eval rand(5,9);

$a+1;

$b*$a-$a;

$a*$a;

2*$C1;

eval $b*$a+$a;

eval 2*($a+$a);

eval round($ansa/$ansb,2);

Estimate the limit, if it exists. If not, determine whether the one-sided limits exist (finite or infinite).

Recall the Quotient Law for evaluating limits given that and exist. If , then exists and .

For the given rational function , evaluate the limit of the numerator and denominator as *x* approaches $a.

= 1Wh3cvJ2xF4=

= 1Wh3cvJ2xF4=

Incorrect.

Correct.

The Quotient Law h6Q4QU2SWfOKIbur4GLV8BRt1Yk= apply. We say that is 5rEcHixAdeJONJPG1u7+MGlhGwvO3Ffr8ZOTskzRg00iFfNADxYU/lSGWsucE+q4 at* x =* $a.

Incorrect.

Correct.

Since the rational function has an indeterminate form of the type at *x* = $a, we can find an equivalent expression for the function by factoring its numerator and denominator and cancelling like factors, however, that we keep the domain of the original rational function.

where *z* = nc1ItEz0kR4=.

Correct.

Incorrect.

where w = nc1ItEz0kR4=, x ≠ $a.

Correct.

Incorrect.

Since the limit is being evaluated as *x* approaches $a (meaning for all values of *x* near $a, but not equal to $a), we can try to evaluate by applying the Quotient Law for evaluating limits.

Evaluate the limit of the numerator and denominator as *x* approaches $a.

= BXETLrOxfxWcrhv0

= WDGIqOk3EfJe+Vr/

Correct.

Incorrect.

Thus, the Quotient Law PXcxRRPwVznkzmRiLdM8PZPj3qw= apply to and the limit G3WoGiusd49jA3XEAg63iCp80mVMXfEpMr/LxQ==.

Correct.

Incorrect.

Evaluate

= qjqZz1N+poo=

(Round your answer to two decimal places.)

Correct.

Incorrect.