Solving chemistry problems sometimes involves solving a math equation. When the quantity you are looking for is isolated, or alone on one side of the equation, all you need to do is complete the calculations. A simple example is finding the Fahrenheit equivalent of 28 °C using the equation
Sometimes the quantity that answers your question is not alone on one side of the equation. To solve these problems, isolate the variable you are looking for on one side of the equation, so that calculations that will lead to your answer are on the other side of the equation. For example, to find a temperature in degrees Celsius, rearrange the equation in terms of C.
A-4
Start with the known relationship | |
Subtract 32° from both sides | |
Multiply both sides by |
Now that C is isolated, you can substitute any Fahrenheit temperature and carry out the calculations to find the corresponding Celsius temperature.
Solving for x
Solve these equations for x.
0.1x + 12 = 2.2
Solution
a. Original equation. |
0.1x + 12 = 2.2 |
Subtract 12 from both sides. |
0.1x + 12 – 12 = 2.2 – 12 |
0.1x = –9.8 |
|
Divide both sides by 0.1. |
x = –98 |
b. Original equation. | |
Multiply both sides by 3. |
12 + 3.12x = –300 |
Subtract 12 from both sides. |
–12 + 12 + 3.12x = –300 – 12 |
3.12x = –312 |
|
Divide both sides by 3.12. |
x = –100 |
Solving for V2
Solve this equation for V2.
for V2
Solution
Original equation. | |
Multiply both sides by T2; remove the factor of 1. |
|
Divide both sides by P2; remove the factor of 1. |
|
The equation is now expressed in terms of V2. Substituting in values for the other five variables will give a value for V2.
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Practice Exercises
Solve these equations. Indicate the action you take at each stage.
144x + 33 = 45
5(x − 7) = 15+ 52
Solve these equations for the variable indicated.
d = rt, for t
P = 2(l + w), for w
for h
1a. (On both sides, subtract 33 and divide by 144.)
1b. x = 36 (On both sides, subtract 2 then multiply by 6.)
1c. x = 15 (Combine 15 and 25 on the right side, divide both sides by 5, and add 7 to both.)
2a.
2b.
2c.