Chapter 1. Chapter 12: Complex Inheritance

1.1 Introduction

Interactive Study Guide
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Polaris Trail

Welcome to the Interactive Study Guide for Chapter 12: Complex Inheritance! This Study Guide will help you master your understanding of the chapter's Driving Questions, using interactive Infographics and activities, as well as targeted assessment questions. Click "Next" to get started, or select a Driving Question from the drop-down menu to the right.

Genetics Q&A:

Complexities of human genetics, from sex to depression

DRIVING QUESTIONS

  • How do chromosomes determine sex and how does sex influence the inheritance of certain traits?
  • Some traits are not inherited in simple dominant or recessive inheritance patterns. What are some complex inheritance patterns?
  • How do numerical abnormalities of chromosomes occur and what are the consequences of these abnormalities?

1.2 Driving Question 1

Driving Question 1

How do chromosomes determine sex, and how does sex influence the inheritance of certain traits?

Why should you care?

Gender identity is an essential part of a person's sense of self and is determined by the sex chromosomes that a person inherits. Although there are 22 pairs of 'non-sex' chromosomes, or autosomes, and only one pair of sex chromosomes in human cells, the special properties of the X and Y sex chromosomes make them important to people's lives for a several reasons: those with two X chromosomes in their cells are usually female, and those with an X and a Y chromosome are usually male. Furthermore, many human traits—including some diseases—are sex linked, usually meaning that they tend to be more prevalent in males than females. And recently, scientists have been able to make use of the lack of recombination between X and Y to trace paternity and family trees through Y chromosome sequences.

There is only one pair of sex chromosomes in the human genome, and they differ from the rest of the pairs in that they are not all the same size and do not carry all the same genes. The X chromosome is the larger of the two human sex chromosomes and therefore carries more genes, most of which are not related to sex determination. The traits controlled by these genes on the X chromosome are called X-linked traits. The Y chromosome is shorter than the X and carries many fewer genes, but it does carry the genes responsible for creating the developmental changes that make a child male. (The names X and Y for these chromosomes are historical and have nothing to do with their shape—a common misconception.)

An X-linked trait like Duchenne Muscular Dystrophy, usually involves an allele that is recessive. Women who have a functional allele on their other X chromosome can still make enough of the functional protein to make up for the disease allele. Men who inherit the DMD allele, however, only have the defective allele on their single X chromosome, and will therefore have the disease.

The X chromosome has many genes that the Y chromosome does not. Because of this, the X and Y chromosomes do not usually recombine (exchange genetic material) during meiosis, and Y chromosomes change less from generation to generation than X chromosomes. This makes the Y chromosome useful in geneological studies and paternity testing.

What should you know?

To fully answer this Driving Question, you should be able to:

  1. Explain how sex is determined in human children.
  2. Describe the location and importance of the SRY gene.
  3. Differentiate between the main sex hormones.
  4. Diagram how X-linked traits are inherited and predict the chance that a child will have an X-linked trait based on the parents’ genotype.
  5. Diagram a human pedigree, following symbol conventions, and use it to track the inheritance of diseases.
  6. Explain the difficulties in predicting whether a female child will be a carrier of an X-linked trait based on phenotype alone.
  7. Explain why the Y chromosome does not often/usually undergo recombination with the X chromosome, and why this fact is important.
  8. Explain why STR locations on the Y chromosome are useful for paternity and identity tests.

Infographic Focus:

The infographics most pertinent to the Driving Question are 12.1, 12.2, 12.3, 12.4 and 12.5.

Question Test Your Vocabulary

Choose the correct term for each of the following definitions:

