7.2 The Michaelis–Menten Model Describes the Kinetics of Many Enzymes

✓ 4 Explain how reaction velocity is determined and how reaction velocities are used to characterize enzyme activity.

Figure 7.1: Reaction velocity versus substrate concentration in an enzyme-catalyzed reaction. An enzyme-catalyzed reaction approaches a maximal velocity.

The initial velocity of catalysis, which is defined as the number of moles of product formed per second shortly after the reaction has begun, varies with the substrate concentration [S] when enzyme concentration is constant, in the manner shown in Figure 7.1. Examining how velocity changes in response to changes in substrate concentration is a reasonable way to study enzyme activity because variation in substrate concentration depends on environmental circumstances (for instance, after a meal), but enzyme concentration is relatively constant, especially on the time scale of reaction rates.

Before we can fully interpret this graph, we need to examine some of the parameters of the reaction. Consider an enzyme E that catalyzes the conversion of S into P by the following reaction:

Figure 7.2: Determining initial velocity. The amount of product formed at different substrate concentrations is plotted as a function of time. The initial velocity (V0) for each substrate concentration is determined from the slope of the curve at the beginning of a reaction, when the reverse reaction is insignificant. The initial velocity is illustrated for substrate concentration [S]4.

where k1 is the rate constant for the formation of the enzyme–substrate (ES) complex, k2 is the rate constant for the formation of product P, and k−1 and k−2 are the constants for the respective reverse reactions. Figure 7.2 shows that the amount of product formed is determined as a function of time for a series of substrate concentrations. As expected, in each case, the amount of product formed increases with time, although eventually a time is reached when there is no net change in the concentration of S or P. The enzyme is still actively converting substrate into product and vice versa, but the reaction equilibrium has been attained.

We can simplify the entire discussion of enzyme kinetics if we ignore the reverse reaction of product forming substrate. We can define the rate of catalysis V0, or the initial rate of catalysis, as the number of moles of product formed per second when the reaction is just beginning—that is, when t ≈ 0 and thus [P] ≈ 0. Thus, for the graph in Figure 7.2, V0 is determined for each substrate concentration by measuring the rate of product formation at early times before P accumulates. With the use of this approximation, reaction 5 can be simplified to the following reaction scheme:

Enzyme E combines with substrate S to form an ES complex, with a rate constant k1. The ES complex has two possible fates. It can dissociate to E and S, with a rate constant k−1, or it can proceed to form product P, with a rate constant k2.

In 1913, on the basis of this reaction scheme and with some simple assumptions, Leonor Michaelis and Maud Menten proposed a simple model to account for these kinetic characteristics. The critical feature in their treatment is that a specific ES complex is a necessary intermediate in catalysis. The notion that an enzyme needed to bind substrate before catalysis could take place was not evident to the early biochemists. Some believed that enzymes might release emanations that converted substrate into product.

The Michaelis–Menten equation describes the variation of enzyme activity as a function of substrate concentration. The derivation of the equation from the terms just described can be found in the Appendix at the end of this chapter. This equation is

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where

KM, a compilation of rate constants called the Michaelis constant, is unique to each enzyme and is independent of enzyme concentration. KM describes the properties of the enzyme–substrate interaction and thus will vary for enzymes that can use different substrates. The maximal velocity possible, Vmax, can be attained only when all of the enzyme (total enzyme, or ET) is bound to substrate (S):

Figure 7.3: Michaelis–Menten kinetics. A plot of the reaction velocity V0 as a function of the substrate concentration [S] for an enzyme that obeys Michaelis–Menten kinetics shows that the maximal velocity Vmax is approached asymptotically. The Michaelis constant KM is the substrate concentration yielding a velocity of Vmax/2.

Vmax is directly dependent on enzyme concentration. Equation 7 describes the typical Michaelis–Menten curve as illustrated in Figure 7.3. At very low substrate concentrations, when [S] is much less than the value of KM, the velocity is directly proportional to the substrate concentration; that is, V0 = (Vmax/KM)[S]. At high substrate concentrations, when [S] is much greater than KM, V0Vmax; that is, the velocity is maximal, independent of substrate concentration. When an enzyme is operating at Vmax, all of the available enzyme is bound to substrate; the addition of more substrate will not affect the velocity of the reaction. The enzyme is displaying zero-order kinetics. Under these conditions, the enzyme is said to be saturated.

!quickquiz! QUICK QUIZ 1

What value of [S], as a fraction of KM, is required to obtain 80% Vmax?

Consider the circumstances when V0 = Vmax/2. Under these conditions, the practical meaning of KM is evident from equation 7. Using V0 = Vmax/2, and solving for [S], we see that [S] = KM at V0 = Vmax/2. Thus, KM is equal to the substrate concentration at which the reaction velocity is half its maximal value. KM is an important characteristic of an enzyme-catalyzed reaction and is significant for its biological function. Determination of Vmax and KM for an enzyme-catalyzed reaction is often one of the first characterizations of an enzyme undertaken.

