Concepts and Vocabulary
True or False The derivative of a product is the product of the derivatives.
If \(F( x) =f(x) g(x)\), then \(F' ( x)\) =______.
True or False \(\dfrac{d}{dx}x^{n}=nx^{n+1}\), for any integer \(n\).
If \(f\) and \(g\neq 0\) are two differentiable functions, then \(\dfrac{d}{dx}\!\left(\dfrac{f(x)}{g(x)}\right)\) = ______.
True or False \(f( x) =\dfrac{e^{x}}{x^{2}}\) can be differentiated using the Quotient Rule or by writing \(f(x) =\dfrac{e^{x}}{x^{2}}=x^{-2}e^{x}\) and using the Product Rule.
If \(g\neq 0\) is a differentiable function, then \(\dfrac{d}{dx} \left[\dfrac{1}{g(x) }\right]\) = ______.
If \(f(x) =x\), then \(f'' ( x)\) =______.
When an object in rectilinear motion is modeled by the function \(s=s(t)\), then the acceleration \(a\) of the object at time \(t\) is given by \(a=a(t)\)= ______.
Skill Building
In Problems 9-40, find the derivative of each function.
\(f( x) =xe^{x}\)
\(f( x) =x^{2}e^{x}\)
\(f(x)=x^{2}(x^{3}-1)\)
\(f(x)=x^{4}(x+5)\)
\(f(x)=(3x^{2}-5)(2x+1)\)
\(f(x)=(3x-2)(4x+5)\)
\(s(t)=(2t^{5}-t)(t^{3}-2t+1)\)
\(F(u)=(u^{4}-3u^{2}+1)(u^{2}-u+2)\)
\(f( x) =( x^{3}+1) ( e^{x}+1)\)
\(f( x) =( x^{2}+1) (e^{x}+x)\)
\(g(s)={\dfrac{2s}{s+1}}\)
\(F(z)={\dfrac{z+1}{2z}}\)
\(G(u)={\dfrac{1-2u}{1+2u}}\)
\(f(w)={\dfrac{1-w^{2}}{1+w^{2}}}\)
\(f(x)={\dfrac{4x^{2}-2}{3x+4}}\)
\(f(x)={\dfrac{-3x^{3}-1}{2x^{2}+1}}\)
\(f( w) =\dfrac{1}{w^{3}-1}\)
\(g( v) =\dfrac{1}{v^{2}+5v-1}\)
\(s(t)=t^{-3}\)
\(G(u)=u^{-4}\)
\(f(x) =-\dfrac{4}{e^{x}}\)
\(f( x) =\dfrac{3}{4e^{x}}\)
\(f(x)={\dfrac{10}{x^{4}}+\dfrac{3}{x^{2}}}\)
\(f(x)={\dfrac{2}{x^{5}}-\dfrac{3}{x^{3}}}\)
\(f(x)=3x^{3}-{\dfrac{1}{3x^{2}}}\)
\(f(x)=x^{5}-{\dfrac{5}{x^{5}}}\)
\(s(t)={\dfrac{1}{t}-\dfrac{1}{t^{2}}+\dfrac{1}{t^{3}}}\)
\(s(t)={\dfrac{1}{t+2}+\dfrac{1}{t^{2}}+\dfrac{1}{t^{3}}}\)
\(f( x) =\dfrac{e^{x}}{x^{2}}\)
\(f( x) =\dfrac{x^{2}}{e^{x}}\)
\(f( x) =\dfrac{x^{2}+1}{xe^{x}}\)
\(f( x) =\dfrac{xe^{x}}{x^{2}-x}\)
In Problems 41-54, find \(f^\prime\) and \(f''\) for each function.