Term Definition
voK/4XWeDtMVNSxuXKI0b4f/TNKTC/qikI89RzuS9xIGy2AkhgSYqkNOTxt0hrIU+oUbRYGByO6kGUQOowEdWboSF2QjxHhohRcvYCOEga9yYfkT A phenotype determined by an allele on an X chromosome.
NUGaU0PhnmZhd2n2D+OYQ9A/iv7bVyUXSJWZ6UsYhZGqPANI6adG914Rrrcocir75PJpmV+nS+OVtiUjdhCsGcQzxIdGhyPrrRKUhH45UbNgOtdP Paired chromosomes present in both males and females; all chromosomes except the X and Y chromosomes.
cKCEsXjaO2ZW9ipZYYVp1/Q58ZJdPz6aOJjFxiAiAFzLkaJ6UxiQt4D3FktvhAljOFw8cKNk+KltfhQG0iLBf6cBRDeM0fY8D8MWBipTWvNwJmN4 Sex organs; ovaries in females, testes in males.
a6ZoLkUgXhJS4gA6DEOoBkBdHi9Ubulld209wwkLqgh17QNG72Fu4RPgrFh2xGlUYaKzeeoC46auhHTnWGfW+sb/psLUuh19uqTEexkCU0ZvDFFn Comparing sequences on the Y chromosome to examine paternity and paternal ancestry.
AVz2tlHPG0+fco1X70ef6eQdmsMlKc8DRIvl/Q0fknn/AWrGkwiD6t4FwJSL6ZnJukTGn5l8ZHQQSF8FFyIqoRP2KZBzVvm1nEGA+yELpwJs37UE Paired chromosomes that differ between males and females, XX in females, XY in males.
ZqhzJ4QiiA0M0/tHbWQZETM1Q3HaA+n1vMi9+pQanmCjD2q+OUDud+Wmc0PXolT0yykr1Z5lLPAXsPdPekwCwUq4Bp/GWEINyn1pOH9ZIJMBm6KO A visual representation of the occurrence of phenotypes across generations.
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Explain how sex is determined in human children.

Question 1.1

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X Y
X XX XY
X XX XY
Table

Question 1.2

bBxeIz/tVe33zpKKW17b/Pu2T04PgGJpULoXJOXP92mYwY00SsOJZ0eOip/7Rktu1RqskKvVMP4cZHErM/r/9gy3pxf/A/5zlz12quC3wgcYm8PL
One kind, X.

Question 1.3

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Two kinds, X and Y.

Question 1.4

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50% chance XX, 50% chance XY.

Question 1.5

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If we look strictly at the results of the Punnett square and do not take into account mutations in other genes or gender identification of the child, then the chance of having a girl is 50% and the chance of having a boy is also 50%.

Describe the location and importance of the SRY gene.

Question 1.6

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It most likely found only on the Y chromosome, because individuals with an XY genotype usually exhibit traits that are considered biologically male, while individuals with an XX genotype usually do not exhibit these biologically male traits.

Question 1.7

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The genotype of such children would likely be XY, since they have an SRY gene to begin with (on the Y chromosome). The outward appearance would likely be more female, since the mutation affected the functions of SRY (e.g., failed to signal testes to develop).

Differentiate between the main sex hormones.

Question 1.8

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Both males and females produce both sex hormones, but in varying amounts. Males produce more testosterone and less estrogen, while females produce more estrogen and less testosterone.

Diagram how X-linked traits are inherited and predict the chance that a child will have an X-linked trait based on the parents’ genotype.

Question 1.9

A gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision.

BlthGX0t+1B3xXsUQupp2SJFTwNHIbunEL+KKXB1zm+/Kh/ePrO+2pzpAOD/QwIBaE5MgLVa4DWhH0DvaUhUmjUG3eYp2b6Vh79ky9N5UH7njsT5HblQtDOFTZjqRQYr3b/TGA==

X*: has red-green colorblindness genotype and phenotype

X Y
X XX XY
X* XX* X*Y
Table

Question 1.10

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50%, genotype X*Y

Question 1.11

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0%, would need to have the genotype X*X*

Question 1.12

vGJ3ybac7Ks5j05sp8XU+0qgKbtnGXQq/dofroPZovgbJvhlU8SLDsqMyomg8isBF7oOzQ==
75%, genotypes XX and XY

Question 1.13

QpksLTYvoXH+q4GfUejLAa7Qn8sEwx8Lz/eY9V1v09iHB+3zvJekY4ZpT856NGd2zuZr6UEihOyAezZJNIWXlvFVxWE8Z8osoWVmfqE57YUl0UdHyTgSgA==

X* = has red-green colorblindness genotype and phenotype

X* Y
X XX* XY
X* X*X* X*Y
Table

Question 1.14

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Yes, the chance of having a color-blind child doubles to 50%. Also, there is a 25% chance that a daughter will have color blindness.