Variations in KM Can have Physiological Consequences

The physiological consequence of KM is illustrated by the sensitivity of some persons to ethanol (Figure 7.4). Such persons exhibit facial flushing and rapid heart rate (tachycardia) after ingesting even small amounts of alcohol. In the liver, alcohol dehydrogenase converts ethanol into acetaldehyde:

Figure 7.4: Ethanol in alcoholic beverages is converted into acetaldehyde.

Normally, the acetaldehyde, which is the cause of the symptoms when present at high concentrations, is processed to acetate by aldehyde dehydrogenase:

Most people have two forms of the aldehyde dehydrogenase, a low KM mitochondrial form and a high KM cytoplasmic form. In susceptible persons, the mitochondrial enzyme is less active owing to the substitution of a single amino acid, and so acetaldehyde is processed only by the cytoplasmic enzyme. Because the cytoplasmic enzyme has a high KM, it achieves a high rate of catalysis only at very high concentrations of acetaldehyde. Consequently, less acetaldehyde is converted into acetate; excess acetaldehyde escapes into the blood and accounts for the physiological effects.

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KM and Vmax Values Can Be Determined by Several Means

Figure 7.5: A double-reciprocal, or Lineweaver–Burk, plot. A double-reciprocal plot of enzyme kinetics is generated by plotting 1/V0 as a function 1/[S]. The slope is KM/Vmax, the intercept on the vertical axis is 1/Vmax, and the intercept on the horizontal axis is −1/KM.

KM is equal to the substrate concentration that yields Vmax/2; however, Vmax, like perfection, is approached but never attained. How, then, can we experimentally determine KM and Vmax, and how do these parameters enhance our understanding of enzyme-catalyzed reactions? The Michaelis constant KM and the maximal velocity Vmax can be readily derived from rates of catalysis measured at a variety of substrate concentrations if an enzyme operates according to the simple scheme given in equation 7. The derivation of KM and Vmax is most commonly achieved with the use of curve-fitting programs on a computer. However, an older method is a source of further insight into the meaning of KM and Vmax.

Before the availability of computers, the determination of KM and Vmax values required algebraic manipulation of the basic Michaelis–Menten equation. The Michaelis–Menten equation can be transformed into one that gives a straightline plot. Taking the reciprocal of both sides of equation 7 gives the Lineweaver–Burk equation:

A plot of 1/V0 versus 1/[S], called a double-reciprocal plot, yields a straight line with a y-intercept of 1/Vmax and a slope of KM/Vmax (Figure 7.5). The intercept on the x axis is −1/KM. This method is now rarely used because the data points at high and low concentrations are weighted differently and thus sensitive to errors.

KM and Vmax Values Are Important Enzyme Characteristics

The KM values of enzymes range widely (Table 7.1). For most enzymes, KM lies between 10−1 and 10−7 M. The KM value for an enzyme depends on the particular substrate and on environmental conditions such as pH, temperature, and ionic strength. The Michaelis constant KM, as already noted, is equal to the concentration of substrate at which half the active sites are filled. Thus, KM provides a measure of the substrate concentration required for significant catalysis to take place. For many enzymes, experimental evidence suggests that the KM value provides an approximation of substrate concentration in vivo, which in turn suggests that most enzymes evolved to have significant activity at the substrate concentration commonly available. We can speculate about why an enzyme might evolve to have a KM value that corresponds to the substrate concentration normally available to the enzyme. If the normal concentration of substrate is approximately equal to KM, the enzyme will display significant activity and yet the activity will be sensitive to changes in environmental conditions—that is, changes in substrate concentration. At values below KM, enzymes are very sensitive to changes in substrate concentration but display little activity. At substrate values well above KM, enzymes have great catalytic activity but are insensitive to changes in substrate concentration. Thus, with the normal substrate concentration being approximately KM, the enzymes have significant activity (1/2 Vmax) but are still sensitive to changes in substrate concentration.

Table 7.1 KM values of some enzymes

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The maximal velocity Vmax reveals the turnover number of an enzyme, which is the number of substrate molecules that an enzyme can convert into product per unit time when the enzyme is fully saturated with substrate. The turnover number is equal to the rate constant k2, which is also called kcat. If the total concentration of active sites, [E]T, is known, then

and thus

For example, a 10−6 M solution of carbonic anhydrase catalyzes the formation of 0.6 M H2CO3 per second when the enzyme is fully saturated with substrate. Hence, k2 is 6 × 105 s−1. This value is one of the largest known turnover numbers. Each catalyzed reaction takes place in a time equal to, on average, 1/k2, which is 1.7 μs for carbonic anhydrase. The turnover numbers of most enzymes with their physiological substrates fall in the range from 1 to 104 per second (Table 7.2).