\(f(x)=3x^{2}+x-2\)
\(f(x)=-5x^{2}-3x\)
\(f( x)=e^{x}-3\)
\(f( x) =x-e^{x}\)
\(f( x) =(x+5)e^{x}\)
\(f( x) =3x^{4}e^{x}\)
\(f( x) =(2x+1)(x^{3}+5)\)
\(f( x) =(3x-5)(x^{2}-2)\)
\(f(x)=x+\dfrac{1}{x}\)
\(f(x)=x-\dfrac{1}{x}\)
\(f(t)=\dfrac{t^{2}-1}{t}\)
\(f(u)=\dfrac{u+1}{u}\)
\(f( x) =\dfrac{e^{x}+x}{x}\)
\(f( x) =\dfrac{e^{x}}{x}\)
Find \(y^\prime\) and \(y''\) for (a) \(y={\dfrac{1}{x}}\) and (b) \(y={\dfrac{2x-5}{x}}\).
Find \(\dfrac{dy}{dx}\) and \(\dfrac{d^{2}y}{dx^{2}}\) for (a) \(y={\dfrac{5}{x^{2}}}\) and (b) \(y={\dfrac{2-3x}{x}}\).
Rectilinear Motion In Problems 57-60, find the velocity \(v\) and acceleration \(a\) of an object in rectilinear motion whose distance \(s\) from the origin at time \(t\) is modeled by \(s=s( t)\).
\(s(t) =16t^{2}+20t\)
\(s( t) =16t^{2}+10t+1\)
\(s( t) =4.9t^{2}+4t+4\)
\(s(t) =4.9t^{2}+5t\)
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In Problems 61-68, find the indicated derivative.
\(f^{(4)}(x)\) if \(f(x)=x^{3}-3x^{2}+2x-5 \)
\(f^{(5)}(x)\) if \(f(x)=4x^{3}+x^{2}-1\)
\({\dfrac{d^{8}}{dt^{8}}\!\left(\dfrac{1}{8}t^{8}-\dfrac{1}{7} t^{7}+t^{5}-t^{3}\right) }\)
\({\dfrac{d^{6}}{dt^{6}}(t^{6}+5t^{5}-2t+4)}\)
\(\dfrac{d^{7}}{du^{7}}( e^{u}+u^{2})\)
\(\dfrac{d^{10}}{du^{10}}( 2e^{u})\)
\(\dfrac{d^{5}}{dx^{5}}( -e^{x})\)
\(\dfrac{d^{8}}{dx^{8}}( 12x-e^{x})\)
In Problems 69-72:
\(f(x)={\dfrac{x^{2}}{x-1}}\) at \({\left(\! -1,-\dfrac{1}{2} \right)\! }\)
\(f(x)={\dfrac{x}{x+1}}\) at \({( 0,0) }\)
\(f(x)={\dfrac{x^{3}}{x+1}}\) at \({\left( 1,\dfrac{1}{2}\right) }\)
\(f(x)={\dfrac{x^{2}+1}{x}}\) at \({\left( 2,\dfrac{5}{2}\right)\! }\)
In Problems 73-80:
\(f( x) =( x+1) ( x^{2}-x-11)\)
\(f( x) =( 3x^{2}-2) ( 2x+1)\)
\(f(x)={\dfrac{x^{2}}{x+1}}\)
\(f(x)={\dfrac{x^{2}+1}{x}}\)
\(f( x) =xe^{x}\)
\(f( x) =x^{2}e^{x}\)
\(f( x) =\dfrac{x^{2}-3}{e^{x}}\)
\(f( x) =\dfrac{e^{x}}{x^{2}+1}\)
In Problems 81 and 82, use the graphs to determine each derivative.
Let \(u( x) =f( x) \cdot g( x)\) and \(v( x) =\dfrac{g( x) }{f( x)}\).
(a) \(u' ( 0)\) | (b) \(u' ( 4)\) |
(c) \(v' ( -2)\) | (d) \(v' ( 6)\) |
(e) \(\dfrac{d}{dx}\left( \dfrac{1}{f( x) }\right)\)at \(x=-2\) | (f) \(\dfrac{d}{dx}\left( \dfrac{1}{g( x) }\right)\) at \(x=4\) |
Let \(F( t) =f( t) \cdot g( t)\) and \(G( t) =\dfrac{g( t) }{f( t) }\).