Question 1.15

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A woman who is a carrier for a sex-linked trait has the mutant allele on one of her X chromosomes but does not manifest the mutant phenotype. This is because the normal gene on her other X chromosome compensates for the mutant allele, and thus she has a normal phenotype. She has a 50% chance, however, that she will pass the mutant allele on to her children, since she will provide an X chromosome to the zygote.

Question 1.16

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Male children are more likely to exhibit sex-linked traits because they have only one copy of the X chromosome and one copy of the Y chromosome. In the case of sex-linked diseases, they do not have a normal second copy of the gene to compensate for the mutant allele.

Diagram a human pedigree, following symbol conventions, and use it to track the inheritance of diseases.

Question 1.17

Examine the formatting of the pedigree chart in Infographic 12.3 so that you will be able to make your own.

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If you are female, you inherited the condition from both your maternal and paternal grandparent. If you are male, you inherited the condition from your maternal grandparent.

Question 1.18

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If you are female, your mother would have to be color-blind or a carrier for color blindness, and your father would have to be color-blind as well. If you are male, your mother would have to be color-blind or a carrier. It would not matter whether you father was color-blind or not.

Question 1.19

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If you are female, your father would be color-blind and your mother would be color-blind or a carrier. If your mother was color-blind, then her parents (your maternal grandparents) would follow the same predictions as for you. If you are male, your mother would be color-blind or a carrier. It would not matter whether your father was color-blind or not. If your mother was color-blind, then her parents (your maternal grandparents) would follow this prediction: her father (your grandfather) would be color-blind, and her mother (your grandmother) would be color-blind or a carrier.

Explain the difficulties in predicting whether a female child will carry an X-linked trait based on phenotype alone.

Question 1.20

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It is possible for multiple generations of women to carry a recessive disease and be unaware of it because they have another X chromosome with normal genes whose functions compensate for the mutated allele.

Explain why the Y chromosome does not often or usually undergo recombination with the X chromosome, and why this fact is important.

Question 1.21

Consider the following facts:

Homologous chromosomes must have similar sequences to recombine.

Recombination is always a rare event, but the recombination of genes between the X and Y chromosomes is rarer still, although it does occur.

It is thought that the X and Y chromosomes were once completely homologous in the earliest mammals.

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Over time, the X and Y chromosome sequences have grown more distinct from each other. Since chromosomes must have similar sequences to recombine, the differences between the sequences of the X and Y chromosomes are great enough that recombination rarely happens. It is important that recombination between these two chromosomes not happen frequently because, especially in males, there is only one copy of each chromosome, so the genes have to be correct and functional.

Explain why STR locations on the Y chromosome are useful for paternity and identity tests.

Question 1.22

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STR locations on the Y chromosome are ideal for paternity testing because you can inherit a Y chromosome only from your father. The STR locations are pretty well conserved generation to generation because recombination of the Y chromosome is very rare.

Review Questions

Question 1.23

For Questions 23 and 24, use the following information: Type A Hemophilia, a disorder in which blood does not clot properly, is governed by a recessive allele on the X chromosome. Suppose a healthy woman marries a man with Hemophilia A, and they are expecting a child.

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Question 1.24

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Question 1.25

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Question 1.26

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1.3 Driving Question 2

Driving Question 2

Some traits are not inherited in simple dominant or recessive inheritance patterns. What are some complex inheritance patterns?

Why should you care?

The inheritance of many traits involves more than one gene or may not be governed by alleles that show a simple dominant-recessive pattern. Moreover, many traits are influenced by environmental factors as well as genes. It is tempting to be disappointed to find out that predicting the inheritance of seemingly simple traits like eye color or height is far from straightforward. But rather than a disappointment, it can be exciting to learn that we are all more than the sum of our genes.

If you recall that genes are actually the building plans for the construction of proteins, and that alleles are different versions of genes, then the concept of codominance will make a lot of sense. When two alleles are codominant, they are both expressed at the same time. In the case of ABO blood types, two alleles (A and B) are codominant, and a third (O) is recessive. This means that if alleles A and B are both present in a person's genotype, the person's blood type wil be based on both the A and B blood-type proteins. In other words, the person will have type AB blood. Understanding codominance will help you understand blood types, which is an important health concept, and it will help you understand the inheritance of other traits.

