}+ y^2+ z^2=1}\] oriented by outward-pointing normals. Use Stokes’ Theorem to compute \(\displaystyle{\iint_{S\,}{\bf curl}({\bf F})\cdot d{\bf S}}\).
Use Stokes’ Theorem to evaluate \(\displaystyle \oint_{C} \langle y,z,x \rangle\cdot d{\bf s} \), where \(C\) is the curve in Figure 17.75.
Let \(S\) be the side of the cylinder \(x^2+y^2=4\), \(0\le z\le 2\) (not including the top and bottom of the cylinder). Use Stokes’ Theorem to compute the flux of \({\bf F}=\langle 0,y, -z\rangle\) through \(S\) (with outward pointing normal) by finding a vector potential \({\bf A}\) such that \({\bf curl}({\bf A})={\bf F}\).
Verify the Divergence Theorem for \({\bf F}= \langle 0,0,z \rangle\) and the region \(x^2+y^2+z^2=1\).
In Exercises 23–26, use the Divergence Theorem to calculate \(\displaystyle{\iint_{S\,}{\bf F}\cdot d{\bf S}}\) for the given vector field and surface.
\({\bf F} = \langle xy,yz, x^2z+ z^2 \rangle\), \(S\) is the boundary of the box \(\left[0,1\right]\times \left[2,4\right]\times \left[1,5\right]\).
\({\bf F} = \langle xy,yz, x^2z+ z^2 \rangle\), \(S\) is the boundary of the unit sphere.
\({\bf F}= \langle xyz+xy,\frac12 y^2(1-z )+ e^x , e^{x^2+ y^2} \rangle\), \(S\) is the boundary of the solid bounded by the cylinder \( x^2+ y^2=16\) and the planes \(z=0\) and \(z=y-4\).
\({\bf F} = \langle \sin(yz), \sqrt{x^2+z^4}, x\cos(x-y)\rangle\), \(S\) is any smooth closed surface that is the boundary of a region in \({\bf R}^3\).
Find the volume of a region \(W\) if \[ \iint_{\partial W\,} \langle x+xy+z,x+3y-\frac12y^2,4z \rangle \cdot d{\bf S} =16 \]
Show that the circulation of \({\bf F} = \langle x^2,y^2,z(x^2+y^2)\rangle\) around any curve \(C\) on the surface of the cone \(z^2= x^2+y^2\) is equal to zero (Figure 17.76).
In Exercises 29–32, let \({\bf F}\) be a vector field whose curl and divergence at the origin are \[ {\bf curl}({\bf F})(0,0,0)=\langle 2, -1, 4\rangle,\qquad \hbox{div}({\bf F})(0,0,0)= -2 \]
Estimate \(\displaystyle{\oint_{C}{\bf F}\cdot d{\bf s}}\), where \(C\) is the circle of radius \(0.03\) in the \(xy\)-plane centered at the origin.
Estimate \(\displaystyle{\oint_{C}{\bf F}\cdot d{\bf s}}\), where \(C\) is the boundary of the square of side \(0.03\) in the \(yz\)-plane centered at the origin. Does the estimate depend on how the square is oriented within the \(yz\)-plane? Might the actual circulation depend on how it is oriented?
Suppose that \({\bf v}\) is the velocity field of a fluid and imagine placing a small paddle wheel at the origin. Find the equation of the plane in which the paddle wheel should be placed to make it rotate as quickly as possible.
Estimate the flux of \({\bf F}\) through the box of side \(0.5\) in Figure 17.77. Does the result depend on how the box is oriented relative to the coordinate axes?
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The velocity vector field of a fluid (in meters per second) is \[ {\bf F}=\langle x^2+y^2,0,z^2\rangle \] Let \(W\) be the region between the hemisphere \[ S = \bigl\{(x,y,z): x^2+y^2+z^2=1,\quad x,y,z \geq 0\bigr\} \] and the disk \(\displaystyle{D = \bigl\{(x,y,0): x^2+y^2\le 1\bigr\}}\) in the \(xy\)-plane. Recall that the flow rate of a fluid across a surface is equal to the flux of \({\bf F}\) through the surface.
The velocity field of a fluid (in meters per second) is \[ {\bf F} = (3y - 4){\bf i}+ e^{-y(z+1)}{\bf j}+ (x^2 + y^2){\bf k} \]
Let \(\displaystyle{ V(x,y)=x+\frac{x}{x^2+y^2}}\). The vector field \({\bf F} = \nabla V\) (Figure 17.78) provides a model in the plane of the velocity field of an incompressible, irrotational fluid flowing past a cylindrical obstacle (in this case, the obstacle is the unit circle \(x^2+y^2=1\)).
Figure 17.79 shows the vector field \({\bf F}=\nabla V\), where \[ V(x,y)=\ln\big(x^2+(y-1)^2\big)+\ln\big(x^2+(y+1)^2\big)\] which is the velocity field for the flow of a fluid with sources of equal strength at \((0,\pm 1)\) (note that \( V\) is undefined at these two points). Show that \({\bf F}\) is both irrotational and incompressible—that is, \({\bf curl}_z({\bf F})=0\) and \(\hbox{div}({\bf F})=0\) [in computing \(\hbox{div}({\bf F})\), treat \({\bf F}\) as a vector field in \({\bf R}^3\) with a zero \(z\)-component]. Is it necessary to compute \({\bf curl}_z({\bf F})\) to conclude that it is zero?
In Section 17.1, we showed that if \(C\) is a simple closed curve, oriented counterclockwise, then the line integral is \begin{equation} \textrm{Area enclosed by \(C\)} = \frac12\oint_{C} x\,dy-y\,dx\tag{1} \end{equation}
Suppose that \(C\) is a path from \(P\) to \(Q\) that is not closed but has the property that every line through the origin intersects \(C\) in at most one point, as in Figure 17.80. Let \( R\) be the region enclosed by \(C\) and the two radial segments joining \(P\) and \(Q\) to the origin. Show that the line integral in Eq. (1) is equal to the area of \( R\). Hint: Show that the line integral of \({\bf F}=\langle -y,x\rangle\) along the two radial segments is zero and apply Green’s Theorem.
Suppose that the curve \(C\) in Figure 17.80 has the polar equation \(r=f(\theta)\).
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Prove the following generalization of Eq. (1). Let \(C\) be a simple closed curve in the plane (Figure 17.81) \[ S:\quad ax+by+cz+d=0 \] Then the area of the region \(R\) enclosed by \(C\) is equal to \[ \frac{1}{2\|{{\bf n}}\|} \oint_{C} (bz-cy) \,dx+(cx-az) \,dy+(ay-bx) \,dz \] where \({\bf n}=\langle a, b, c\rangle\) is the normal to \(S\), and \(C\) is oriented as the boundary of \( R\) (relative to the normal vector \({\bf n}\)). Hint: Apply Stokes’ Theorem to \(\displaystyle{{\bf F} = \langle bz-cy,cx-az,ay-bx \rangle}\).
Use the result of Exercise 37 to calculate the area of the triangle with vertices \((1,0,0)\), \((0,1,0)\), and \((0,0,1)\) as a line integral. Verify your result using geometry.
Show that \(G(\theta,\phi)= (a\cos\theta\sin\phi,b\sin\theta\sin\phi,c\cos\phi)\) is a parametrization of the ellipsoid \[ \left(\frac{x}a\right)^2+\left(\frac{y}b\right)^2+\left(\frac{z}c\right)^2 = 1 \] Then calculate the volume of the ellipsoid as the surface integral of \({\bf F} = \frac13\langle x,y,z\rangle\) (this surface integral is equal to the volume by the Divergence Theorem).