Concepts and Vocabulary
True or False If a twice differentiable vector function \(\mathbf{r}(t)=x(t)\mathbf{i}+y(t)\mathbf{j}+z(t)\mathbf{k}\) represents the position of a particle moving along a smooth curve, then the velocity vector is \(\mathbf{v}( t)\;=\;\mathbf{r}^{\prime} ( t) \) and the acceleration vector is \(\mathbf{a}( t)\;=\; \mathbf{r}^{\prime \prime} ( t) .\)
True or False If a particle moving along a smooth curve traced out by a twice differentiable vector function \(\mathbf{r}= \mathbf{r}( t) \) travels at a constant speed, then the acceleration of the particle is directed along the unit tangent vector \(\mathbf{T}.\)
True or False The acceleration vector \(\mathbf{a}= \mathbf{a}( t) \) of a particle moving along a smooth curve traced out by a twice differentiable vector function \(\mathbf{r}=\mathbf{r}( t)\) can be written as the sum of two orthogonal vectors: one vector in the direction of the velocity and the other vector perpendicular to the direction of the velocity.
When the acceleration vector \(\mathbf{a}( t) \mathbf{ \ }\) of a particle moving along a smooth curve is written as \(\mathbf{a} (t)=v^{\prime} (t)\mathbf{T}(t)+\left[ v( t) \right] ^{2}\kappa \mathbf{N}(t),\) then \(a_{\mathbf{T}}=v^{\prime} ( t) \) is called the _____ component and \(a_{\mathbf{N}}=\left[ v( t) \right] ^{2}\kappa \) is called the _____ component of the acceleration vector \(\mathbf{a}\).
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Skill Building
In Problems 5–10:
\(\mathbf{r}(t)=t\mathbf{i}+t^{2}\mathbf{j}\)
\(\mathbf{r}(t)=t\mathbf{i}-t^{3}\mathbf{j}\)
\(\mathbf{r}(t)=(t^{2}+1)\mathbf{i}+(1-t)\mathbf{j}\)
\(\mathbf{r}(t)=t^{3}\mathbf{i}+3t\mathbf{j}\)
\(\mathbf{r}(t)= {4t}\mathbf{i}-{t^{3}}\mathbf{j}\)
\(\mathbf{r}(t)=t^{3}\mathbf{i}+\dfrac{1}{2}t\mathbf{j}\)
In Problems 11–16, find the velocity, acceleration, and speed of a particle whose motion is along the space curve traced out by the vector function \(\mathbf{r}=\mathbf{r}( t) \).
\(\mathbf{r}(t)=t^{2}\mathbf{i}+t\mathbf{j}-3t^{3}\mathbf{k}\)
\(\mathbf{r}(t)=( t+1) \mathbf{i}+6t\mathbf{j}+t^{2}\mathbf{k}\)
\(\mathbf{r}(t)=\sqrt{16-t^{2}}\kern.7pt\mathbf{i}+t^{2}\mathbf{j}+t\mathbf{k}\)
\(\mathbf{r}(t)=\dfrac{1}{t^{2}}\mathbf{i}+\dfrac{t+1}{t^{2}}\mathbf{j}+t\mathbf{k}\)
\(\mathbf{r}(t)=2\cos t\mathbf{i}+\sin t\mathbf{j}+t\mathbf{k}\)
\(\mathbf{r}(t)=t\mathbf{i}+\sin({4}t)\mathbf{j}+cos({4}t)\mathbf{k}\)
In Problems 17 and 18:
\(\mathbf{r}(t)=\sin t\mathbf{i}+\cos t\mathbf{j}+\sin (2t) \mathbf{k,}\quad t=\dfrac{\pi }{2}\)
\(\mathbf{r}(t)=\sin t\mathbf{i}+\cos t\mathbf{j}+\sqrt{t}\mathbf{k,}\quad t=\pi \)
In Problems 19–26, a particle of mass \(m\) is moving along the curve traced out by the vector function \(\mathbf{r}=\mathbf{r}( t) \).