Besides the many genes involved in brain development and function, your nutrition, education and experiences also influence the way your brain works. In other words, personality and mental health are polygenic and multifactorial traits, just like height.

What should you know?

To fully answer this Driving Question, you should be able to:

  1. Predict the potential trait (phenotype) that will be exhibited by a child for a gene whose alleles exhibit incomplete dominance.
  2. Describe the differences in blood markers between the different blood types.
  3. Predict a person’s genotype for the ABO blood type gene based on the person’s blood type.
  4. Compare and contrast complete dominance, incomplete dominance, and codominance.
  5. Differentiate between polygenic and multifactorial inheritance.
  6. Propose an explanation for how multifactorial inheritance works in the case of the serotonin transporter allele, stressful life events, and incidence of depression.

Infographic Focus:

The infographics most pertinent to the Driving Question are 12.6, 12.7, 12.8, 12.9, 12.10 and 12.11.

Question Test Your Vocabulary

Choose the correct term for each of the following definitions:

Term Definition
lZLpRU/bmZco08y/R6FtKhG3HhSGJozE7k0mNLDZa7qHgXBOd1agsDbVcKWv63lbF+5lGeHYoafXpRGoHYJ5n/SwzLEUg+nZn1HEY06X56npZXq1G5eo4AH0vqTPce6f0NV16pkfct8= An interaction between genes and the environment that contributes to a phenotype or trait.
qtCp4EVeawOIuhlU+Jn6eE/v5/YIFQ5wieDkaNepSMq79JfykZOrDTOhE8KLdZMI6pSTpO/PKNzfQGaxgv5szb7XDF/R8zXKfFueAq8zBytdpGmQt8do8XRu/le5a4d1MZU60g9yItY= A form of inheritance in which both alleles contribute equally to the phenotype.
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4y+M1hRC1W6v6z6C4zwHrag0rjOgHHgmY7J5IsKMQjVyRDxRbKOl1okOeOtylDD6oycGUnntlqLr6SgpKR8Lw/x7l1kZyJBKiqSBPeSPei+9W7S49vOl+i1LMaNOUU/WPDjv+YJG8KA= Variation in a population showing an unbroken range of phenotypes rather than discrete categories.
XcnME3XO2A73+E3hbsIGmhcnD64vN2QtJ2LWC8X0yuEoZmLmj0qsFuKVsdrLpo+7xc9JEwqs/Eoevo6T9k2LV/ZXlYQinV9J1x3rtpEuX/hS3CQ8OaCHbN1K9niMeBiQDhtEIXw1z4c= A trait whose phenotype is determined by the interaction among alleles of more than one gene.
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Predict the potential trait (phenotype) that will be exhibited by a child for a gene whose alleles exhibit incomplete dominance.

Question 1.27

Hair texture exhibits incomplete dominance in humans, and the alleles involved are shown in Infographic 12.6. Is it possible for two parents with wavy hair to have a curly-haired child? Fill in the Punnett square that follows to answer the question.

  • Determine the alleles that the mother and father should have and write the genotype of the testis and ovary cells.
  • Enter the correct allele in the eggs and sperm cells made by the parents.
  • Combine the eggs and sperm cells in all possible ways using the Punnett square.
  • Make sure to write both the genotype (allele combination) and the phenotype (type of hair texture) that would result in the zygotes produced from each fertilization event of the Punnett square.
XQYuaBuVeBw= XQYuaBuVeBw=
XQYuaBuVeBw= QCeScxLofpyrO0/awqJj6g== x2LGK6ypKBzdum1V11APFw==
XQYuaBuVeBw= x2LGK6ypKBzdum1V11APFw== KnuJ7vnPvQ3tDLlzlSFSoc6/YcA=
Table
Correct.
Incorrect.

Question 1.28

ebGYHTfyZzifTLYu2z6s1b3HE29psY6Ah3iHLjOrUMFUWxBc+gcb5mzjaqP6PULOjOdMRrQCoMMph9YqYiI6XoRVURlAt+MeBUS4YA0ZXbkQTIEs
They have a 50% chance of having a wavy-haired child.

Deduce a person’s genotype for the ABO blood type gene based on the blood types of the person’s family members.