Table 7.2 Turnover numbers of some enzymes

kcat/KM Is a Measure of Catalytic Efficiency

When the substrate concentration is much greater than KM, the velocity of catalysis approaches Vmax. However, in the cell, most enzymes are not normally saturated with substrate. Under physiological conditions, the amount of substrate present is often between 10% and 50% KM. Thus, the [S]/KM ratio is typically between 0.01 and 1.0. When [S] ≪ KM, the enzymatic rate is much less than kcat (k2) because most of the active sites are unoccupied. We can derive an equation that characterizes the kinetics of an enzyme under these cellular conditions:

When [S] ≪ KM, almost all active sites are empty. In other words, the concentration of free enzyme, [E], is nearly equal to the total concentration of enzyme, [E]T; so

Thus, when [S] ≪ KM, the enzymatic velocity depends on the values of kcat/KM, [S], and [E]T. Under these conditions, kcat/KM is the rate constant for the interaction of S and E. The rate constant kcat/KM, called the specificity constant, is a measure of catalytic efficiency because it takes into account both the rate of catalysis with a particular substrate (kcat) and the nature of the enzyme–substrate interaction (KM). For instance, by using kcat/KM values, we can compare an enzyme’s preference for different substrates. Table 7.3 shows the kcat/KM values for several different substrates of chymotrypsin, a digestive enzyme secreted by the pancreas. Chymotrypsin clearly has a preference for cleaving next to bulky, hydrophobic side chains.

Table 7.3 Substrate preferences of chymotrypsin
Source: Data from A. Fersht, Structure and Mechanism in Protein Science: A Guide to Enzyme Catalysis and Protein Folding (W.H. Freeman and Company, 1999), Table 6.3.

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How efficient can an enzyme be? We can approach this question by determining whether there are any physical limits on the value of kcat/KM. Note that the kcat/KM ratio depends on k1, k−1, and kcat, as can be shown by substituting for KM:

Suppose that the rate of formation of product (kcat) is much faster than the rate of dissociation of the ES complex (k–1). The value of kcat/KM then approaches k1. Thus, the ultimate limit on the value of kcat/KM is set by k1, the rate of formation of the ES complex. This rate cannot be faster than the diffusion-controlled encounter of an enzyme and its substrate. Diffusion limits the value of k1, and so it cannot be higher than 108 to 109 s−1 M−1. Hence, the upper limit on kcat/KM is between 108 and 109 s−1 M−1.

The kcat/KM ratios of the enzymes superoxide dismutase, acetylcholinesterase, and triose phosphate isomerase are between 108 and 109 s−1 M−1. Enzymes that have kcat/KM ratios at the upper limits have attained kinetic perfection. Their catalytic velocity is restricted only by the rate at which they encounter substrate in the solution (Table 7.4).

Table 7.4 Enzymes for which kcat/KM is close to the diffusion-controlled rate of encounter
Source: Data from A. Fersht, Structure and Mechanism in Protein Science: A Guide to Enzyme Catalysis and Protein Folding (W. H. Freeman and Company, 1999), Table 4.5.

Most Biochemical Reactions Include Multiple Substrates

The simplest way to explain Michaelis–Menten kinetics is to use a one-substrate reaction as an example. However, most reactions in biological systems start with two substrates and yield two products. They can be represented by the following bisubstrate reaction:

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Many such reactions transfer a functional group, such as a phosphoryl or an ammonium group, from one substrate to the other. Those that are oxidation–reduction reactions transfer electrons between substrates. Although equations can be developed to describe the kinetics of multiple-substrate reactions, we will forego a kinetic description of such reactions and simply examine some general principles of bisubstrate reactions.

Multiple-substrate reactions can be divided into two classes: sequential reactions and double-displacement reactions (Figure 7.6). The depictions shown in Figure 7.6 are called Cleland representations.

Figure 7.6: Cleland representations of bisubstrate reactions. (A) Sequential reaction. The first substrate (NADh) binds to the enzyme, followed by the second substrate (pyruvate) to form a ternary complex of two substrates and the enzyme. Catalysis then takes place, forming a ternary complex of two products and the enzyme. The products subsequently leave sequentially. (B) Double displacement. The first substrate (aspartate) binds, and the first catalytic step takes place, resulting in a substituted enzyme (E-NH3). The first product (oxaloacetate) then leaves. The second substrate (α-ketoglutarate) binds to the substituted enzyme. The second catalytic step takes place, and the Nh3 is transferred to the substrate to form the final product glutamate, which departs the enzyme.

Sequential reactionsIn sequential reactions (Figure 7.6A), all substrates must bind to the enzyme before any product is released. Consequently, in a bisubstrate reaction, a ternary complex consisting of the enzyme and both substrates forms. Sequential mechanisms are of two types: ordered, in which the substrates bind the enzyme in a defined sequence, and random.

Double-displacement (ping-pong) reactionsIn double-displacement, or ping-pong, reactions (Figure 7.6B), one or more products are released before all substrates bind the enzyme. The defining feature of double-displacement reactions is the existence of a substituted enzyme intermediate, in which the enzyme is temporarily modified. Reactions that shuttle amino groups between amino acids and α-ketoacids are classic examples of double-displacement mechanisms. As shown in Figure 7.6, the substrates and products appear to bounce on and off the enzyme just as a Ping-Pong ball bounces on and off a table.