(a) \(F^\prime ( 0)\) | (b) \(F^\prime ( 3)\) |
(c) \(F^\prime ( -4)\) | (d) \(G^\prime ( -2)\) |
(e) \(G^\prime ( -1)\) | (f) \(\dfrac{d}{dt}\left( \dfrac{1}{f( t) }\right)\) at \(t=3\) |
Applications and Extensions
Movement of an Object An object is propelled vertically upward from the ground with an initial velocity of \(39.2{\text{m/s}}\). The distance \(s\) (in meters) of the object from the ground after \( t\) seconds is \(s= s(t)= -4.9t^{2}+39.2t\).
Movement of a Ball A ball is thrown vertically upward from a height of \(6{\text{ft}}\) with an initial velocity of \(80\text{ft/s}\). The distance \(s\) (in feet) of the ball from the ground after \(t\) seconds is \(s= s(t)=6+80t-16t^{2}\).
Environmental Cost The cost \(C\), in thousands of dollars, for the removal of a pollutant from a certain lake is given by the function \(C( x) =\dfrac{5x}{110-x},\) where \(x\) is the percent of pollutant removed.
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Investing in Fine Art The value \(V\) of a painting \(t\) years after it is purchased is modeled by the function \[ \begin{eqnarray*} V( t) =\dfrac{100t^{2}+50}{t}+400, 1 ≤ t ≤ 5\\[-19pt] \end{eqnarray*} \]
Drug Concentration The concentration of a drug in a patient’s blood \(t\) hours after injection is given the function \(f( t) =\dfrac{0.4t}{2t^{2}+1}\) (in milligrams per liter).
Population Growth A population of 1000 bacteria is introduced into a culture and grows in number according to the formula \(P( t) =1000\left( 1+\dfrac{4t}{100+t^{2}}\right)\), where \(t\) is measured in hours.
Economics The price-demand function for a popular e-book is given by \(D( p) =\dfrac{100,000}{p^{2}+10p+50},\) \(5 ≤ p ≤ 20,\) where \(D = D(p)\) is the quantity demanded at the price \(p\) dollars.
Intensity of Light The intensity of illumination \(I\) on a surface is inversely proportional to the square of the distance \(r\) from the surface to the source of light. If the intensity is 1000 units when the distance is 1 meter from the light, find the rate of change of the intensity with respect to the distance when the source is 10 meters from the surface.
Ideal Gas Law The Ideal Gas Law, used in chemistry and thermodynamics, relates the pressure \(p\), the volume \(V\), and the absolute temperature \(T\) (in Kelvin) of a gas, using the equation \(pV=nRT\), where \(n\) is the amount of gas (in moles) and \(R=8.31\) is the ideal gas constant. In an experiment, a spherical gas container of radius \(r\) meters is placed in a pressure chamber and is slowly compressed while keeping its temperature at 273 K.
Body Density The density \(\rho\) of an object is its mass \(m\) divided by its volume \(V\); that is, \(\rho =\dfrac{m}{V}\). If a person dives below the surface of the ocean, the water pressure on the diver will steadily increase, compressing the diver and therefore increasing body density. Suppose the diver is modeled as a sphere of radius \(r\).