\(\mathbf{r}(t)=e^{t}\mathbf{i}+e^{-t}\mathbf{j}\)
\(\mathbf{r}(t)=e^{2t}\mathbf{i}+e^{-t}\mathbf{j}\)
\(\mathbf{r}(t)=t\mathbf{i}+e^{t}\mathbf{j}\)
\(\mathbf{r}(t)=t\mathbf{i}+\ln (1+t)\mathbf{j}\)
\(\mathbf{r}(t)=3\sin ( 2t) \mathbf{i}+3\cos ( 2t) \mathbf{j}\)
\(\mathbf{r}(t)=4\sin t\mathbf{i}-4\cos t\mathbf{j}\)
\(\mathbf{r}(t)=2\cos t\mathbf{i}-3\sin t\mathbf{j}\)
\(\mathbf{r}(t)=-\cos ( 3t) \mathbf{i}+2\sin ( 3t) \mathbf{j}\)
In Problems 27–44:
\(\mathbf{r}(t)=2t\mathbf{i}+(t+1)\mathbf{j}\)
\(\mathbf{r}(t)=(1-3t)\mathbf{i}+2t\mathbf{j}\)
\(\mathbf{r}(t)=e^{t}\mathbf{i}+e^{2t}\mathbf{j}\)
\(\mathbf{r}(t)=e^{-t}\mathbf{i}+e^{-2t}\mathbf{j}\)
\(\mathbf{r}(t)=2\sin t\mathbf{i}+\cos t\mathbf{j}\)
\(\mathbf{r}(t)=2\cos t\mathbf{i}+3\sin t\mathbf{j}\)
\(\mathbf{r}(t)=(1-3t)\mathbf{i}+2t\mathbf{j}-(5+t)\mathbf{k}\)
\(\mathbf{r}(t)=(2+t)\mathbf{i}+(2-t)\mathbf{j}+3t\mathbf{k}\)
\(\mathbf{r}(t)=t\mathbf{i}+t^{2}\mathbf{j}+t^{3}\mathbf{k}\)
\(\mathbf{r}(t)=\dfrac{t^{2}}{t+1}\mathbf{i}+\dfrac{1}{t+1}\mathbf{j}+\dfrac{t}{t+1}\mathbf{k}\)
\(\mathbf{r}(t)=3\mathbf{i}+\cos t\mathbf{j}+\sin t\mathbf{k}\)
\(\mathbf{r}(t)=t\mathbf{i}+\sin t\mathbf{j}+\cos t\mathbf{k}\)
\(\mathbf{r}(t)=\ln t\mathbf{i}+\sqrt{t}\mathbf{j}+t^{3/2}\mathbf{k}\); \(t>0\)
\(\mathbf{r}(t)=\cos ( 2t) \mathbf{i}+\sin ( 2t) \mathbf{j}-5\mathbf{k}\)
\(\mathbf{r}(t)=e^{t}\cos t\mathbf{i}+e^{t}\sin t\mathbf{j}+e^{t}\mathbf{k}\)
\(\mathbf{r}(t)=e^{-t}\cos t\mathbf{i}+e^{-t}\sin t\mathbf{j}-e^{-t}\mathbf{k}\)
\(\mathbf{r}(t)=a\cos t\mathbf{i}+b\sin t\mathbf{j}+ct\mathbf{k}\) ; \(a>0\), \(b>0\), \(c>0\)
\(\mathbf{r}(t)=\cosh t\mathbf{i}+\sinh t\mathbf{j}+t\mathbf{k}\)
Applications and Extensions
Velocity and Acceleration Find the velocity and acceleration of a particle moving on the cycloid $$\mathbf{r}( t)\;=\;[ \pi t-\sin ( \pi t) ]\kern.7pt \mathbf{i}\,+ [ 1-\cos ( \pi t) ]\,\mathbf{j}\kern.7pt$$
Velocity and Acceleration
Acceleration A particle moves along the path \(y=3x^{2}-x^{3}\) with the horizontal component of the velocity equal to \(\dfrac{1}{3}\). Find the acceleration at the points where the velocity \(\mathbf{v}\) is horizontal. Graph the motion and indicate \(\mathbf{v}\) and \(\mathbf{a}\) at these points.
