Condition for rolling without slipping (8-13)

Balloon Art Concept Check: Click on the part of the equation that is described by the bubble text shown

Question 1 of 3

Question

\(\textbf{Speed}\) of the center of mass of a rolling object
Feedback
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Review

Equation 8-13 says that there is a direct proportionality between the linear speed \(v_\mathrm{CM}\) and angular speed \(\omega\) of a circular object that rolls without slipping. As the wheel in Figure 8-13 rolls downhill it gains speed so \(v_\mathrm{CM}\) increases, and it rotates faster so \(\omega\) increases, but these increases are always proportional to each \perpher so that \(v_\mathrm{CM}\) and \(\omega\) are always related by Equation 8-13.