Question 1.29

What are the three ABO blood type alleles?

kxeqpWJuMf4=, jE2JFFEMYDU=, and qJrV8HIdNts=

Correct.
Incorrect.

Question 1.30

RoZZX9Tqf77drgjiianIX+KZ69C1osjwsuwrtvJMz+jFw4qjhzW9emwpCxvrplIA
A and B are codominant.

Question 1.31

Using pedigrees, Punnett Squares or both, determine Person X’s ABO blood type genotype based on the three facts that follow:

X+IMExZp7YDR5lVsJvF/6WwpURVf6ApRZ7SUwlnRBQ3AaShNdjbxz6M5XfI=
So the genotype would be either BB or BO.

Question 1.32

/TJwIRTkLa4QAI0U235FVC0auiZU2bV0J3H93BRPaMFh1zwW2pNkE72EYWCJoSpg1K50wN5DTKo=
The parent’s genotype would be either AA or AO. Since we know that Person X has type B blood, not AB or A, we can assume that Person X received an O allele from a parent. So Person X’s genotype is likely BO.

Question 1.33

1WyI0wsbF4KfmKehDqTUeBY1F4+TS8N226xUTM+Tt4xLfR4OAcOj/NMbriwvNSP7If4DY5p64RM=
Having the OO genotype, the child must have received an O allele from each parent. Thus Person X’s genotype must be BO.

Compare and contrast complete dominance, incomplete dominance, and codominance.

Question 1.34

ht2CR2Y9cjj4ivU+JZsbHXaBFyTUFzIxmXccaOejmaAg98InDvL2jSXkbnoZHJ91jyptEdfrVj/vX6DEEB2rqDCtNeO9z3t+GHIQW93K8m5eDH/2GJhB/41/bXkvcudgF9yqz+n30PdVU6IgYldh9W+/tCX6mL67zR329wrSiTRf5f8qGQ0wCotEPjzUG+xJMUEcyb4qZsK3DnrPqUOYDbOGsQVny5ydJ70yqQ7OBBQ6piv272quwVnOpfU6GW4W0855c3TB7eZvOHZRBFEFXQsy/3lmH91tvdfLOgNrX9y71ZMu6opljN3G7ua8veG/8KwC6NJv3uG0t5FxfofybtHyt19+KPlyrTf4V9CLLq8KQj60
Complete dominance, incomplete dominance, and codominance can largely be defined by which gene products (proteins) affect phenotype. For example, in Huntington disease (H, disease; h, normal), a complete dominance trait, the genotypes HH and Hh both exhibit the disease. The protein that is produced from the mutant allele H masks the function of the protein produced by the normal allele h, so both homozygous dominant and heterozygous genotypes have the disease.

In the case of hair texture, an incomplete dominance trait, both alleles (C, curly and c, straight) produce functional proteins. The result is an intermediate phenotype of not quite curly but not quite straight hair, or wavy hair. If a trait is classified as incomplete dominant, neither allele product (protein) is fully dominant over the other, but one protein typically has a greater effect on phenotype than the other.

For traits that are codominant, like blood type (A, B, and O), the proteins produced by alleles A and B, for example, contribute equally to the phenotype of the organism. In this case, the red blood cell would have both A and B markers on the cell surface. Neither allele is dominant over the other.

Differentiate between polygenic and multifactorial inheritance.

Question 1.35

J0K3JVT+1SeVj3fUCVfKJ6yNLYrNG6+UcfRMluIy7RyKiYqaMt0ya6taXy64jbbqjL6JrZIazKd/TtZhVUzw2pcKvGlZ/42ohT9C90I9SvQ/nqhcbBu7bK2prgH2MLVZ3XFtGIjMMGrCuu+Z4nROa0UzqqjcpHs2HrwBUZ2U74ONnfV30yZYurNu51yUpm2MhFLc3zMoNFm8oTyqtV0nPyLErMK6CIXUHezDDjg48OXDfHXbKSyXZPBj+rgLAEVd
Human height is continuously variable, meaning that height is an unbroken range of phenotypes rather than discrete groups of phenotypes. In other words, if you look at the heights of your classmates, it is likely that you will find a wide range of heights, not people who are either 5 feet 4 inches or 5 feet 8 inches tall. The main reason for this phenomenon is that height is controlled by a multitude of genes and can also be influenced by environmental factors like nutrition and diet.