Jerk and Snap Problems 93-96 use the following discussion:
Suppose that an object is moving in rectilinear motion so that its distance \( s\) from the origin at time \(t\) is given by the function \(s=s( t) \). The velocity \(v=v( t)\) of the object at time \(t\) is the rate of change of the distance \(s\) with respect to time, namely, \(v=v( t) =\dfrac{ds}{dt}.\) The acceleration \(a=a( t)\) of the object at time \(t\) is the rate of change of the velocity with respect to time, namely, \[ a=a( t) =\dfrac{dv}{dt}= \dfrac{d}{dt}\!\left( \dfrac{ds}{dt}\right) =\dfrac{d^{2}s}{dt^{2}}. \]
There are also physical interpretations to the third derivative and the fourth derivative of \( s=s( t) .\) The jerk \(J=J( t)\) of the object at time \(t\) is the rate of change in the acceleration \(a\) with respect to time; that is, \[ J=J( t) = \dfrac{da}{dt}= \dfrac{d}{ dt}\!\left( \dfrac{dv}{dt}\right) =\dfrac{d^{2}v}{dt^{2}}=\dfrac{d^{3}s}{dt^{3}} \]
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The snap \(S= S(t)\) of the object at time \(t\) is the rate of change in the jerk \(J\) with respect to time; that is, \[ S=S(t) =\dfrac{dJ}{dt}= \dfrac{d^{2}a}{dt^{2}}=\dfrac{d^{3}v}{dt^{3}}=\dfrac{d^{ 4 }s}{dt^{ 4 }}. \]
Engineers take jerk into consideration when designing elevators, aircraft, and cars. In these cases, they try to minimize jerk, making for a smooth ride. But when designing thrill rides, such as roller coasters, the jerk is increased, making for an exciting experience.
Rectilinear Motion As an object in rectilinear motion moves, its distance \(s\) from the origin at time \(t\) is given by \(s = s(t) =t^{3}-t+1\), where \(s\) is in meters and \(t\) is in seconds.
Rectilinear Motion As an object in rectilinear motion moves, its distance \(s\) from the origin at time \(t\) is given by \(s=s(t) =\dfrac{1}{6}t^{4}-t^{2}+\dfrac{1}{2}t\)+4, where \(s\) is in meters and \(t\) is in seconds.
Elevator Ride Quality The ride quality of an elevator depends on several factors, two of which are acceleration and jerk. In a study of 367 persons riding in a 1600-kg elevator that moves at an average speed of 4 m/s, the majority of riders were comfortable in an elevator with vertical motion given by \[ s(t) =4t+0.8t^{2}+0.333t^{3} \]
Source: Elevator Ride Quality, January 2007, http://www.lift-report.de/index.php/news/176/368/Elevator-Ride-Quality.
Elevator Ride Quality In a hospital, the effects of high acceleration or jerk may be harmful to patients, so the acceleration and jerk need to be lower than in standard elevators. It has been determined that a 1600-kg elevator that is installed in a hospital and that moves at an average speed of 4 m/s, should have vertical motion \[ s(t) =4t+0.55t^{2}+0.1167t^{3} \]
Source: Elevator Ride Quality, January 2007, http://www.lift-report.de/index.php/news/176/368/Elevator-Ride-Quality.
Current Density in a Wire The current density \(J\) in a wire is a measure of how much an electrical current is compressed as it flows through a wire and is modeled by the function \(J(A) =\dfrac{I}{A}\), where \(I\) is the current (in amperes) and \(A\) is the cross-sectional area of the wire. In practice, current density, rather than merely current, is often important. For example, superconductors lose their superconductivity if the current density is too high.
Derivative of a Reciprocal, Function Prove that if a function \(g\) is differentiable, then \(\dfrac{d}{dx}\!\left[\dfrac{1}{g(x)}\right]\) = − \(\dfrac{g^\prime (x)}{[g(x)]^{2}}\), provided \(g(x)\neq 0\).
Extended Product Rule Show that if \(f,g\), and \(h\) are differentiable functions, then \[ \begin{eqnarray*} \frac{d}{dx}[f(x)g(x)h(x)]&=&f(x)g(x){h}^{\prime }(x)+f(x){g}^{\prime }(x)h(x)\\ &&+{f}^{\prime }(x)g(x)h(x) \end{eqnarray*} \]
From this, deduce that \[ \frac{d}{dx}[f(x)]^{3}=3[f(x)]^{2}f^\prime (x) \]
In Problems 100–105, use the Extended Product Rule (Problem 99) to find \(y^\prime\).
