Here are some resources to help you better understand molar mass.
We'll ask a simple problem here: 0VV1JcqyBrI=
Consider the following equation:
H2A(aq) + NaOH(aq) -> Na2A(aq) + H2O(l)
Balance the equation by entering the appropriate numbers (Don't leave any spaces blank - use 1 if needed):
0VV1JcqyBrI=H2A(aq) + XvVM00l89Is=NaOH(aq) -> 0VV1JcqyBrI=Na2A(aq) + XvVM00l89Is=H20(l)
Notice that you are given the molar concentration and volume of NaOH delivered in the titration. Since the units of molar concentration (molarity) are in moles/L, multiplying the molar concentration by the volume of NaOH (in L) yields the moles of NaOH.
How many moles of NaOH react?XvVM00l89Is=
Once you have the moles of NaOH delivered in the titration, use the stoichiometric coefficients to derive the mole ratio to convert from moles NaOH to moles H2A. Since you need the moles of NaOH to cancel, the correct mole ratio is 1 mol H2A/2 mol NaOH.
How many moles of H2A react? 0VV1JcqyBrI=
The units of molar mass are g/mol. Inspect the question and notice that you are given the mass of the H2A sample. Next, divide the mass of H2A by the moles of H2A.
I'm not sure exactly what this question should be 0VV1JcqyBrI=
Any additional help to provide?