Question 1.36

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Polygenic traits are phenotypes that are controlled by a number of genes and their alleles. Multifactorial traits are genetic traits that are also influenced by the environment. (The genetic traits can be single gene inheritance or polygenic.) Human height is both a polygenic trait (over 20 genes being likely to contribute to height) and a multifactorial one (nutrition during youth being an environmental factor that influences height).

Question 1.37

79n+MYiYScAS5Kcpd8dBtb76qZfdM1xe1R4wwP/K91FHm6dLESx5NTuxz7uK9zeWAh528INWSm/vc28JH0cGKi576v2t00XGnO/tzrN43arAWe5y2I0C37Z1FXWlYrZtOqF0KWiRxuvV7LUuOPeYiA==
The height of a person cannot be determined by the inheritance pattern of a single gene; rather many genes contribute to a person’s height. Along with a complex inheritance pattern, height is affected by a person’s environment. For example, a child’s height may be affected by food intake in conjunction with the genes inherited from the parents. So it is impossible to predict a child’s height based solely on the height of the parents.

Explain how multifactorial inheritance works in the case of the serotonin transporter allele, stressful life events, and incidence of depression.

Question 1.38

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
From the data, it appears that the tipping point is around two stressful events for a person with two copies of the short allele. One more stressful event and the person would have a higher chance of developing depression. For a person with two copies of the long allele, the data are more complex. There does not seem to be a definitive point where one more stressful event would lead to a higher chance of developing depression.

Question 1.39

/fMsOfQtIrtUqi72um3x46JknSSWwl9OLLIdTtgoIrBWFt9lVXHraY8Tz+3wicjwAUHgtAG+RzGjfDpPuBKYIzs/9baIfaSQGpF8TTW0zRUV1k2RoXvtJrWF7YYxTJudrgn1XbVMNSlqpE6NcJjorA==
After two stressful life events, people who are homozygous for the short allele are more likely to develop depression than people who are homozygous for the long allele.

Question 1.40

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Since depression is a multifactorial trait, a person’s genotype is not the only indicator of whether a person will develop depression. Environmental factors also contribute to the likelihood of a person developing depression. So a person who is homozygous for the long allele still may develop depression if the environmental factors are strong enough.

Review Questions

Question 1.41

PIK8snIJ8AoOgkeIeuqpLRMtBLewK2/0TVJ2EYysONAhenHDX3yJ/GXRblejMIjWlucPsinNMF/Lq4dgKRKUiBuck56l3btHZn8xnEeDHgq4X9Ft4K7GUBU1LshrZQAIIWZB5Opem5UTJrGnrogg9oUxaIuqusXE1Qxc36A3hqRGjJ+nf8fw1BNooC5lG5V0//AwsYrEjjLiV+yraH1OYcxs6hPXFWJBYJ7iiCj0TZdk6zv8iV3em753zXT9BAoDPMn4+fwm/t/5nkxci34ecdNZKtZuUidaDaMF2g==
2
Try again.
Correct.
Incorrect.

Question 1.42

38xh5cgRtCz15bWn1t+Wg5WFChiClk63rWEmfjueszPNKRLZp/jbdemYlAhxd4mRZkV3plD6eDUL5x9HjeUyTb+f4iccqBjVfbbaXk3UBJUhH7B54tnkDVNaMFzzwMJ8NwWp+Sv4Oj53qOLgver39//5WUfhwlAmlBZAewzrLoGvZcQO2AP4wpMF6xc4Pssi1KyojuKsVgL16vg3rh8TaGtnpRtbbqnl8jm9F5e22gJRp8UIERH+6haWPs6FnegK1vhSJ/z1bvCebl+CQpRhdbmvFC7JpM0WLEWcrXZ4AbA/Gs0WHxzKiR+XNlpahPq02CJo484NmIi6lgxJODHrkeDcxB492N4FSW/quleXmpp58eOsufZ9Gg==
2
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Correct.
Incorrect.

Question 1.43

+DH5fq7+LOeVkiLjlfvGqLj1MMCcf/3of2zCREiznMoAMJkXODNusITD2bI4GUuSURLz4DtBpIMMgKtkduzw6Ht1Cs3nB/E8gwATPjYQyW9pdWA836iopZRoazqwkgchb7NwzlEvXv1dzkOmwnNX5pWwdMb1d1dF
2
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Correct.
Incorrect.