Show that if the speed of a particle along a curve is constant, then the velocity and acceleration vectors are orthogonal.
If a particle moves along the graph of \(y=f(x)\), show that \(a_{\mathbf{N}}=0\) at a point of inflection of the graph.
Suppose that the vector function \(\mathbf{r}(t)=e^{t}\mathbf{i} +e^{-t}\mathbf{j}\) gives the position of a particle at time \(t\).
A particle moves along the graph \(y=\dfrac{1}{2}x^{2}\) with constant speed \(v_{0}=2\). Find \(a_{\mathbf{T}}\) and \(a_{\mathbf{N}}\) in terms of \(x\) alone at a general point \(\left( x,\dfrac{1}{2}x^{2}\right) \) on the graph.
If the motion of a particle is along the curve traced out by \( \mathbf{r}(t)=\alpha \cosh t\mathbf{i}+\beta \sinh t\mathbf{j}\), where \( \alpha >0\) and \(\beta >0\), show that the force acting on the particle is in the direction of \(\mathbf{r}=\) \(\mathbf{r}(t)\).
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Centripetal Force Refer to Example 5.
Frictional Force A race car with mass \(1000\) kg is driven at a constant speed of \(200\) km/h around a circular track whose radius is \(75\) m. What frictional force must be exerted by the track on the tires to keep the car from skidding?
Particle Collider The Large Hadron Collider (LHC), buried 100 m beneath Earth’s surface, is located near Geneva, Switzerland, and spans the border between France and Switzerland. The LHC is 26,659 m in circumference and, at full power, protons travel at a speed of \( 299{,}792{,}455.3\) m/s (99.9999991% the speed of light) around the circle. Find the magnitude of force necessary to keep a proton of mass \(m\) moving at this speed.
Source: http://public.web.cern.ch.
Particle Collider At the Fermi National Accelerator Laboratory in Batavia, Illinois, protons were accelerated along a circular route with radius \(1\) km. Find the magnitude of the force necessary to give a proton of mass \(m\) a constant speed of \(280{,}000\) km/s.
Magnitude of a Force Find the maximum magnitude of the force acting on a particle of mass \(m\) whose motion is along the curve \(\mathbf{r} (t)=4\cos t\mathbf{i}-2\cos ( 2t) \mathbf{j}\).
Curvature of the Path of a Golf Ball A golf ball is hit with an initial speed \(v_{0}\) at an angle \(\theta \) to the horizontal and travels on a smooth curve traced out by the vector function \[ \mathbf{r}=\mathbf{r}(t)= ( v_{0}\cos \theta ) t\mathbf{i}+\left[ ( v_{0}\sin \theta ) t -\dfrac{1}{2}gt^{2}\right] \mathbf{j}, \]
where \(g=9.8{ m}/{ s}^{2}\) and \(0\leq \theta \leq \dfrac{\pi }{2}\).
Velocity A particle moves on the circle \(x^{2}+y^{2}=1\) so that at time \(t\geq 0\) the position is given by the vector \begin{equation*} \mathbf{r}(t)=\frac{1-t^{2}}{1+t^{2}}\mathbf{i}+\frac{2t}{1+t^{2}}\mathbf{j} \end{equation*}
Velocity The position of a particle at time \(t\geq 0\) is given by \(\mathbf{r}( t)\;=\;e^{-t}\cos t\mathbf{i}+e^{-t}\sin t \mathbf{j}\).
Oscillating Motion Suppose a particle moves along the curve traced out by \(\mathbf{r}(t)=4\cos t\mathbf{i}-2\cos ( 2t) \mathbf{j}\).