\(y=(x^{2}+1)(x-1)(x+5)\)
\(y=(x-1)(x^{2}+5)(x^{3}-1)\)
\(y=(x^{4}+1)^{3}\)
\(y=(x^{3}+1)^{3}\)
\(y=(3x+1){\left(1+\dfrac{1}{x}\right) (x^{-5}+1)}\)
\(y={\left(1-\dfrac{1}{x}\right)\!\! \left(1-\dfrac{1}{x^{2}}\right)\!\! \left(1-\dfrac{1}{x^{3}}\right) }\)
(Further) Extended Product Rule Write a formula for the derivative of the product of four differentiable functions. That is, find a formula for \(\dfrac{d}{dx}[ f_{1}(x) f_{2}(x) f_{3}(x) f_{4}(x)]\). Also find a formula for \(\dfrac{d}{dx}[f(x)]^{4}.\)
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If \(f\) and \(g\) are differentiable functions, show that if \(F(x)\)=\(\dfrac{1}{f(x) g(x)}\), then \[ F’ (x)=-F(x)\left[ {\frac{f^\prime (x)}{f(x)}}+{\frac{g^\prime (x)}{g(x)}}\right] \] provided \(f(x) \neq 0,\) \(g(x) \neq 0.\)
Higher-Order Derivatives If \(f(x)=\dfrac{1}{1-x}\), find a formula for the \(n\)th derivative of \(f\). That is, find \(f^{(n)}(x)\).
Let \(f(x)=\dfrac{x^{6}-x^{4}+x^{2}}{x^{4}+1}\). Rewrite \(f\) in the form \((x^{4}+1) f(x) = x^{6}-x^{4}+x^{2}\). Now find \(f^\prime (x)\) without using the quotient rule.
If \(f\) and \(g\) are differentiable functions with \(f\neq -g\), find the derivative of \(\dfrac{fg}{f+g}\).
\(f(x) =\dfrac{2x}{x+1}\).
Challenge Problems
Suppose \(f\) and \(g\) have derivatives up to the fourth order. Find the first four derivatives of the product \(fg\) and simplify the answers. In particular, show that the fourth derivative is \[ \dfrac{d^4}{dx^4} (fg) = f^{(4)}g+4f^{(3)}g^{(1)}+6f^{(2)}g^{(2)}+4f^{(1)}g^{(3)}+fg^{(4)} \]
Identify a pattern for the higher-order derivatives of \(fg\).
Suppose \(f_{1}(x),\ldots ,f_{n}(x)\) are differentiable functions.
Let \(a,b,c\), and \(d\) be real numbers. Define \[ \begin{equation*} \left\vert \begin{array}{l@{\quad}l} {a} & {b} \\ {c} & {d} \end{array} \right\vert =ad-bc \end{equation*} \]
This is called a \(2\times 2\) determinant and it arises in the study of linear equations. Let \(f_{1}(x),f_{2}(x),f_{3}(x)\), and \(f_{4}(x)\) be differentiable and let \[ D(x)=\left\vert \begin{array}{l@{\quad}l} {f_{1}(x)} & {f_{2}(x)} \\[3pt] {f_{3}(x)} & {f_{4}(x)} \end{array} \right\vert \]
Show that \[ D^{\prime }(x)=\left\vert \begin{array}{l@{\quad}l} {f_{1}' (x)} & {f_{2}' (x)} \\[3pt] {f_{3}(x)} & {f_{4}(x)} \end{array} \right\vert +\left\vert \begin{array}{l@{\quad}l} {f_{1}(x)} & {f_{2}(x)} \\[3pt] {f_{3}' (x)} & {f_{4}' (x)} \end{array} \right\vert \]
Let \(f_{0}(x) =x-1\)
\[ f_{1}( x) =1+\dfrac{1}{x-1}\]
\[f_{2}( x) =1+\dfrac{1}{1+\dfrac{1}{x-1}}\]
\[f_{3}( x) =1+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{x-1}}} \]