Question 1.44

nFAAyPnVGLz5xUVQQ3y6w3qF87Vq6yz6MgNG3grU9GztKSYtl7M4JZj3oWMKgU/QqP5z2edhhP5gDW/NTGrKvZtL12BRO1owt5l6OgNubdQXonWWPAnIdiX9YKo3g14/cdpGXA==
2
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Correct.
Incorrect.

1.4 Driving Question 3

Driving Question 3

How do numerical abnormalities of chromosomes occur, and what are the consequences of these abnormalities?

Why should you care?

Some genetic disorders are not the result of problems with single genes but with entire chromosomes. We have already looked at some chromosomal defects involving sex chromosomes such as Turner Syndrome (X0) and Klinefelter's Syndrome (XXY); both are examples of aneuploidy, which means not having the proper number of one or more particular chromosome. Aneuploidy of autosomes can also occurs, and it almost always has negative impacts. (The effects of the common sex chromosome aneuploidies are not as serious as those of autosomal aneuploidy because the Y chromosome has very few genes, and because all X chromosomes except one are usually inactivated in the cells of developing human embryos).

Most aneuploidies occur because of mistakes during meiotic cell division called nondisjunctions, in which chromosomes are not evenly separated and thus the resulting gametes have either additional or missing chromosomes. Most cases of autosomal aneuploidy result in spontaneous abortion or miscarriage of the affected embryos. The few non-terminal autosomal aneuploidies are always associated with birth defect syndromes (an association of common symptoms). The most well-known autosomal aneuploidy syndrome is Down Syndrome, which results from inhertiting an extra chromosome 21, a condition called trisomy 21.

What should you know?

To fully answer this Driving Question, you should be able to:

  1. Diagram how the chromosome number in gametes will be affected based on whether nondisjunction occurs during meiosis I or meiosis II.
  2. Predict the chromosomal makeup of a zygote if one of the gametes that produced it were aneuploid.
  3. Explain how constructing a karyotype of a fetus can determine if there is any incidence of aneuploidy, specifically how examining a fetal karyotype can determine if the child will have Down syndrome.

Infographic Focus:

The infographics most pertinent to the Driving Question are 12.12 and 12.13.

Question Test Your Vocabulary

Choose the correct term for each of the following definitions:

Term Definition
mn+DwLWejFIZ+He3zG1Tux/eourRfQS/m+38IbV9eh0yZhov7iHJdmtVDt8PwDhgHk1UO7vm89ZsMiAlVA0rdX/6Ivs= The failure of chromosomes to separate accurately during cell division; nondisjunction in meiosis leads to aneuploidy gametes.
/uMcigvOW9jad7R0l6KwG+NVZnde/jdog3GA7I5Ys39LFh5CgED6EjPocFcfUwiaACVUy2uO42TTlF3GrR+rwdHMGXA= The chromosomal makeup of cells. Karyotype analysis can be used to detect trisomy 21 prenatally.
t7/HEEVEG/YavES5Vo2zzHld7SBl8CR8ptqb8NZAu4Q0lrd7OJ+Lco9X1+2WpDp0ojVYYmuAYg3OloVWcaSYWE7+tqY= An abnormal number of one or more chromosomes (either extra or missing copies).
+Di3d/0eTe/KD18YwIN3Tg+VscAW33k1D6MiiFt1H3O8NnMvdMxbWbUK1V+kCMctlyckq0EGIKT/R8ctpB76CJLuV4I= Carrying an extra copy of chromosome 21, also known as Down syndrome.
2skRarzVcxVlxQLOT8oIHn3LGx0ajl+h3z6V6uzY2MaYiGYsxVn5RshvPKQAFFJwoZQ++DLyZ1Bm6CbnyxLce13VowM= A procedure that removes fluid surrounding the fetus to obtain and analyze fetal cells to diagnose genetic disorders.
Table
9
Try again.
Correct.
Incorrect.

Diagram how the chromosome number in gametes will be affected based on whether nondisjunction occurs during meiosis I or meiosis II.

Question 1.45

Following the example of Infographic 12.12, trace the path of homologous pairs of chromosomes through meiosis twice. The first time assume nondisjunction occurs during meiosis I, and the second time assume nondisjunction occurs during meiosis II.