If \(\mathbf{r}^{\prime} (t)=\mathbf{b}\times \mathbf{r}(t)\) for all \(t\), where \(\mathbf{b}\) is a constant vector, show that the acceleration \(\mathbf{a}(t)\) is perpendicular to \(\mathbf{b}\) and that the speed is constant.
Mars Orbit NASA's Odyssey orbiter has a new mission to relay directly back to Earth the UHF telemetry taken by Curiosity, which landed on Mars on August 6, 2012. Odyssey is in a 'near-Mars' orbit at a height of \(400\textrm {km}\) above its surface. Find the speed of the Odyssey if the acceleration due to gravity on Mars is \(3.71\textrm{ m}/\textrm{s}^{2}\) and Mars' radius is \(3390\textrm{ km}\).
Physics The power expended by a force \(\mathbf{F}(t)\) acting on an object of mass \(m\) with velocity \(\mathbf{v}(t)\) is the dot product \[ \hbox{Power}=\mathbf{F}(t)\,{\cdot}\, \mathbf{v}(t) \] The kinetic energy of an object of mass \(m\) and velocity \(\mathbf{v}(t)\) equals one-half the product of its mass times the square of its speed: \[ \hbox{Kinetic energy}=\frac{1}{2}m\left\Vert \mathbf{v}(t)\right\Vert ^{2} \] Show that the power of an object equals the rate of change of its kinetic energy with respect to time.
Momentum In classical mechanics, the momentum \(\mathbf{p}(t)\) of an object of mass \(m\) at time \(t\) is defined as \(\mathbf{p}(t)=m\mathbf{v}(t)\), where \(\mathbf{v}(t)\) is the velocity of the object at time \(t\). Show that force equals the rate of change of momentum with respect to time.
Angular Momentum The torque \({\tau }\) (Greek letter tau) produced by a force \(\mathbf{F}(t)\) acting on an object whose position at time \(t\) is \(\mathbf{r}(t)\) is defined as \({\tau }(t)=\mathbf{r}(t)\times \mathbf{F}(t)\). Torque measures the twist imparted on the object by the force. See the figure below. The angular momentum \(\mathbf{L}\) of an object of mass \(m\) and velocity \(\mathbf{v}(t)\) whose position at time \(t\) is \(\mathbf{r}(t)\) is \(\mathbf{L}(t)=\mathbf{r} (t)\times m\mathbf{v}(t)\). Show that the rate of change of angular momentum with respect to time equals the torque.
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Central Fields of Force A central field of force \(\mathbf{F}(t)\) is one whose direction is parallel to that of the position \(\mathbf{r}=\mathbf{r}(t)\) of the object it acts upon; that is, \(\mathbf{F}(t)=u(t)\mathbf{r}(t)\), where \(u(t)\) is a scalar function. Show that a central field of force produces zero torque.
Hydrogen Atom The Bohr model of an atom views it as a miniature solar system, with negative electrons in circular orbits around the positive nucleus. A hydrogen atom consists of a single electron in orbit around a single proton. The electric force \(F_{\rm {elec}}\) that the proton of charge \(e=1.60\times 10^{-19}\textrm {C}\) exerts on the electron, also of charge \(e=1.60\times 10^{-19}\textrm {C}\), is \(F_{\rm {elec}}=\dfrac{ke^{2}}{ r^{2}}\), where \(r\) is the distance in meters between the nucleus and the electron and \(k=9.0\times 10^{9}\textrm {N}\,{\cdot} \textrm {m}^{2}\!/\textrm {C}\) is a constant. Apply Newton's Second Law of Motion to the electron in a hydrogen atom and show that its speed is \(v=\sqrt{\dfrac{ke^{2}}{mr}}\), where \( m=9.11\times 10^{-31}\textrm {kg}\) is the mass of the electron.
