Chapter 9. Hooke's law for an oject under volume stress (9-6)

Question

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{"title":"Volume stress on the object: change in the pressure p on all sides of the object","description":"Correct!","type":"correct","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"33,45,69,100\"}]"} {"title":"Bulk modulus B: How difficult it is to compress the material of which the object is made; larger B means harder to compress.","description":"Wrong","type":"incorrect","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"164,36,200,86\"},{\"shape\":\"rect\",\"coords\":\"154,37,157,37\"}]"} {"title":"Volume strain of the object: resulting change in volume Delta V divided by the object's initial volume v sub 0","description":"Incorrect","type":"incorrect","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"257,11,291,56\"}]"} {"title":"Important! If ∆p is positive, then ∆V is negative; if ∆p is negative, then ∆V is positive.","description":"Incorrect","type":"incorrect","color":"#000080","code":"[{\"shape\":\"rect\",\"coords\":\"127,49,167,75\"}]"}

Question

0MO1/VBY60E1nyeSbChmIBTkIHn+sVIrGPTCUWJryCDeWPm8Rsrc05HyiorvF7a+r+QX4WMjAmpQmUtXY+WK7qZaiP4ItdYVV8mwvvvRFYHUiWcbQO8fBdPmXM7PG3O7BNLnvmA+3HJtHqb0ipNsiiNm9AbkKGgoc+OYxilQfsuvYuE9zADSYIlKJQ0bkG74/3FsAA==
{"title":"Volume stress on the object: change in the pressure p on all sides of the object","description":"Incorrect","type":"incorrect","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"33,45,69,100\"}]"} {"title":"Bulk modulus B: How difficult it is to compress the material of which the object is made; larger B means harder to compress.","description":"Correct!","type":"correct","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"164,36,200,86\"},{\"shape\":\"rect\",\"coords\":\"154,37,157,37\"}]"} {"title":"Volume strain of the object: resulting change in volume Delta V divided by the object's initial volume v sub 0","description":"Incorrect","type":"incorrect","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"257,11,291,56\"}]"} {"title":"Important! If ∆p is positive, then ∆V is negative; if ∆p is negative, then ∆V is positive.","description":"Incorrect","type":"incorrect","color":"#000080","code":"[{\"shape\":\"rect\",\"coords\":\"127,49,167,75\"}]"}

Question

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{"title":"Volume stress on the object: change in the pressure p on all sides of the object","description":"Incorrect","type":"incorrect","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"33,45,69,100\"}]"} {"title":"Bulk modulus B: How difficult it is to compress the material of which the object is made; larger B means harder to compress.","description":"Wrong","type":"incorrect","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"164,36,200,86\"},{\"shape\":\"rect\",\"coords\":\"154,37,157,37\"}]"} {"title":"Volume strain of the object: resulting change in volume Delta V divided by the object's initial volume v sub 0","description":"Correct!","type":"correct","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"257,11,291,56\"}]"} {"title":"Important! If ∆p is positive, then ∆V is negative; if ∆p is negative, then ∆V is positive.","description":"Incorrect","type":"incorrect","color":"#000080","code":"[{\"shape\":\"rect\",\"coords\":\"127,49,167,75\"}]"}

Question

XWtw4Pz2cqRc5J+j/iWz1D8K5RjAg6amt0Gd2MAxMW8Rx+bb2QC8TmA+WehYoSoPw68RA1OIVL9Sd0FSBECFATACJZRZUPObXWy4VO5djgVd+zBX1r5E9+7qGuz7cOA6+g7KHlw7ToZBVnLgfLOACVlQldHUJ+NbWeowfQwkzC4zkxvY17c1x0oK0kM=
{"title":"Volume stress on the object: change in the pressure p on all sides of the object","description":"Incorrect","type":"incorrect","color":"#99CCFF","code":"[{\"shape\":\"poly\",\"coords\":\"82,133\"},{\"shape\":\"rect\",\"coords\":\"33,45,69,100\"}]"} {"title":"Bulk modulus B: How difficult it is to compress the material of which the object is made; larger B means harder to compress.","description":"Wrong","type":"incorrect","color":"#ffcc00","code":"[{\"shape\":\"rect\",\"coords\":\"118,11,119,13\"},{\"shape\":\"rect\",\"coords\":\"164,36,200,86\"},{\"shape\":\"rect\",\"coords\":\"154,37,157,37\"}]"} {"title":"Volume strain of the object: resulting change in volume Delta V divided by the object's initial volume v sub 0","description":"Incorrect","type":"incorrect","color":"#333300","code":"[{\"shape\":\"rect\",\"coords\":\"257,11,291,56\"}]"} {"title":"Important! If ∆p is positive, then ∆V is negative; if ∆p is negative, then ∆V is positive.","description":"Correct!","type":"correct","color":"#000080","code":"[{\"shape\":\"rect\",\"coords\":\"127,49,167,75\"}]"}

Review

In terms of the quantities \(\Delta{p}\), \(V_0\), and \(\Delta{V}\) depicted in Figure 9-10, we can rewrite Equation 9-5 as:

To get more insight into the meaning of Equation 9-6, multiply both sides by \(-V_0/B\) to rewrite it so that \(\Delta{V}\) is by itself on one side of the equation:

9-7 \(\Delta{V} = - \frac{\Delta{p}}{B}V_0\)