How many gametes are affected if the nondisjunction happens during:

meiosis I? h4XZagboIgc=

meiosis II? XvVM00l89Is=

Correct.
Incorrect.

Predict the chromosomal makeup of a zygote if one of the gametes that produced it was aneuploid.

Question 1.46

LXK4jfHI/qlpHW1XHvBshsf7raIH9JlCUGOBu72By85UCE6YlqQYM9H5Tmgfry4In2kZBZzjl7jTzaDLU8VXHptEUlUc3O1+meC3hSxnnP047RcU+fP2AgO2lZ1QqNGnmk24A+jQyprewGWqygsPPsjzeUGNOv3wSLvjwdVDBszPJdLE19DiYiy/5A1ACJHqhRVRRZPYBOOTR6hCw47FpmQ3X5zXowmklKQ00rIrlKOlP1sr
If the abnormal gamete had three chromosomes, the zygote would have five. If the abnormal gamete had one chromosome, the zygote would have three.

Explain how constructing a karyotype of a fetus can determine whether there is any incidence of aneuploidy, specifically how examining a fetal karyotype can determine whether the child will have Down syndrome.

Question 1.47

The karyotype above (from Infographic 12.13) is not the way the chromosomes look in an actual cell. It is the result of a researcher painstakingly arranging images of all of the chromosomes obtained from a sampled fetal cell in descending order by size, matching up homologous pairs. This allows for the detection of extra or missing chromosomes.

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It is an extra copy of chromosome 21, so the fetus has three copies of chromosome 21 (trisomy 21).

Question 1.48

XT9F19vS/wRTKQEO6L/ja7E7X3M8MpLGPHoHjfsPpL+/KGkUiUPt4ZgQfVokXdKFvsDw31sc1Gkx1qR6oLWoGEFgwj0Qx7yaOaBqeyIT9+NbjfHXVeutaKB58PdFA2bu9oZz7H4uP99n5UgFUKRRHfL6AgljMKS6SvF78ayvh5vbd1kYXh6kRWlI2dEs7t6GMhYIbbrw5SDlozX2P5rV6Sqleh0F3ZyANDNlEPxXocyrHsiRm+z6gVJ1847ET20LrXBCQ25GCaHCFUfhj8RZW6wSX/f7j1RHDMOlgJkFB84saIuljJu32qU6fdpv6s3ULsh6jHk5UlgXI+PrlacoJNUYbh1/diDLk7Xl5O87jVH09g6etubr/4CJCuhID3OKakICBRWzMGc=
Because chromosome 21 is the second smallest chromosome, there are relatively few genes encoded in its DNA. Thus, fewer genes are affected by having three copies in the cells.

Review Questions

Question 1.49

Q1/gRGiBAlMZJfrGtpw3FuDlKlHbEAEbtbO9TOx6dK36DQcGGs1wnY018V1lbfqLJKBsHqMgluNw047eztgCQPGslsN5BmN2YgmJfZqi/CLhqbizTBOsiTLNWA/1Iw+kX4WpJStZVh6zuxUJl1tefXAMSRdsQjRipWxPZrPjL4x+SfTwZJguw7uTMgtSBdXes/fDLNWoAUMEau2uR6/GdMghTDDfYSi53jUDnVe4kI36D/9jWKU+mqj7xDLlZIR7Bcw0M23f6dhhY8dx1fpHrIb+gPvjpHOx9rdfiA==
2
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Correct.
Incorrect.

Question 1.50

rt107HHc9vG9gnyjw1BTPySjfGhVEQtS/v4NCoSDSxR6CoO2Cq3oECAKyqYoC9AfF8be9jMXWPrb9Euh4j/xkItChDakcpoYPzx7TKRv6OpUzhymv8qqHS2nbF/R0N6QFzob8izGAHsUQhc3y7x1n9K9dt809nMWNiXu4Z3cU5nHSwo8myZe+CnEKOlbsBdyUf+fUcq+lW1pYhKyDCv0WlEl2RLtHmC3bkAZmAz3nm8nhsBOYMDtL+KaAGe3mJQQrBH9RGfmCrw=
2
Try again.
Correct.
Incorrect.