Analyzing Forces Use the formula \begin{equation*} \mathbf{F}=m\mathbf{a}=m\frac{dv}{dt}\mathbf{T}+mv^{2}\kappa\mathbf{N} \end{equation*} to discuss the forces on a passenger in a car.
Analyzing Motion Suppose \(\mathbf{r}=\mathbf{r}(t)\) gives the position of a particle at time \(t\). If the normal component of acceleration equals \(0\) at any time \(t\), explain why the motion of the particle must be in a straight line.
Suppose the position of a particle in space is given by the vector function \(\mathbf{r}=\mathbf{r}( t) \). Show that if \( \mathbf{r}=\mathbf{r}( t) \) lies on a sphere, then the tangent vector is always orthogonal to \(\mathbf{r}=\mathbf{r}( t) \mathbf{ }\).
Challenge Problems
Coriolis Acceleration A particle moves on a disk from the center directly toward the edge. See the figure. The disk has radius 1 and is revolving in the counterclockwise direction at a constant angular speed \(\omega \), so the position of a point on the edge of the disk is given by \(\mathbf{R}(t)=\cos ( \omega t) \mathbf{i}+\sin ( \omega t) \mathbf{j}\). Suppose the position of the particle at time \(t\) is \( \mathbf{r}( t)\;=\;t\mathbf{R}( t) \).
(a) Show that the velocity \(\mathbf{v}\) of the particle is \begin{equation*} \mathbf{v}=\cos ( \omega t) \mathbf{i}+\sin ( \omega t) \mathbf{j}+t\mathbf{v}_{\mathbf{d}} \end{equation*}
where \(\mathbf{v}_{\mathbf{d}}=\mathbf{R}^{\prime} (t)\) is the velocity of the rotating disk.
(b) Also show that the acceleration \(\mathbf{a}\) of the particle is \begin{equation*} \mathbf{a}=2\mathbf{v}_{\mathbf{d}}+t\mathbf{a}_{\mathbf{d}} \end{equation*}
where \(\mathbf{a}_{\mathbf{d}}=\mathbf{R}^{\prime \prime} (t)\) is the acceleration of the rotating disk. The extra term \(2\mathbf{v}_{\mathbf{d}}\) is called the Coriolis acceleration, which results from the interaction of the rotation of the disk and the motion of the particle on the disk.
Coriolis Acceleration Refer to Problem 72.
(a) Find the velocity and acceleration of a particle revolving on a rotating disk according to \begin{equation*} \mathbf{r}(t)=t^{2}\cos ( \omega t) \mathbf{i}+t^{2}\sin ( \omega t) \mathbf{j} \end{equation*}
(b) What is the Coriolis acceleration?
Suppose a curve \(C\) is traced out by the vector function \(\mathbf{r}=\mathbf{r}(t)\). Find two nonparallel vectors that are orthogonal to \(\mathbf{T}(t)\) other than the principal unit normal vector. Assume \(\mathbf{T}(t)\neq \mathbf{0}\) and \(\mathbf{N}(t)\neq \mathbf{0}\).
Let \(\mathbf{u}_{r}=\cos \theta \mathbf{i}+\sin \theta \mathbf{j}\) and \(\mathbf{u}_{\theta }=-\!\sin \theta \mathbf{i}+\cos \theta \mathbf{j}\).
Express the velocity \(\mathbf{v}\) and acceleration \(\mathbf{a}\) in terms of \(\mathbf{u}_{r}\) and \(\mathbf{u}_{\theta }\) for a motion along the polar curve \(r=2+\cos t\), where \(\theta\;=\;2t\).
Find polar coordinate equations for \(\mathbf{r}(t)=e^{2t}\cos t\mathbf{i}+e^{2t}\sin t\mathbf{j}\) and express the velocity \(\mathbf{v}\) and acceleration \(\mathbf{a}\) in terms of \(\mathbf{u}_{r}\) and \(\mathbf{u}_{\theta }\).